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3 votes
0 answers
162 views

Closed form for $\sum_{k=n}^{2n-1} k(-1)^k \sum_{i=k}^{2n-1} {2n \choose i+1} {i \choose n}$?

I've found this sum: $$S(n) = \sum_{k=n}^{2n-1} k(-1)^k \sum_{i=k}^{2n-1} {2n \choose i+1} {i \choose n}$$ The inner sum is elliptical iirc, but perhaps the double sum has a nice expression. We can ...
hellofriends's user avatar
  • 1,940
2 votes
1 answer
139 views

Finding the value of $\sum^{\infty}_{n=3,5,7,9....}\frac{2n^2 \exp(-\pi n/2)}{\exp(\pi n)+1}$

I want to evalutate: $\displaystyle \tag*{} \sum \limits ^{\infty}_{n=3,5,7,9....}\dfrac{2n^2 \exp \left(-\pi n/2\right)}{\exp(\pi n)+1}$ This question is inspired from my previous question which ...
Dhanvin's user avatar
  • 921
2 votes
0 answers
28 views

Summation with given parameter :

Consider the following sum: $$F(x)=\sum_{n=2}^{\infty}\frac{1}{(n\ln(n))^x}$$ Now this series converges for $x>1$. Can we get a closed form of this function for $x>1$?
GSA_1's user avatar
  • 187
1 vote
3 answers
177 views

Find the sum $\sum_{n=1}^\infty\frac{\sqrt{n}}{2^{n/2}}$

Find the sum $\sum_{n=1}^\infty\frac{\sqrt{n}}{2^{n/2}}$. Is it possible to find a closed form for this sum? I was trying to upper bound this sum by another series, but could not find one. Can anyone ...
Maths Freak's user avatar
4 votes
1 answer
180 views

A new sum that equals $-\frac12 \ln (\frac{\pi}{2})$

(See EDIT) I found this result while working another problem in two slightly different directions and it kind of took me by surprise. $$ \begin{align} &\sum_{n=1}^{\infty}\left(\frac{\ln4n}{4n-1}-\...
tyobrien's user avatar
  • 3,557
7 votes
2 answers
268 views

Possible to get a closed form expression, or an upper bound, for $ f(n)=\sum_{m=1}^\infty \bigg(\frac{m+n}{3}\bigg)^{m+n}\bigg(\frac{1}{m}\bigg)^m$?

Is it possible to get a closed form expression, or an upper bound, for the following function $f$ which is given by an infinite summation: $$ f(n) = \sum_{m=1}^\infty \bigg(\frac{m+n}{3}\bigg)^{m+n} \...
sonicboom's user avatar
  • 10k
-1 votes
1 answer
108 views

Does $\sum\limits_{k=2}^{\infty}{\frac{|B_{k}|}{k!}(\cos(n)-1)}$ have a closed form?

I am trying to find a closed form expression of the following sum in terms of $n$ (if it exists) where $B_{k}$ is the $k$th Bernoulli number. $$\sum_{k=2}^{\infty}{\frac{|{B_{k}|}}{k!}(\cos(n)-1)}$$ ...
Gnumbertester's user avatar
8 votes
1 answer
259 views

Showing that $\sum_{j=0}^{2n-1}{\cos^n(\frac{j\pi}{2n})(2\cos(\frac{2j\pi}n)+1)\cos(\frac{j\pi}2-\frac{2j\pi}n)}$ is never an integer for $n>10$

I want to show that $$f(n) = \sum_{j=0}^{2n-1}{\cos^n\left( \frac{j \pi}{2n}\right) \left( 2\cos \left( \frac{2 j \pi}{n} \right) + 1\right) \cos \left( \frac{j \pi}{2} - \frac{2 j \pi}{n} \right)}$$ ...
spyr03's user avatar
  • 1,034
3 votes
1 answer
98 views

How can I sum the series $e^{-2}\frac{(3)^n}{n!}\sum_{k=0}^{\infty}\left ( \frac{1}{2}\right )^k\frac{1}{(k-n)!}$

How can I sum the following series? $$e^{-2}\frac{(3)^n}{n!}\sum_{k=0}^{\infty}\left ( \frac{1}{2}\right )^k\frac{1}{(k-n)!}$$ I think I can make this sum in the form of exponential expansion but ...
userNoOne's user avatar
  • 1,204
5 votes
2 answers
200 views

What is the close form of: $\sum\limits_{k=1}^{\infty}\log\left(\frac{1}{k^2}+1\right)$

Is there a close form for of this series $$\sum_{k=1}^{\infty}\log\left(\frac{1}{k^2}+1\right) =\log \prod_{k=1}^{\infty}\left(\frac{1}{k^2}+1\right)$$ I know it converges in fact since $ \log(x+1)\...
Guy Fsone's user avatar
  • 24.2k
1 vote
1 answer
66 views

Values for which this sum can be defined in terms of known constants in a closed form

I'm interested in the sum, $$\sum_{n=1}^\infty\frac{\zeta(2n)\Gamma(2n)}{\Gamma(2k+2n+2)}x^{2n}$$ Otherwise written as $$\sum_{n=1}^\infty\frac{\zeta(2n)}{(2n)(2n+1)\cdots(2n+2k+1)}x^{2n}$$ I am ...
tyobrien's user avatar
  • 3,557
3 votes
3 answers
3k views

Sum of a series $\frac {1}{n^2 - m^2}$ m and n odd, $m \ne n$

I was working on a physics problem, where I encountered the following summation problem: $$ \sum_{m = 1}^\infty \frac{1}{n^2 - m^2}$$ where m doesn't equal n, and both are odd. n is a fixed constant ...
Zar's user avatar
  • 539
4 votes
1 answer
197 views

Formula for $\sum\limits_{j=1}^{m-1}\frac{1}{\sin^{2p}(\frac{j\pi}{m})}$

Let $m\geq 2$ be an integer, then there is the well known formula $$\sum\limits_{j=1}^{m-1}\frac{1}{\sin^2(\frac{j\pi}{m})}=\frac{m^2-1}{3},$$ I'm interested in similar equations for the following ...
Braten's user avatar
  • 1,965
2 votes
0 answers
92 views

How to find $\sum_{n \in \mathbb Z_+} \frac{2^{n-1}}{2^{2^n}}$?

I'm trying to calculte the measure of a fat Cantor set, but run into this question: How to find $$\sum_{n \in \mathbb Z_+} \frac{2^{n-1}}{2^{2^n}}$$
Epicurus's user avatar
  • 407
3 votes
5 answers
390 views

Infinite Series $\left(\frac12+\frac14-\frac23\right)+\left(\frac15+\frac17-\frac26\right)+\left(\frac18+\frac{1}{10}-\frac29\right)+\cdots$ [duplicate]

How do I find the sum of the following infinite series: $$\left(\frac12+\frac14-\frac23\right)+\left(\frac15+\frac17-\frac26\right)+\left(\frac18+\frac{1}{10}-\frac29\right)+\cdots$$ The series ...
Kalpan's user avatar
  • 375

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