By the work energy theorem we have that the total energy of a nonrelativistic point charge, $q_0$ of mass $m$, moving in an electric field $\mathbf{E}$ is
$ E = E_k + U_e = \frac{1}{2}mv^2 + q_0V \quad Eq.1 $
As I read in my text:
The electrical charge acquires potential energy. If the charge is released, work is done by the field and the charge accelerates. It means that its potential energy is converted into kinetic energy.
But if an accelerating charge emits electromagnetic radiation some electric potential energy, should be dissipated and could not be converted into kinetic energy. How can eq. 1 hold? The text mentions the dissipation of energy by accelerating charges only later in the course, and says nothing when treating energy conservation of moving charges in the electrostatic field.