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Questions tagged [hodge-structure]

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3 votes
1 answer
180 views

When does the rational Hodge structure determine the integral Hodge structure?

Take a smooth complex projective variety $X$, consider $H^k(X,\mathbb Z)$, and take the global period domain as described, for example, in Voisin's Hodge theory book, 10.1.3: it's a subset of a flag ...
Nick Addington's user avatar
2 votes
1 answer
203 views

Prefactor $2\pi i$ for Tate-Hodge structure

A rather basic question. What was the original reason to consider the underlying $\mathbb{Z}$-module of the - as canonical object regarded - Tate-Hodge structure $\mathbb{Z}(1)$ to be given as $2 \pi ...
user267839's user avatar
  • 5,780
0 votes
0 answers
76 views

Hodge filtration vs Hodge structure on algebraic de Rham cohomology

I have a basic question on the relation between the definitions of the Hodge structure on the algebraic de Rham of a smooth proper scheme defined over a subfield of $\mathbb{C}$ and the Hodge ...
kindasorta's user avatar
  • 2,113
7 votes
0 answers
142 views

Is the $\ell$-adic cohomology ring of a cubic threefold a complete invariant?

The only interesting $\ell$-adic cohomology of a smooth cubic threefold $X$ is $H^3(X,\mathbb{Z}_{\ell}(2))$, which is isomorphic as a $\mathrm{Gal}_k$-module to $H^1(JX,\mathbb{Z}_{\ell}(1))^{\vee}$ ...
TCiur's user avatar
  • 557
2 votes
0 answers
163 views

Hodge bundles associated to a family of complex manifolds

I'm reading Voisin's books on Hodge theory. In the first volume she claimed but didn't prove this theorem: Theorem 10.10 (Voisin) Let $\varphi:\chi\rightarrow B$ be a family of compact complex ...
ZYun's user avatar
  • 21
1 vote
0 answers
83 views

Unique polarization on a very general curve with Mumford-Tate

I try to understand why a very general curve (smooth, projective over $\mathbb{C}$) has an unique polarization up to scalar on the $H^1(X,\mathbb{Q})$. I was advised to look at the maximality of the ...
Christopher Nicol's user avatar
2 votes
1 answer
276 views

Geometric Interpretation of absolute Hodge cohomology

$\quad$Let $\mathcal{Sch}/\mathbb C$ denote the category of schemes over $\mathbb C$. For an arbitrary $X\in\mathcal{Ob}(\mathcal{Sch}/\mathbb C)$, Deligne in his Article defined a polarizable Hodge ...
user avatar
2 votes
1 answer
203 views

Why do we ask Shimura datum to have Hodge weight $(-1,1),(0,0),(1,-1)$?

Why do we ask Shimura datum to have Hodge weight $(-1,1),(0,0),(1,-1)$? I know it's related to the decomposition of a complex Lie algebra $\frak{g}_{\mathbb{C}}=\frak{t}\oplus\frak{p}^{+} \oplus \frak ...
Marsault Chabat's user avatar
4 votes
1 answer
274 views

Hodge conjecture for generic points

I was reading the following paper: "Beilinson’s Hodge Conjecture For Smooth Varieties". They study the cycle class map $cl_{m,r}: H^{2r-m}_{\mathcal{M}}(U, \mathbb{Q}(r))\rightarrow \text{...
user127776's user avatar
  • 5,861
1 vote
0 answers
159 views

Beilinson-Hodge conjecture and generation of cohomology ring by $H^1$

Beilinson's version of Hodge conjecture has the following form. For any quasi-projective smooth complex variety $X$ the following map is surjective: $$H^i_{\mathcal{M}}(X, \mathbb{Q}(j))\rightarrow \...
user127776's user avatar
  • 5,861
1 vote
0 answers
115 views

Abelian subvarieties corresponding to vector subspaces

Let $S$ be a connected smooth projective surface. Let $C$ a smooth curve on $S$ In page 9 of the paper "https://arxiv.org/abs/1704.04187v1" a read the following: Let \begin{equation*} r: ...
Roxana's user avatar
  • 519
2 votes
0 answers
115 views

Nilpotent orbits and mixed Hodge structures

Let $(H_\mathbb{Z}, \{h^{p,q}\}_{p+q=n}, \phi)$ be the datum to define weight $n$ polarized Hodge structures on $H_\mathbb{Z}$, $h^{p,q}$ is the Hodge numbers, $\phi$ is a polarization. Let $D$ be the ...
user96145's user avatar
2 votes
0 answers
189 views

Cohomology of maps between Hilbert schemes

Let $S$ be a smooth complex projective surface. We consider the following two types of Hilbert schemes of $S$. The Hilbert scheme of an ample curve $D$. Suppose that $D$ is sufficiently ample, then ...
Pène Papin's user avatar
1 vote
0 answers
204 views

Exterior power of Hodge structures

Let $V$ be a $\mathbb{Q}$-vector space and suppose there is a decomposition of $V_{\mathbb{C}}:=V \otimes_{\mathbb{Q}} \mathbb{C}$ into two $\mathbb{C}$-sub-vector spaces i.e., $V_{\mathbb{C}} \cong V^...
Chen's user avatar
  • 1,593
7 votes
2 answers
642 views

Super mixed Hodge structures?

It's common in subjects that have some version of the "yoga of weights" that you have a functor called "Tate twist" and that the most natural version of it seems like it should be ...
Ben Webster's user avatar
  • 44.3k

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