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1 vote
0 answers
87 views

What is natural about the Berry connection?

So I asked a similar question here and even though I still believe it's a valid question, the formulation may have been a bit too complicated to pique people's interest, so let me try to break it up ...
1 vote
0 answers
62 views

Concise formulation of Berry phase as holonomy of "natural" connection

I've been trying to understand the Berry phase (abelian/non-abelian) as the holonomy of some "natural connection". I almost have all the pieces together, but there are a few parts that are a ...
0 votes
2 answers
738 views

Berry Curvature

Can I ask two questions about the Berry curvature? The formula for the berry curvature is written below. $$\Omega_n (k) = -Im \langle \bigtriangledown_k u_{nk} | \times | \bigtriangledown_k u_{nk} \...
1 vote
0 answers
65 views

How does the fiber bundle perspective on geometric phase lead to a certain connection one-form?

I'm trying to understand why the relevant connection one-form when calculating geometric phase in quantum systems is $$\mathcal{A}_\psi(X):=i \text{Im}\langle \psi | X\rangle.$$ Set-up: I'll set the ...
3 votes
2 answers
1k views

Derivation of the Berry Curvature and Bloch Magnetic Moment in Graphene

(I found a workable solution, skip to the "Solution" part to see it) I am attempting to derive equations 2 and 6 from Xiao et al. paper "Valley contrasting physics in graphene" (...
2 votes
0 answers
168 views

How can i calculate the Berry Curvature for the Dirac points in Haldane graphene?

I want to calculate the berry curvature at the Dirac points in graphene with complex next nearest hopping (haldane model) in order to show that it is non-zero at the dirac points and use it to compute ...
3 votes
3 answers
672 views

‘Proof’ that non-Abelian Berry phase vanishes identically

For a degenerate system with Hamiltonian $H =H(\mathbf{R})$ and eigenstates $\left|n(\mathbf{R})\right\rangle$ the non-Abelian Berry connection is $$A^{(mn)}_i=\mathrm{i}\left\langle m|\partial_in\...
3 votes
1 answer
4k views

Numerical Calculation of Berry Curvature

I am trying to calculate some berry curvature (BC) in a 2D lattice and I have some things I am getting lost with. In the 2D lattice, we set up the eigenvalue problem $H|u_1\rangle = \epsilon_i|u_i\...
1 vote
1 answer
234 views

Curl of Berry connection

If $|n\rangle=|n( \textbf{R}(t) ) \rangle $ satisfies the equation $$H(\textbf{R}(t))|n(\textbf{R}(t)) \rangle = E_{n}(\textbf{R}(t))|n(\textbf{R}(t))\rangle$$ then the berry phase $\gamma_{n}(t)$ ...
8 votes
2 answers
607 views

Numerical Berry curvature for bosons

I am trying to numerically compute the Berry Curvature for a generic quadratic Bosonic Hamiltonian of the form $$H = \sum_{ij} A_{ij} b_{i}^\dagger b_j + \frac{1}{2} \sum_{ij}\left( B_{ij} b_i b_j + \...
0 votes
0 answers
177 views

Berry curvature vanishes in TRS system

In spin 1/2 system with TR symmetry , the Berry curvature must vanish. Because Berry curvature is odd. How to prove it? \begin{equation} \langle\partial_{-k_x}u^{I}(-k)|\partial_{-k_y}u^{I}(-k)\rangle-...
1 vote
1 answer
93 views

What is the logic connection between these two statements?

What is the connection between these two statements: the berry curvature change sign under time-reversal operation If the system has the time-reversal symmetry, then berry curvature is odd in k. ...
1 vote
1 answer
467 views

Is it possible understand Berry curvature as Gaussian curvature in some limit?

I would like to understand the Berry curvature and the Chern number from mathematical geometry-topology. I understand that in electronic QHE, there is a map from $k^2$ to a vector space where the ...
2 votes
1 answer
514 views

Berry phase covariant derivative

I have been studying some simple examples of the covariant derivative for 2D surfaces and the way that it is constructed is by taking the usual derivative in the 3D Euclidean space at a point $p$ on ...
7 votes
1 answer
2k views

Detail of deriving Berry Curvature From Berry Connection

The Berry curvature of the $n^{\mathrm{th}}$ eigenstate of Hamiltonian $H$ for the vector of external parameters $\vec{R}$ can be derived in part by writing the following two lines: $$ B^n(\vec{R}) \...

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