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0 votes
1 answer
22 views

How to more formally prove this inequality

This is a simple problem I came up with while doing another problem: Given: $n < (n + \frac{1}{2}) < y < (n + 1)$ Prove: $|y - n| > |y - (n + 1)|$ So how I proved it was simply using the ...
Bob Marley's user avatar
-3 votes
4 answers
108 views

why is the co-prime part not mentioned in the definition of the rational number?

Proving $\sqrt{2}$ an irrational number is a quite popular exercise, in precalculus courses, but if we look clearly the definition that is introduced, in the beginning of the course, it never ...
Yanjan. Kaf.'s user avatar
-1 votes
1 answer
52 views

Prove that there exist equal number of irrational numbers between any 2 rational numbers, when the difference between the 2 rational numbers is same. [closed]

Prove that there exist equal number of irrational numbers between any 2 rational numbers, when the difference between the 2 rational numbers is same. If the assertion is not true then please prove ...
Ash_Tag's user avatar
7 votes
2 answers
276 views

Baby Rudin Theorem 1.19 Step 5

I have no background in pure mathematics, and I'm trying to learn how to be more rigorous in general. To help with this, I am trying to make everything more explicit as I progress through Rudin's ...
AspiringScrub's user avatar
0 votes
1 answer
137 views

proof of infimum and upper bound of $(1+1/n)^n$

I have to prove that 2 is the minimum, and therefore infimum of the set of all numbers $(1+1/n)^n$, where $n$ are positive integer numbers. And also that it is upper bounded, not necessarily to show ...
TheScientist's user avatar
1 vote
0 answers
59 views

Exercise 6, Section 2.2 of Hoffman’s Linear Algebra

(a) Prove that the only subspaces of $\Bbb{R}$ are $\Bbb{R}$ and the zero subspace. (b) Prove that a subspace of $\Bbb{R}^2$ is $\Bbb{R}^2$, or the zero subspace, or consist of all scalar multiples of ...
user264745's user avatar
  • 4,227
0 votes
1 answer
163 views

Prove that the closed interval [a, b] is compact.

I am studying the topology of $\mathbb{R}$ and I want to prove that the closed interval $[a,b]$ is compact using the Heine-Borel Theorem that a set in $\mathbb{R}$ is compact iff it is closed and ...
user avatar
0 votes
3 answers
179 views

Is a bounded polynomial constant? [duplicate]

I am trying this problem: If $p(x)$ is a bounded polynomial for all $x\in \mathbb R$, then $p(x)$ must be a constant. I am trying to prove it by contradition. So I assume that $p(x)$ is bounded for ...
learningmaths's user avatar
3 votes
1 answer
94 views

Help With Basic Proof from Rudin PMA Chapter One

From Walter Rudin's Principles of Mathematical Analysis, Third Edition, page 20, Step 8: I want to complete the proof of (b) by proving the following claim. Claim: For $r\in{}\mathbb{Q}^+$ and $s\in{}...
Gary's user avatar
  • 515
6 votes
1 answer
202 views

Different definitions of the archimedean property

In some textbooks I have seen the archimedean property defined as: for some positive real $x$, real number $y$, there exists a natural $n$ such that $nx>y$. In other textbooks the archimedean ...
Elimination_matrices's user avatar
0 votes
1 answer
264 views

Proving trichotomy and transitivity from the definition of an ordered field

I'm reading a set of notes (and can provide the link if anyone is interested) which attempt to build up the properties of an ordered field. After defining a field based on its axioms, it defines an ...
JohnT's user avatar
  • 1,418
0 votes
2 answers
105 views

Is there a proof for triangle inequality in $\mathbb{R}$ by contradiction/absurd?

I want to prove that given $a,b,c\in\mathbb{R}$ we have $|a+b|\leq|a|+|b|$ using an absurd and reaching a contradiction. So, I state, by absurd, that $|a+b|>|a|+|b|$, but I can't reach the ...
Curious's user avatar
  • 369
0 votes
0 answers
137 views

Prove $(-a)^{-1} = -a^{-1}$

This is my proof for part (17) of Lemma 2.3.2 in Bloch's Real Analysis. I'd like if someone verifies that I did not miss or skip a step, did anything unjustified, or anything of this sort. I will ...
Hassan Ashraf's user avatar
2 votes
0 answers
70 views

If $0<a<b$ and $0<c<d$ then $bd+ac>bc+ad.$ Can this inequality be generalised to include more than just two lots of two numbers?

$0.7<2.4,\ $ and $\ 0.8< 0.9.$ By calculation, we see that $0.7\times 0.8 + 2.4\times 0.9 > 0.7\times 0.9 + 2.4\times 0.8.$ Indeed, for any pair of two numbers $\ 0<a<b\ $ and $\ 0<c&...
Adam Rubinson's user avatar
2 votes
1 answer
63 views

Proving a rational number is NOT in the lower Dedekind cut for a transcendental number

I'm attempting to argue with a finitist who claims that transcendental numbers can't be defined as Dedekind cuts without using an infinite predicate or in some other way requiring an infinite number ...
antimeme's user avatar
  • 121

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