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35 votes
3 answers
17k views

What are examples of irreducible but not prime elements?

I am looking for a ring element which is irreducible but not prime. So necessarily the ring can't be a PID. My idea was to consider $R=K[x,y]$ and $x+y\in R$. This is irreducible because in any ...
MyNameIs's user avatar
  • 1,057
17 votes
1 answer
963 views

What is the correct notion of unique factorization in a ring?

I was recently writing some notes on basic commutative ring theory, and was trying to convince myself why it was a good idea to study integral domains when it comes to unique factorization. If $R$ is ...
Ishan Levy's user avatar
13 votes
2 answers
3k views

$K[x_1, x_2,\dots ]$ is a UFD

I wonder about how to conclude that $R=K[x_1, x_2,\dots ]$ is a UFD for $K$ a field. If $f\in R$ then $f$ is a polynomial in only finitely many variables, how do I prove that any factorization of $f$...
harajm's user avatar
  • 2,157
8 votes
5 answers
14k views

Proving gcd($a,b$)lcm($a,b$) = $|ab|$

Let $a$ and $b$ be two integers. Prove that $$ dm = \left|ab\right| ,$$ where $d = \gcd\left(a,b\right)$ and $m = \operatorname{lcm}\left(a,b\right)$. So I went about by saying that $a = p_1p_2......
SalmonKiller's user avatar
  • 2,148
7 votes
2 answers
4k views

Prove that every nonzero prime ideal is maximal in $\mathbb{Z}[\sqrt{d}]$

$d \in \mathbb{Z}$ is a square-free integer ($d \ne 1$, and $d$ has no factors of the form $c^2$ except $c = \pm 1$), and let $R=\mathbb{Z}[\sqrt{d}]= \{ a+b\sqrt{d} \mid a,b \in \mathbb{Z} \}$. Prove ...
PandaMan's user avatar
  • 3,269
7 votes
1 answer
211 views

Irreducibility of an integer polynomial with exponents in linear sequence?

Let $b$ and $n$ be two positive integers. Is there are a general result which tell us when the polynomial $$1+x^{b}+x^{2b}+x^{3b}+\cdots+x^{nb}$$ is irreducible over the integers? I know that $$1+x+...
user avatar
6 votes
1 answer
148 views

factoring $x^n+x+1$

Is there a way of factoring a polynomial of the general form $$x^n+x+1$$ in the ring $\mathbb C[x]$ or $\mathbb R[x]$ or $\mathbb Z [x]$ for any $n \in \mathbb N$? (Or perhaps with certain conditions ...
flawr's user avatar
  • 16.7k
5 votes
3 answers
183 views

Sanity check on factorization of $\langle 5 \rangle$ in $\mathbb{Z}_{10}$

Looking at $\mathbb{Z}_{10}$, consisting of $0, 1, 2, 3, 4, 5, 6, 7, 8, 9$ with addition and multiplication adjusted so the ring is closed under both operations. Clearly $5 = 3 \times 5 = 5 \times 5 =...
Mr. Brooks's user avatar
  • 1,108
4 votes
1 answer
2k views

How can I find decompositions in $\mathbb{Z}[\sqrt{d}]$?

Decompositions in $\mathbb{Z}$ In $\mathbb{Z}$ you can find a decomposition of any element $n \in \mathbb{Z}$ by factorization such that $$n = \prod_{p \in \mathbb{P}} p^{v_p(n)}$$ So for a ...
Martin Thoma's user avatar
  • 9,891
4 votes
2 answers
1k views

Verifying prime factorization equivalence class

I define a relation on $\Bbb N$ as follows: $x \sim y \Longleftrightarrow \ \exists \ j,k \in \Bbb Z$ s.t. $x \mid y^j \ \wedge \ y \mid x^k$ I have shown that $\sim$ is an equivalence relation by ...
Moderat's user avatar
  • 4,467
3 votes
2 answers
682 views

Definition of UFD and the fact that UFDs are integrally closed

I am trying to understand the proof of the fact that UFDs are integrally closed. In addition to the lecture notes I have, there are at least two solutions on MSE: One is here: How to prove that UFD ...
abeliangrape's user avatar
3 votes
1 answer
84 views

A non-UFD $B$ such that $A \subset B \subset C$, where $A \cong C$ are UFD's

Let $A \subset C$ be two isomorphic unique factorization domains (UFD's). Is it possible to find an integral domain $B$, $A \subset B \subset C$, such that $B$ is not a UFD? I have tried to ...
user237522's user avatar
  • 6,705
3 votes
3 answers
764 views

Is $\mathbb{Z}[√13] $ a Unique factorization domain?

I think it is not so as $12 $ can be written in two ways $12=2.6=(1+\sqrt{13})(-1+\sqrt{13})$. Are these two factorization unique upto irreducibles? Please help.
Promit Mukherjee's user avatar
3 votes
1 answer
480 views

Why a certain integral domain is not a UFD.

Let $$\mathbb{Z}[q]^{\mathbb{N}} = \varprojlim_j \mathbb{Z}[q]/((1-q)\cdots (1- q^j))$$ Why isn't $\mathbb{Z}[q]^{\mathbb{N}}$ a unique factorization domain? The author proposes a proof whose ...
user313212's user avatar
  • 2,236
3 votes
1 answer
688 views

Primary Decomposition

The standard primary decomposition theorem in algebra is about being able to write an ideal uniquely as an intersection of primary ideals. In linear algebra the theorem is about how a vector space can ...
user109871's user avatar
  • 1,457

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