Skip to main content

All Questions

1 vote
2 answers
66 views

Transforming two index sum into single index sum

I know this is a quite basic question, but I have been looking at it for more than I would like to admit and I simply don't see the solution. Namely, I have the sum: $$\sum_{1\leq i < j \leq n} \...
AlaskaYoung's user avatar
3 votes
2 answers
123 views

Does this sum converge? Does it converge absolutely? $\sum_{n=1}^{\infty} \frac{(-1)^n}{n-\sqrt{n-1}}$

Does this sum converge? Does it converge absolutely? $$\sum_{n=1}^{\infty} \frac{(-1)^n}{n-\sqrt{n-1}}$$ I first checked absolute convergence. Taking the absolute value of the term, we get $\frac{1}{...
wengen's user avatar
  • 1,135
5 votes
1 answer
106 views

Does this serie converge ? $\sum_{n=1}^{\infty} \frac{1}{n^3 - 5n}$

Does this serie converge ? $$\sum_{n=1}^{\infty} \frac{1}{n^3 - 5n}$$ We have $$n^3 - 5n < n^3 \implies \frac{1}{n^3-5n} > \frac{1}{n^3}$$ We know $\frac{1}{n^3}$ converges because it's a p ...
wengen's user avatar
  • 1,135
3 votes
2 answers
181 views

Interchanging integration with summation on a specific example

Consider the infinite sum $$S=\sum_{j=1}^\infty (-1)^{j +1}\frac{1}{2j+1} \int_0^1 \frac{1-x^{2j}}{1-x}dx$$ and the associated integral $$L=\int_0^1 \sum_{j=1}^\infty\frac{ 1-x^{2j}}{1-x} (-1)^{j +1}\...
ray's user avatar
  • 482
2 votes
1 answer
114 views

Complete the proof of $ \int_{-\infty}^{\infty}{e^{-x^2/2}x^{2n} dx} = \sqrt{2\pi} \frac{(2n)!}{2^nn!} $

What I already know is that if $L(s) := \int_{-\infty}^{\infty}{e^{sx}e^{\frac{-x^2}{2}} dx}=\sqrt{2\pi}e^{\frac{s^2}{2}}$, then $L^{(2n)}(0)=\int_{-\infty}^{\infty}{e^{\frac{-x^2}{2}}x^{2n} dx}$. So ...
OLalalala's user avatar
0 votes
0 answers
30 views

Useful Partial Sums

The following formula: $$\sum_{k=m}^nf(k)=c(n-m)+\sum_{k=m}^\infty(f(k)-f(k+n))$$(Where $f\rightarrow c$) can be proven by telescoping the infinite sum in the RHS. The use of this formula is to expand ...
Kamal Saleh's user avatar
  • 6,549
1 vote
3 answers
103 views

Why $\sum_{k=1}^n \frac{a_k}{s-a_k}=s \sum_{k=1}^n \frac{1}{s-a_k}-n$ where is $s=\sum_{k=1}^n a_k$?

Why $$\sum_{k=1}^n \frac{a_k}{s-a_k}=s \sum_{k=1}^n \frac{1}{s-a_k}-n$$ where is $s=\sum_{k=1}^n a_k$? but not $$\sum_{k=1}^n \frac{a_k}{s-a_k}=\sum_{k=1}^n \sum_{k=1}^n \frac{a_k}{s-a_k} \neq s \...
SysRq308's user avatar
  • 153
1 vote
1 answer
79 views

Asymptotic equivalent of $\sum_{k=1}^n a^k k^{-1/2}$

I encountered recently the following partial sum $\sum_{k=1}^n a^k k^{-1/2}$ with $a$ a constant approximately equal to $2.955$. I was wondering if there were any clever way to find an asymptotic to ...
Florian Ingels's user avatar
1 vote
0 answers
67 views

Proof of Cesàro summation

This is a proof I came up with while working on the textbook Understanding Analysis: Supposing $x_{n} \rightarrow x$, we have that $$s_n = \frac{1}{n} \sum_{k=1}^{n} x_k \rightarrow x$$ Let $\epsilon \...
Mani's user avatar
  • 402
1 vote
0 answers
50 views

$\dfrac{\mathrm{d}^n}{\mathrm{d}x^n}\dfrac{e^{ax}}{\ln(cx)}$ and summation with Stirling number of the first kind

I would like to calculate the $n$-th derivative of $\dfrac{e^{ax}}{\ln(cx)}$ I tried to calculate it in this way: $$(fg)^{(n)}(x)=\sum_{k=0}^{n}\binom{n}{k}f^{(k)}(x)g^{(n-k)}(x)$$ $$\frac{\mathrm{d}^...
Math Attack's user avatar
4 votes
1 answer
89 views

A conjecture involving series with zeta function

Recently, I tried to evaluate a limit proposed by MSE user Black Emperor. In the process of evaluating the limit, I have obtained the following equality. $$ \lim_{N\rightarrow \infty} \sum_{n=0}^{N-2}{...
oO_ƲRF_Oo's user avatar
  • 1,250
4 votes
0 answers
87 views

How deduce $\prod_{k=1}^{(n-1)/2} \sin^2 \frac{k\pi}{n} =\frac{n}{2^{n-1}}$ from $\prod_{k=1}^{n-1} \sin \frac{k\pi}{n} =\frac{n}{2^{n-1}}$?

I know that $\displaystyle\prod_{k=1}^{n-1} \sin \frac{k\pi}{n} =\frac{n}{2^{n-1}}$ for any integer $n \geq 1$ is true. Now, suppose that $n$ is odd, how show $$ \prod_{k=1}^{(n-1)/2} \sin^2 \frac{k\...
Liam's user avatar
  • 323
4 votes
0 answers
135 views

Simplify a summation in the solution of $\displaystyle\int_{0}^{\infty}e^{-cx}x^{n}\arctan(ax)\mathrm{d}x$

Context I calculated this integral: $$\begin{array}{l} \displaystyle\int_{0}^{\infty}e^{-cx}x^{n}\arctan(ax)\mathrm{d}x=\\ \displaystyle\frac{n!}{c^{n+1}}\left\lbrace\sum_{k=0}^{n}\left[\text{Ci}\left(...
Math Attack's user avatar
0 votes
1 answer
56 views

Simplify $ \sum\limits_{i=0}^l{n\choose i}{m\choose l-i}$

Is there a nice way to simplify $ \sum\limits_{i=0}^l{n\choose i}{m\choose l-i}$? I tried to tinker a bit with telescope sums but it did not get me nowhere...
Philipp's user avatar
  • 4,564
1 vote
1 answer
74 views

Estimating a sum with an integral to nearest power of $10$

Suppose I want to estimate the sum $\sum_{x = -1000}^{1000} \sum_{y: x^2 + y^2 < 10^6 } x^2$, or identically, $\sum_{y = -1000}^{1000} \sum_{x: x^2 + y^2 < 10^6 } x^2$, to the nearest power of $...
algebroo's user avatar
  • 731

15 30 50 per page
1
3 4
5
6 7
73