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0 votes
0 answers
66 views

Why $r \notin R^*$ if it is a prime? [duplicate]

My professor gave us the following definition: Let $R$ be a commutative ring. $r \in R$ is prime if $r.R$ is a prime ideal. Then he concluded that this definition tells us $r \notin R^*$ but I do not ...
user avatar
3 votes
0 answers
180 views

Does every commutative ring with $1 \neq 0$ and a non-zero, non-unit element contain a prime element?

As above, I am trying to answer the following question: "Does every commutative ring with $1 \neq 0$ and a non-zero, non-unit element contain a prime element?" Since in some books prime elements are ...
Pawel's user avatar
  • 4,899
1 vote
0 answers
61 views

minimality of ideals generated by primes among the prime ideals

I have following task: Given a factorial ring $R$ (i.e. with unique prime decomposition) and a prime element $a \in R$ prove that if $I \subseteq R$ is a prime ideal with $(0) \subseteq I \subseteq ...
flawr's user avatar
  • 16.7k
5 votes
3 answers
183 views

Sanity check on factorization of $\langle 5 \rangle$ in $\mathbb{Z}_{10}$

Looking at $\mathbb{Z}_{10}$, consisting of $0, 1, 2, 3, 4, 5, 6, 7, 8, 9$ with addition and multiplication adjusted so the ring is closed under both operations. Clearly $5 = 3 \times 5 = 5 \times 5 =...
Mr. Brooks's user avatar
  • 1,108
0 votes
1 answer
110 views

Is every polynomial with integer coefficients prime in $\mathbb{Z}[x]$ also prime in $\mathbb{Q}[x]$? [closed]

The question is as in the title: Is every polynomial with integer coefficients prime in $\mathbb{Z}[x]$ also prime in $\mathbb{Q}[x]$?
Julio Yarasca's user avatar