Skip to main content

Questions tagged [triangles]

The tag has no usage guidance.

-1 votes
0 answers
37 views

Point on the line connecting the incenter and circumcenter [closed]

Let D, E, and F be the points where the orthogonal bisectors intersect the circumcircle, and H, I, and J be the tangent points of the incircle. Prove that lines DH, EI, and FJ are concurrent and this ...
Benjamin L. Warren's user avatar
1 vote
0 answers
38 views

Name of the perspector of the orthic triangle and excentral triangle

The orthic triangle and tangential triangles of a given triangle are in perspective. What's the official kimberling center associated with this perspector?
Benjamin L. Warren's user avatar
3 votes
1 answer
265 views

Name this kimberling center

The lines which connect the vertices of a triangle with the tangent points between the Spieker circle and the medial triangle are concurrent. Which kimberling center does this point correspond to?
Benjamin L. Warren's user avatar
1 vote
0 answers
87 views

A circle is inscribed in a triangle, with three other circles in the corner regions. The radii are integers. Possible values of the largest radius?

Originally posted at MSE. A circle with integer radius $R$ is inscribed in a triangle. Three other circles with integer radii $a,b,c$ are each tangent to the large circle and two sides of the ...
Dan's user avatar
  • 2,997
1 vote
1 answer
158 views

An "almost" geodesic dome

A regular $ n$-gon is inscribed in the unit circle centered in $0$. We want to build an "almost" geodesic dome upon it this way: on each side of the $n$-gon we build an equilateral triangle ...
user967210's user avatar
13 votes
8 answers
1k views

The vertices of a triangle are three random points on a unit circle. The side lengths are, in random order, $a,b,c$. Show that $P(ab>c)=\frac12$

The vertices of a triangle are three unifomly random points on a unit circle. The side lengths are, in random order, $a,b,c$. There is a convoluted proof that $P(ab>c)=\frac12$. But since the ...
Dan's user avatar
  • 2,997
30 votes
2 answers
2k views

Packing an upwards equilateral triangle efficiently by downwards equilateral triangles

Consider the problem of packing an upwards-pointing unit equilateral triangle "efficiently" by downwards-pointing equilateral triangles, where "efficiently" means that there is ...
Terry Tao's user avatar
  • 112k
2 votes
0 answers
79 views

Another variant of the Malfatti problem

We try to add to A Variant of the Malfatti Problem As stated in the Wikipedia entry on Malfatti circles, it is an open problem to decide, given a number $n$ and any triangle, whether a greedy method ...
Nandakumar R's user avatar
  • 5,827
4 votes
3 answers
969 views

Is there a pyramid with all four faces being right triangles? [closed]

If such a pyramid exists, could someone provide the coordinates of its vertices?
Humberto José Bortolossi's user avatar
1 vote
1 answer
72 views

Partitioning polygons into obtuse isosceles triangles

Ref: Partitioning polygons into acute isosceles triangles Partition of polygons into 'strongly acute' and 'strongly obtuse' triangles https://math.stackexchange.com/questions/1052063/...
Nandakumar R's user avatar
  • 5,827
1 vote
0 answers
62 views

Cutting off odd numbers of equal area triangles from a unit square

Two earlier related posts: Cutting the unit square into pieces with rational length sides On a possible variant of Monsky's theorem Question: for odd n, how does one cut the unit square into n ...
Nandakumar R's user avatar
  • 5,827
1 vote
0 answers
96 views

Tiling the plane with pair-wise non-congruent and mutually similar triangles

Question: Is it possible to tile the plane with triangles that are (1) mutually similar, (2) pairwise non-congruent and (3)non-right? No other constraints. Note 1: Reg requirement 3 above: since any ...
Nandakumar R's user avatar
  • 5,827
1 vote
0 answers
101 views

How many convex polygons can be made from $n$ identical right angle triangles?

Whilst working on a Tangram problem, I came across the need to find the total number of convex shapes that can be produced from $16$ identical (isosceles) right angle triangles (since the Tangram can ...
FD_bfa's user avatar
  • 147
3 votes
1 answer
193 views

Do the heights of an acute triangle intersect at a single point (in neutral geometry)?

A well-known result of the Euclidean planimetry says that the heights of any triangle have a common point called the orthocentre of the triangle. This result is not true in neutral geometry (i.e., ...
Taras Banakh's user avatar
  • 41.1k
2 votes
1 answer
147 views

Finding angle with geometric approach [closed]

I would like to solve the problem in this picture: with just an elementary geometric approach. I already solved with trigonometry, e.g. using the Bretschneider formula, finding that the angle $ x = ...
Ulissex 's user avatar

15 30 50 per page
1
2 3 4 5
8