Skip to main content

All Questions

2 votes
0 answers
132 views

Hodge numbers of a complement

Let $Y\subset X$ be an analytic subvariety of codimension $d$ of a smooth compact complex variety $X$. Denote $U = X\setminus Y$. The relative cohomology exact sequence implies that $$ H^i(X) \to H^i(...
cll's user avatar
  • 2,305
11 votes
1 answer
1k views

Hodge conjecture as the equality of arithmetic and algebraic weights of motivic L-functions

Recently I became aware of the following statement given on page 13 of this paper. First, let us recall the following definitions: Definition 4.1. Suppose $L(s)$ is an analytic $L$-function with ...
KStar's user avatar
  • 533
2 votes
1 answer
276 views

Geometric Interpretation of absolute Hodge cohomology

$\quad$Let $\mathcal{Sch}/\mathbb C$ denote the category of schemes over $\mathbb C$. For an arbitrary $X\in\mathcal{Ob}(\mathcal{Sch}/\mathbb C)$, Deligne in his Article defined a polarizable Hodge ...
user avatar
1 vote
0 answers
77 views

Optimality condition of the harmonic form representatives of a homology class

In "Hodge theory on metric spaces, Smale et al." the $d$-th harmonic forms of the Hodge Laplacian $\Delta_d=\delta^* \delta+\delta \delta^*$ satisfying $\Delta_d(f)=0$ are claimed to be ...
Alex Keros's user avatar
3 votes
2 answers
381 views

Generalization of the Leray-Hirsch theorem

We know the classical Leray-Hirsch theorem for fibrations. My question is, whether a similar statement also holds for flat, proper morphism? In particular, consider a faithfully flat, proper morphism $...
user43198's user avatar
  • 1,949
2 votes
1 answer
278 views

Middle cohomology of very general hyperplane sections

Let $X$ be a smooth, projective variety over $\mathbb{C}$ of dimension $n$ satisfying the property that for every $i \ge 0$, $H^{i,i}(X,\mathbb{C}) \cap H^{2i}(X,\mathbb{Q})=\mathbb{Q}c_1(\mathcal{O}...
Jana's user avatar
  • 2,022
3 votes
0 answers
165 views

Hodge-theoretic criterion for smoothness

Let $k$ be an algebraically closed field of any characteristic. Is it possible to give an equivalent condition for a $k$-variety to be smooth using only the cohomology of the variety (and whatever ...
user avatar
5 votes
2 answers
808 views

Mixed Hodge Polynomial for Algebraic Stacks

Let $X$ be a complex algebraic variety. The numerical invariants associated with the Mixed Hodge Structure of $X$ can be encoded in a polynomial in three variables called the mixed Hodge polynomial $H(...
Dr. Evil's user avatar
  • 2,711
56 votes
2 answers
10k views

What is prismatic cohomology?

Prismatic cohomology is a new theory developed by Bhatt and Scholze; see, for instance, these course notes. For the sake of the community, it would be great if the following question is discussed in ...
Dr. Evil's user avatar
  • 2,711
26 votes
2 answers
3k views

Hodge theory (after Deligne)

In an interview with Deligne on the Simons Foundation website, I heard Robert MacPherson say that at the time Deligne's papers on Hodge theory were being published, the results seemed absolutely ...
THC's user avatar
  • 4,503
12 votes
0 answers
593 views

Refinement of Hodge conjecture

This question deals with the classic Hodge conjecture on projective non-singular complex varieties, or in other words, projective Kähler manifolds. In Deligne's writeup for the Clay Foundation he says ...
David Roberts's user avatar
  • 34.8k
4 votes
0 answers
413 views

Complex manifolds with the same cohomology

Is there an example of two non-homeomorphic projective smooth complex varieties $X$ and $Y$ such that there exists an isomorphism $H^{\ast}(X,\mathbb{C})\rightarrow H^{\ast}(Y,\mathbb{C})$ of ...
Nguyen lan Lee's user avatar
5 votes
1 answer
442 views

Hodge decomposition for Bott-Chern cohomology

$\DeclareMathOperator{im}{im}$ I want to prove that Bott-Chern cohomology group $H^{p,q}_{BC}=\frac{\ker\partial\cap \ker\bar{\partial}}{\im\partial\bar{\partial}}$ has finite dimension via Hodge ...
Fallen Apart's user avatar
  • 1,615
3 votes
1 answer
325 views

Hypersurfaces without variable cohomology

Let $X$ be a smooth projective variety over $\mathbb C$ of dimension $n+1$. If $Y$ is a smooth very ample hypersurface, we know that except $H^n(X;\mathbb Q)\rightarrow H^n(Y;\mathbb Q)$, the ...
Honglu's user avatar
  • 1,079
6 votes
2 answers
410 views

Hodge map and the Cohomology Ring of a Riemannian Manifold

For a compact Riemannian manifold $M$, we know that the Hodge map $\ast$ and Laplacian $\Delta$ commute. From Hodge decomposition and its implied isomorphism between harmonic forms and cohomology ...
Andrea Pena's user avatar

15 30 50 per page