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-3 votes
2 answers
81 views

Meaning of $d\mathcal{L}=-H$ in analytical mechanics?

In Lagrangian mechanics the momentum is defined as: $$p=\frac{\partial \mathcal{L}}{\partial \dot q}$$ Also we can define it as: $$p=\frac{\partial S}{\partial q}$$ where $S$ is Hamilton's principal ...
User198's user avatar
  • 443
0 votes
2 answers
82 views

Generalized momentum

I am studying Hamiltonian Mechanics and I was questioning about some laws of conservation: in an isolate system, the Lagrangian $\mathcal{L}=\mathcal{L}(q,\dot q)$ is a function of the generalized ...
user1255055's user avatar
0 votes
1 answer
69 views

Changing variables from $\dot{q}$ to $p$ in Lagrangian instead of Legendre Transformation

This question is motivated by a perceived incompleteness in the responses to this question, which asks why we can't just substitute $\dot{q}(p)$ into $L(q,\dot{q})$ to convert it to $L(q,p)$, which ...
user1247's user avatar
  • 7,398
1 vote
1 answer
66 views

Landau/Lifshitz action as a function of coordinates [duplicate]

In Landau/Lifshitz' "Mechanics", $\S43$, 3ed, the authors consider the action of a mechanical system as a function of its final time $t$ and its final position $q$. They consider paths ...
CW279's user avatar
  • 349
1 vote
1 answer
49 views

Definition of generalized momenta in analytical mechanics

I've seen mainly two definitions of generalized momenta, $p_k$, and I wasn't sure which one is always true/ the correct one: $$p_k\equiv\dfrac{\partial\mathcal T}{\partial \dot q_k}\text{ and }p_k\...
Conreu's user avatar
  • 296
1 vote
1 answer
54 views

Sufficient condition for conservation of conjugate momentum

Is the following statement true? If $\frac{\partial \dot{q}}{\partial q}=0$, then the conjugate momentum $p_q$ is conserved. We know that conjugate momentum of $q$ is conserved if $\frac{\partial L}{\...
Rainbow's user avatar
  • 41
0 votes
1 answer
80 views

Lagrangian and Hamiltonian Mechanics: Conjugate Momentum

I am a physics undergraduate student currently taking a classical mechanics course, and I am not able to understand what conjugate/canonical momentum is (physically). It is sometimes equal to the ...
SyntaxError_10's user avatar
1 vote
1 answer
51 views

Lagrange momentum for position change

After the tremendous help from @hft on my previous question, after thinking, new question popped up. I want to compare how things behave when we do: $\frac{\partial S}{\partial t_2}$ and $\frac{\...
Giorgi's user avatar
  • 525
1 vote
2 answers
103 views

Momentum $p = \nabla S$

My book mentions the following equation: $$p = \nabla S\tag{1.2}$$ where $S$ is the action integral, nabla operator is gradient, $p$ is momentum. After discussing it with @hft, on here, it turns out ...
Giorgi's user avatar
  • 525
2 votes
0 answers
57 views

What are the extra terms in the generalized momentum regarding the Lagrangian formalism?

In the lectures, we have defined the generalized momentum in the Lagrangian to be: $$p_i=\frac{\partial L}{\partial\dot q_i}.$$ But with this definition, if we do not make any assumptions about the ...
gluon's user avatar
  • 193
1 vote
1 answer
135 views

In a simple case of a particle in a uniform gravitational field, do we have translation invariance or not?

Consider a system where a particle is placed in a uniform gravitational field $\vec{F} = -mg\,\vec{e}_{z}$. The dynamics of this are clearly invariant under translations. When we take $z\rightarrow z+...
Maximal Ideal's user avatar
4 votes
3 answers
236 views

How to show the velocity of free motion is constant in Galileo's relativity principle?

Picture below is from Landau & Lifshitz's Mechanics. How to get the red line from green line?
Enhao Lan's user avatar
  • 351
0 votes
1 answer
299 views

Generalized vs conjugate momenta

For a given Lagrangian $L$, the $i$th generalized momentum is defined as $$p_i = \frac{\partial L}{\partial \dot{q_i}}$$ where $\dot{q_i}$ is the time derivative of the $i$th generalized coordinate (i....
CBBAM's user avatar
  • 3,350
3 votes
2 answers
452 views

Help with geometric view of conjugate momenta and Legendre transformation

I'm familiar with the ''coordinate view'' of Lagrangian and Hamiltonian mechanics where if $\pmb{q}=(q^1,\dots, q^n)\in\mathbb{R}^n$ are any $n$ generalized coordinates and $L(\pmb{q},\dot{\pmb{q}})$ ...
J Peterson's user avatar
2 votes
1 answer
99 views

What do you think about this particularization of the Euler-Lagrange equation that resembles Newton's 2nd Law?

For: $$\mathcal{L}=\mathcal{L}(q_j,\dot{q_j},t)=T-V$$ the Euler-Lagrange equation is simply: $$\frac{d}{dt}\left(\frac{\partial \mathcal{L}}{\mathcal{\dot{q_j}}} \right)-\frac{\partial \mathcal{L}}{\...
agaminon's user avatar
  • 1,775
0 votes
1 answer
87 views

Help with understanding virtual displacement in Lagrangian

I know that these screen shots are not nice but I have a simple question buried in a lot of information My question Why can't we just repeat what they did with equation (7.132) to equation (7.140) ...
Reuben's user avatar
  • 283
0 votes
2 answers
530 views

Why is derivative of Lagrangian with respect to generalized position and velocity equal to this?

I'm currently studying Lagrangian mechanics, and in the process, I've met the following equations in a couple of proofs. $$ \frac{\partial \mathcal{L}}{\partial q_i} = \dot p_i $$ $$ \frac{\partial \...
user avatar
0 votes
0 answers
95 views

Conjugate momentum vs translation generator with non-standard kinetic term

I am reading this paper and for equation (2.5) (associated with the Lagrangian in eq 2.1) there is the claim that for a Lagrangian $L(\varphi,A,\dot{\varphi},\dot{A})$ containing an extra non-standard ...
de-baby-Sitter's user avatar
3 votes
5 answers
370 views

Axiomatising classical mechanics to arrive at the principle of stationary action - what are the fundamental definitions of momentum, etc.?

$\newcommand{\d}{\mathrm{d}}\newcommand{\l}{\mathcal{L}}$Throughout all my study of physics, it has never been clear what is a definition, what is an axiom, what is a law and what is a proof in ...
FShrike's user avatar
  • 221
3 votes
0 answers
121 views

Intuitive explanation on why velocity = 0 for a inverted pendulum on a wheel system

I believe I have solved below problem. I am not looking for help on problem-solving per se. I am just looking for an intuitive explanation. Problem statement: wheel mass = $m_1$, even mass rod BC mass ...
Josh Bolton's user avatar
1 vote
1 answer
108 views

Geometric meaning of conjugate momentum

Let's say I have a free particle moving in an $n$-dimensional Manifold $M$. There is a tangent space $TM$ associated with all possible infinitesimal motions of a particle at each point in this ...
Bondo's user avatar
  • 137
2 votes
2 answers
156 views

How to derive the fact that $p\sim d/dx$ and $H\sim d/dt$ from classical mechanics?

I am trying to understand Noether's conserved quantities to shifts in time and or position. I have seen the derivation of the operators for Schrodinger's equation but not for classical mechanics. Is ...
nemui's user avatar
  • 381
0 votes
0 answers
124 views

Lagrangian and Friction

How does lagrangian mechanics explain loss of momentum conservation in presence of friction? My try is this: The lagrange equation would then include a generalized force term $Q_i$: $$\frac{d}{dt}\...
Lifelong Learner's user avatar
2 votes
2 answers
161 views

Conjugate momentum notation

I was reading Peter Mann's Lagrangian & Hamiltonian Dynamics, and I found this equation (page 115): $$p_i := \frac{\partial L}{\partial \dot{q}^i}$$ where L is the Lagrangian. I understand this is ...
math-ingenue 's user avatar
0 votes
1 answer
320 views

Gauge ivariance and canonical versus kinetic momenta for a charged particle in an EM field

I all, I am struggling to grasp the notion of gauge invariant when talking about an object like the canonical momenta $\frac{\partial L}{\partial \dot{q}_i}$ or kinetic momenta $m\dot{q}_i$. I am very ...
Lopey Tall's user avatar
  • 1,031
3 votes
1 answer
151 views

Reducing the degrees of freedom of a Lagrangian in a spherical potential by using integrals of motion [duplicate]

I'm sure I've made a silly mistake here, so I would be very grateful if someone could help me clear it up! Here is my reasoning: The Lagrangian in a spherical potential is $$ \mathcal{L}=\frac{m\...
xzd209's user avatar
  • 2,157
1 vote
2 answers
202 views

Does the conservation of $\frac{\partial L}{\partial\dot{q}_i}$ necessarily require $q_i$ to be cyclic?

If a generalized coordinate $q_i$ is cyclic, the conjugate momentum $p_i=\frac{\partial L}{\partial\dot{q}_i}$ is conserved. Is the converse also true? To state more explicitly, if a conjugate ...
Solidification's user avatar
0 votes
1 answer
328 views

Difference between kinematic momentum and conjugated momentum in purely mechanical setup

I don't know much about physics, but I wanted to understand what was the difference between the "kinematic momentum" and the conjugated momentum. As I understand it, kinematic momentum is mass times ...
roi_saumon's user avatar
1 vote
2 answers
352 views

Ambiguity in d'Alembert's principle

It seems to me that many different momenta $\dot{\bf p}_j $ can satisfy d'Alembert's principle: $$\tag{1} \sum_{j=1}^N ( {\bf F}_j^{(a)} - \dot{\bf p}_j ) \cdot \delta {\bf r}_j~=~0 $$ in a ...
VanD1206's user avatar
  • 121
2 votes
2 answers
2k views

Defining generalized momentum in terms of kinetic energy versus a Lagrangian

Reputable authors (e.g., Bergmann, Wells, Susskind) define generalized momentum using the Lagrangian $L$ as $$p_{i}\equiv\frac{\partial L}{\partial\dot{q}^{i}}.\tag{1}$$ Joos and Freeman define ...
Steven Thomas Hatton's user avatar

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