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-3 votes
2 answers
81 views

Meaning of $d\mathcal{L}=-H$ in analytical mechanics?

In Lagrangian mechanics the momentum is defined as: $$p=\frac{\partial \mathcal{L}}{\partial \dot q}$$ Also we can define it as: $$p=\frac{\partial S}{\partial q}$$ where $S$ is Hamilton's principal ...
0 votes
2 answers
82 views

Generalized momentum

I am studying Hamiltonian Mechanics and I was questioning about some laws of conservation: in an isolate system, the Lagrangian $\mathcal{L}=\mathcal{L}(q,\dot q)$ is a function of the generalized ...
0 votes
1 answer
69 views

Changing variables from $\dot{q}$ to $p$ in Lagrangian instead of Legendre Transformation

This question is motivated by a perceived incompleteness in the responses to this question, which asks why we can't just substitute $\dot{q}(p)$ into $L(q,\dot{q})$ to convert it to $L(q,p)$, which ...
8 votes
5 answers
716 views

Why can't we obtain a Hamiltonian from the Lagrangian by only substituting?

This question may sound a bit dumb. Why can't we obtain the Hamiltonian of a system simply by finding $\dot{q}$ in terms of $p$ and then evaluating the Lagrangian with $\dot{q} = \dot{q}(p)$? Wouldn't ...
1 vote
1 answer
66 views

Landau/Lifshitz action as a function of coordinates [duplicate]

In Landau/Lifshitz' "Mechanics", $\S43$, 3ed, the authors consider the action of a mechanical system as a function of its final time $t$ and its final position $q$. They consider paths ...
1 vote
1 answer
49 views

Definition of generalized momenta in analytical mechanics

I've seen mainly two definitions of generalized momenta, $p_k$, and I wasn't sure which one is always true/ the correct one: $$p_k\equiv\dfrac{\partial\mathcal T}{\partial \dot q_k}\text{ and }p_k\...
1 vote
1 answer
54 views

Sufficient condition for conservation of conjugate momentum

Is the following statement true? If $\frac{\partial \dot{q}}{\partial q}=0$, then the conjugate momentum $p_q$ is conserved. We know that conjugate momentum of $q$ is conserved if $\frac{\partial L}{\...
0 votes
1 answer
80 views

Lagrangian and Hamiltonian Mechanics: Conjugate Momentum

I am a physics undergraduate student currently taking a classical mechanics course, and I am not able to understand what conjugate/canonical momentum is (physically). It is sometimes equal to the ...
11 votes
2 answers
1k views

Simple explanation of why momentum is a covector?

Can you give a simple, intuitive explanation (imagine you're talking to a schoolkid) of why mathematically speaking momentum is covector? And why you should not associate mass (scalar) times velocity (...
1 vote
1 answer
51 views

Lagrange momentum for position change

After the tremendous help from @hft on my previous question, after thinking, new question popped up. I want to compare how things behave when we do: $\frac{\partial S}{\partial t_2}$ and $\frac{\...
1 vote
2 answers
103 views

Momentum $p = \nabla S$

My book mentions the following equation: $$p = \nabla S\tag{1.2}$$ where $S$ is the action integral, nabla operator is gradient, $p$ is momentum. After discussing it with @hft, on here, it turns out ...
2 votes
0 answers
57 views

What are the extra terms in the generalized momentum regarding the Lagrangian formalism?

In the lectures, we have defined the generalized momentum in the Lagrangian to be: $$p_i=\frac{\partial L}{\partial\dot q_i}.$$ But with this definition, if we do not make any assumptions about the ...
1 vote
1 answer
135 views

In a simple case of a particle in a uniform gravitational field, do we have translation invariance or not?

Consider a system where a particle is placed in a uniform gravitational field $\vec{F} = -mg\,\vec{e}_{z}$. The dynamics of this are clearly invariant under translations. When we take $z\rightarrow z+...
4 votes
3 answers
236 views

How to show the velocity of free motion is constant in Galileo's relativity principle?

Picture below is from Landau & Lifshitz's Mechanics. How to get the red line from green line?
0 votes
1 answer
299 views

Generalized vs conjugate momenta

For a given Lagrangian $L$, the $i$th generalized momentum is defined as $$p_i = \frac{\partial L}{\partial \dot{q_i}}$$ where $\dot{q_i}$ is the time derivative of the $i$th generalized coordinate (i....

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