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2 votes
3 answers
60 views

For which values the following summation converges

I have the following problem: For which $a$ and $b$ values does the following summation converges: $$\sum_{n=1}^{\infty}(-1)^{n-1}\left(a-\frac{(n-b)^n}{n^n}\right)$$ I tried to solve this in many ...
smith_brown's user avatar
5 votes
1 answer
409 views

Dini's theorem (specific case)

Note: I asked this question before but it wasn't well written, So I deleted my previous question and re-wrote it. According to Dini's theorem: If $X$ is a compact topological space, and $\{ f_n \}$...
Daniel98's user avatar
  • 421
2 votes
2 answers
367 views

Cauchy product summation converges

I had a previous question here, which I'm quoting: How can I prove that the following summation converges? $$\sum_{n=0}^\infty \sum_{k=0}^n \frac{(-1)^n}{(k+1) (n-k+1)}$$ I tried to prove ...
Daniel98's user avatar
  • 421
0 votes
2 answers
31 views

$\sum_{\alpha=0}^A\binom{A}{\alpha}(zb)^{\alpha} c^{A-\alpha} = (bz+c)^A$

Why the following equality holds:$$\sum_{\alpha=0}^A\binom{A}{\alpha}(zb)^{\alpha} c^{A-\alpha} = (bz+c)^A$$ How to prove it?
Johnpiton's user avatar
0 votes
1 answer
326 views

Dini's theorem, under which conditions?

According to Dini's theorem: If $X$ is a compact topological space, and $\{ f_n \}$ is a monotonically increasing sequence (meaning $f_n(x) \leq f_{n+1}(x)$ for all $n$ and $x$) of continuous ...
Daniel98's user avatar
  • 421
0 votes
0 answers
43 views

How to prove that a non-positive series converges?

Given a(n) a series that is monotonic and converges to zero which means: a(n)---->0. How to prove that the following summation converges for any K (a normal number): $$\sum\limits_{n=1}^\infty (-1)^{...
Daniel98's user avatar
  • 421
0 votes
2 answers
37 views

Summation with two costs

I need to find for which alpha and beta values, the following summation will converge and for which it will diverge $$\sum\limits_{n=1}^\infty (-1)^{n-1}\left(\alpha-\frac{(n-\beta)^n}{n^n}\right)$$ ...
Daniel98's user avatar
  • 421
3 votes
3 answers
120 views

radius of convergence of a given series

How could I find the radius of convergence for the following power series: $$ \sum\limits_{n = 1}^\infty {\frac{{2^{n - 1} x^{2n - 1} }}{{(4n - 3)^2 }}} . $$ From what I read I need to find: $$ \...
user avatar
0 votes
0 answers
37 views

Why the sum$\sum_{n=1}^\infty \left(n^{n^a}-1\right)$ converges when a is strictly less then -1

$$\sum_{n=1}^\infty \left(n^{n^a}-1\right)$$ Plugging in numbers on wolfram alpha I know that this sum converges when a is strictly less than -1. It is kinda very similar to the p-series test because ...
kman's user avatar
  • 1
1 vote
3 answers
196 views

Testing a Series for Convergence or Divergence

The problem is to test the following series for convergence: $\displaystyle\sum\limits_{i=1}^{\infty} ((i^2+1)/(i^3+1))$ I tried several tests like the root and limit comparison test but they ...
DoctorDave's user avatar
2 votes
0 answers
137 views

Can this summation be done without calculator?

Is it possible to perform the summation , $$\sum_{i=1}^{\infty} \frac{1}{i^i}$$ without the use of calculator? It does converge to a finite value = 1.29129... Wolfram Alpha link to this Describe the ...
Saket Gurjar's user avatar
  • 1,663
4 votes
5 answers
386 views

Show that $\sum_{n=0}^\infty \frac{1}{n+1} \binom{2n}{n} \frac{1}{2^{2n+1}} = 1.$

Question: Show that $$\sum_{n=0}^\infty \frac{1}{n+1} \binom{2n}{n} \frac{1}{2^{2n+1}} = 1.$$ From Wolfram alpha, it seems that the equality above is indeed correct. But I do not know how to ...
Idonknow's user avatar
  • 15.9k
3 votes
3 answers
74 views

Why would this series Absolutely Converge using Root Test?

So I was working on this problem and I got diverge, since my answer was greater than 1. The Limit was > 1, using the root test. $$\sum\limits_{n=4}^\infty (1 +\frac{1}{n})^{-n^2}$$ I ended up with ...
Adan Vivero's user avatar
2 votes
3 answers
5k views

How to evaluate whether summation of $e^n/(ne^n+1)$ diverges or converges?

How to test this summation for divergence or convergence? $$\sum_{n=0}^\infty \frac{e^n}{ne^n+1}$$ Edit: Here is my work, but I got it wrong. I tried using the comparison test. \begin{align*} a_n &...
Anna Nguyen's user avatar
1 vote
1 answer
219 views

Baby Rudin ex. 3.8 proof verification

The question asks: if $\sum a_n$ converges, $\{b_n\}$ is monotonic and bounded, prove that $\sum a_nb_n$ converges. My proof goes as follows: Let $\varepsilon>0$, and let $S_k$ denote $k$-th ...
askerxdf's user avatar

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