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76 votes
7 answers
33k views

Is an automorphism of the field of real numbers the identity map?

Is an automorphism of the field of real numbers $\mathbb{R}$ the identity map? If yes, how can we prove it? Remark An automorphism of $\mathbb{R}$ may not be continuous.
Makoto Kato's user avatar
  • 42.9k
10 votes
2 answers
1k views

Are the real numbers the unique Dedekind-complete ordered set?

A totally ordered set is Dedekind-complete if any subset which has an upper bound also has a least upper bound. Now any two ordered fields which are Dedekind-complete are order-isomorphic as well as ...
Keshav Srinivasan's user avatar
1 vote
3 answers
172 views

What are all different (non-isomorphic) field structures on $\mathbb R \times \mathbb R$

We know that $\mathbb R \times \mathbb R$ forms a field under addition and multiplication defined as $(a,b)+(c,d)=(a+c,b+d)$ ; $(a,b)*(c,d)=(ac-bd,ad+bc)$ ; is there any other way to make $\mathbb R \...
Souvik Dey's user avatar
  • 8,387
3 votes
1 answer
136 views

Is there an ordered field with distinct subfields isomorphic to the reals?

Is there an ordered field with distinct subfields isomorphic to the field $\mathbb R$ of real numbers?
Pierre-Yves Gaillard's user avatar