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3 votes
4 answers
84 views

Finding and proofing a closed formula for $\sum_{n=1}^k\sqrt{1+\frac{1}{n^2}+\frac{1}{(n+1)^2}}$

I want to find and proof a closed formula for the following sum $$\sum_{n=1}^k\sqrt{1+\frac{1}{n^2}+\frac{1}{(n+1)^2}}=\sqrt{1+\frac{1}{1^2}+\frac{1}{2^2}}+\sqrt{1+\frac{1}{2^2}+\frac{1}{3^2}}+\dots +\...
David Krell's user avatar
-1 votes
1 answer
126 views

Find the value $\sum_{n=a}^b\frac1{\sin (2^{n+3})}$ [closed]

Find the value of: $$\sum_{n=0}^{10}\frac1{\sin (2^{n+3})}$$ I'm stuck on this problem, can someone please help?
Shub's user avatar
  • 596
-1 votes
1 answer
75 views

how to find the sum of these terms without the gamma function?

While solving a problem based on integration, I arrived at the following $$\sum\limits_{x = 1}^{38} \ln\left(\frac{x}{x+1}\right)$$ I'm supposed to prove that this is less than $\ln(99)$ in order to ...
math and physics forever's user avatar
2 votes
1 answer
88 views

Best way to solve a summation with binomial coefficients in denominator apart from telecoping method

The value of $\sum_{r=1}^{m}\frac{(m+1)(r-1)m^{r-1}}{r\binom{m}{r}} = \lambda$ then the correct statement is/are (1) If $m=15$ and $\lambda$ is divided by m then the remainder is 14. (2) If $m=7$ and $...
Rishi Shekher's user avatar
-2 votes
2 answers
243 views

Sum the series : $\frac{1}{9\sqrt11 + 11\sqrt9} +\frac{1}{11\sqrt13 + 13\sqrt11} +\ldots$ [closed]

$$\frac{1}{9\sqrt11 + 11\sqrt9} + \frac{1}{11\sqrt13 + 13\sqrt11} + \frac{1}{13\sqrt15 + 15\sqrt13} + \ldots + \frac{1}{n\sqrt{n+2} + (n+2)\sqrt{n}} = \frac{1}{9}$$ Find the value of $n$. I got the ...
user1729's user avatar
  • 187
3 votes
1 answer
145 views

Find $\sum_{r=1}^{20} (-1)^r\frac{r^2+r+1}{r!}$.

Calculate $$\sum_{r=1}^{20} (-1)^r\frac{r^2+r+1}{r!}\,.$$ I broke the sum into partial fractions and after writing 3-4 terms of the sequence I could see that it cancels but I wasn't able to arrive at ...
Amadeus's user avatar
  • 1,107
2 votes
1 answer
149 views

Evaluate $\sum_{r=1}^{m} \frac{(r-1)m^{r-1}}{r\cdot\binom{m}{r}}$

Evaluate:$$\sum_{r=1}^{m} \frac{(r-1)m^{r-1}}{r\cdot\binom{m}{r}}$$ Using the property:$$r\binom{m}{r}=m\binom{m-1}{r-1}$$ It is same as $$\sum_{r=2}^{m} \frac{(r-1)m^{r-1}}{m\cdot\binom{m-1}{r-1}}$$ ...
user69608's user avatar
  • 888
0 votes
3 answers
2k views

If $\sum_{r=0}^{n-1}\log _2\left(\frac{r+2}{r+1}\right)= \prod_{r = 10}^{99}\log _r(r+1)$, then find $n$.

If \begin{align}\sum_{r=0}^{n-1}\log _2\left(\frac{r+2}{r+1}\right) = \prod_{r = 10}^{99}\log _r(r+1).\end{align} then find $n$. I found this question in my 12th grade textbook and I just can't wrap ...
Chris Williams's user avatar
1 vote
1 answer
195 views

Find the sum: $\sum_{n=1}^{20}\frac{(n^2-1/2)}{(n^4+1/4)}$

Hint: this is a telescoping series sum (I have no prior knowledge of partial fraction decomposition) Attempt: I tried to complete the square but the numerator had an unsimplifiable term. So I couldn't ...
sfsg's user avatar
  • 45
2 votes
3 answers
625 views

Prove sum of $k^2$ using $k^3$

So the title may be a little bit vague, but I am quite stuck with the following problem. Asked is to first prove that $(k + 1)^3 - k^3 = 3k^2 + 3k + 1$. This is not the problem however. The question ...
Matthias K.'s user avatar
1 vote
2 answers
83 views

Finding a formula for $\sum_{k=1}^n(k^2-(k-1)^2)$

I have got this following series: $$\sum_{k=1}^n(k^2-(k-1)^2)$$ I want to come up with a formula for the summation. I did some math and for me, the formula would be as follows: $$\sum_{k=1}^n(k^2-(...
Matheus Minguini's user avatar
0 votes
2 answers
184 views

Possible telescopic sum

Prove that $$\sum_{k=1}^n 4^{k}\sin^{4} \left(\frac{a}{2^k}\right) = 4^{n}\sin^{2} \left(\frac{a}{2^n}\right) - \sin^{2}a$$ I suspect that telescopic sum is involved but don't know how to proceed. ...
OhMyGauss's user avatar
  • 407
4 votes
2 answers
392 views

Find the sum of series: $\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt{3}+\sqrt{4}}+...+\frac{1}{\sqrt{97}+\sqrt{98}}+\frac{1}{\sqrt{99}+\sqrt{100}}$

Find the sum of series: $$\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt{3}+\sqrt{4}}+\frac{1}{\sqrt{5}+\sqrt{6}}+...+\frac{1}{\sqrt{97}+\sqrt{98}}+\frac{1}{\sqrt{99}+\sqrt{100}}$$ My Attempt: I tried ...
Maverick's user avatar
  • 9,599
0 votes
2 answers
52 views

Rewrite $\sum_{n=1}^k\log_3{(\frac{n+1}{n})}$ and write the formula in terms of k

Rewrite $\sum_{n=1}^k\log_3{(\frac{n+1}{n})}$ and write the formula in terms of k. I rewrote to $1+\frac{1}{n}$ and summed to get (I think) $\log_3(k+\frac{1}{n^k+k!})$ but I'm unsure if the $\log_3$ ...
T. Rowaway's user avatar
0 votes
2 answers
56 views

Rewrite $\sum_{n=1}^k{(n-1)/n!}$ and write the formula in terms of k [closed]

Rewrite $\sum_{n=1}^k{\frac{n-1}{n!}}$ I have turned it into $\frac{1}{n}*\frac{1}{(n-2)!}$ but do not know where to go from here.
T. Rowaway's user avatar
3 votes
4 answers
98 views

Compute $\sum_{k=1}^{25} (\frac{1}{k}-\frac{1}{k+4})$

Compute $\sum_{k=1}^{25} (\frac{1}{k}-\frac{1}{k+4})$ I know that some of the terms will cancel each other. Have it been $k+1$ instead of $k+4$, I could have easily see the pattern in which the terms ...
Eldar Rahimli's user avatar
0 votes
1 answer
38 views

Prove $x_n = \sum_{k=1}^n \frac{1}{(a+(k-1)\cdot d)\cdot(a+k\cdot d)}$ is a bounded sequence.

Let $n \in \mathbb N$ and: $$ x_n = \sum_{k=1}^n \frac{1}{(a+(k-1)\cdot d)\cdot(a+k\cdot d)} $$ Prove $\{x_n\}$ is a bounded sequence. I'm having hard time finishing the proof. Below is what i've ...
roman's user avatar
  • 5,411
2 votes
2 answers
3k views

Find $x$ if $\frac1{\sin1°\sin2°}+\frac1{\sin2°\sin3°}+\cdots+\frac1{\sin89°\sin90°} = \cot x\cdot\csc x$ [duplicate]

If $$\dfrac1{\sin1°\sin2°}+\dfrac1{\sin2°\sin3°}+\cdots+\dfrac1{\sin89°\sin90°} = \cot x\cdot\csc x$$ and $x\in(0°,90°)$, find $x$. I tried writing in $\sec$ form but nothing clicked. Any ideas?
TheGuyNotGoodAtMath's user avatar
1 vote
1 answer
270 views

Compute the values of the Double Sum

Compute the value of the following double sum: $$\sum_{\mu=1}^n\sum_{\upsilon=\mu+1}^n\frac{\mu^2}{\upsilon(2\upsilon-1)}$$ I started by simply trying to compute the value of the inner sum: $$\sum_{...
EllipticalInitial's user avatar
1 vote
4 answers
298 views

Evaluate a sum which almost looks telescoping but not quite:$\sum_{k=2}^n \frac{1}{k(k+2)}$ [duplicate]

Suppose I need to evaluate the following sum: $$\sum_{k=2}^n \frac{1}{k(k+2)}$$ With partial fraction decomposition, I can get it into the following form: $$\sum_{k=2}^n \left[\frac{1}{2k}-\frac{1}{...
EllipticalInitial's user avatar
0 votes
4 answers
186 views

Solving $\left(1+3+5...+(2n+1)\right ) + \left(3.5+5+6.5+...+(\frac{7+3n}{2})\right)=105$ [closed]

$\left(1+3+5...+(2n+1)\right ) + \left(3.5+5+6.5+...+(\frac{7+3n}{2})\right)=105$ It is the equation that I did not understand how to find $n.$
user avatar
3 votes
3 answers
153 views

Summing up $3+5+9+17+...$

Find the sum of sum of $3 +5+9+17+...$ till $n$ terms. Using Method of differences, the sum of the series is $$\sum\limits_{j=1}^n 2^{j-1}+n$$ I am facing difficulty in evaluating $$\sum\limits_{j=1}...
Archer's user avatar
  • 6,111
9 votes
3 answers
369 views

How to evaluate the sum : $\sum_{k=1}^{n} \frac{k}{k^4+1/4}$

I have been trying to figure out how to evaluate the following sum: $$S_n=\sum_{k=1}^{n} \frac{k}{k^4+1/4}$$ In the problem, the value of $S_{10}$ was given as $\frac{220}{221}$. I have tried ...
akhmeteni's user avatar
  • 671
1 vote
3 answers
325 views

A formula for $1^4+2^4+...+n^4$

I know that $$\sum^n_{i=1}i^2=\frac{1}{6}n(n+1)(2n+1)$$ and $$\sum^n_{i=1}i^3=\left(\sum^n_{i=1}i\right)^2.$$ Here is the question: is there a formula for $$\sum^n_{i=1}i^4.$$
abc...'s user avatar
  • 4,934
3 votes
2 answers
196 views

Inequality $\frac{1}{a+b}+\frac{1}{a+2b}+...+\frac{1}{a+nb}<\frac{n}{\sqrt{a\left( a+nb \right)}}$

Let $a,b\in \mathbb{R+}$ and $n\in \mathbb{N}$. Prove that: $$\frac{1}{a+b}+\frac{1}{a+2b}+...+\frac{1}{a+nb}<\frac{n}{\sqrt{a\left( a+nb \right)}}$$ I have a solution using induction, but ...
whitexlotus's user avatar
6 votes
4 answers
5k views

$\sum r(r+1)(r+2)(r+3)$ is equal to?

$$\sum r(r+1)(r+2)(r+3)$$ is equal to? Here, $r$ varies from $1$ to $n$ I am having difficulty in solving questions involving such telescoping series. While I am easily able to do questions where a ...
Siddharth Garg's user avatar
1 vote
2 answers
98 views

If $S=\frac{1}{1+1^2+1^4}+\frac{2}{1+2^2+2^4}+\cdots+\frac{n}{1+n^2+n^4}$, then calculate $14S$.

If $$S=\frac{1}{1+1^2+1^4}+\frac{2}{1+2^2+2^4}+\cdots+\frac{n}{1+n^2+n^4}\,$$ find the value of $14S$. The question can be simplified to: Find $S=\sum\limits_{k=1}^n\,t_k$ if $t_n=\dfrac{n}{1+n^2+n^...
oshhh's user avatar
  • 2,642
0 votes
5 answers
6k views

Prove $\sum_{k=1}^n \frac{1}{(2k-1)(2k+1)}=\frac{n}{2n+1}$ [closed]

I have attached an image of a kind of mathematical induction question that i have never seen before. I attached it because i don't know how to type all the symbols out properly, i'm sorry again would ...
Daniel's user avatar
  • 69
6 votes
3 answers
4k views

How to derive $\sum j^2$ from telescoping property

The book Real Analysis via Sequences and Series has a method of proving that $$\sum_{j=1}^n j = \frac{n(n+1)}{2}$$ that I've never seen before. The way they do it is by starting with $\sum (2j+1)$, ...
user328348's user avatar
2 votes
2 answers
129 views

Proving that $\sum_{i=1}^n\frac{1}{i^2}<2-\frac1n$ for $n>1$ by induction [duplicate]

Prove by induction that $1 + \frac {1}{4} + \frac {1}{9} + ... +\frac {1}{n^2} < 2 - \frac{1}{n}$ for all $n>1$ I got up to using the inductive hypothesis to prove that $P(n+1)$ is true but I ...
shoestringfries's user avatar
15 votes
1 answer
31k views

Find the sum $\frac{1}{\sqrt{1}+\sqrt{2}} + \frac{1}{\sqrt{2}+\sqrt{3}} + ...+ \frac{1}{\sqrt{99}+\sqrt{100}}$

I would like to check I have this correct Find the sum $$\frac{1}{\sqrt{1}+\sqrt{2}} + \frac{1}{\sqrt{2}+\sqrt{3}} + ...+ \frac{1}{\sqrt{99}+\sqrt{100}}$$ Hint: rationalise the denominators to ...
mikoyan's user avatar
  • 1,155