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4 votes
1 answer
62 views

Every binary tree with $n$ leaves has a subtree with $k$ leaves where $\frac{n}{3} \leq k \leq \frac{2n}{3}$.

I want to show the following: Every binary tree with $n$ leaves has a subtree with $k$ leaves where $\frac{n}{3} \leq k \leq \frac{2n}{3}$. My approach: First thing I did was to draw a binary tree and ...
NTc5's user avatar
  • 609
1 vote
0 answers
132 views

How many trees with $n$ vertices correspond to the vector $(g_1,g_2,g_3,g_4)$, where the $g_i$ are the number of vertices of degree $i$?

Let there be a tree with $n$ vertices. How to count the number of trees corresponding to the set $(g_1,g_2,g_3,g_4)$, where $g_i$ is the number of vertices of degree $i$? For example, with $n=8$ we ...
user avatar
2 votes
1 answer
47 views

Suppose a tree graph T with $n\ge 4$ ,and 3 edges $e_1,e_2,e_3$ from its complement tree graph T-.Show that $G = T + e_1 + e_2 +e_3$ is a planar graph

can't seem to find the proof for this problem. I know that a Tree graph has the property: $n = m - 1$ where $n$ is the number vertices and $m$ is the number of edges. Also not sure if the restriction ...
Steve M.'s user avatar
0 votes
1 answer
67 views

How many subgraphs with exactly 6 edges can I make from a complete graph with 7 vertices?

Let the complete graph be unweighted and undirected. The subgraphs can be unconnected. Edit (More detail): I'm trying to go about this by splitting it up into spanning trees and non-spanning trees ...
Chris Hacen's user avatar
4 votes
1 answer
99 views

Suppose $G$ is a bipartite planar graph such that for any two vertices $A$ and $B$

Suppose $G$ is a bipartite planar graph such that for any two vertices $A$ and $B$, the number of shortest paths from $A$ to $B$ is odd. Prove that $G$ is a tree. Suppose $G$ is a bipartite planar ...
urt43as's user avatar
  • 341
2 votes
1 answer
86 views

Do minimum spanning trees drawn on points in $\mathbb{R}^2$ always have non-intersecting edges?

Preamble This question is motivated by the question "Embedded minimum spanning trees for visualizing effects of dimensionality reduction?". Suppose I were to begin with a collection of ...
Galen's user avatar
  • 1,876
1 vote
1 answer
54 views

Does every 3-valent planar graph admit a maximal tree, which is non-branching?

Consider a $3$-valent (multi)graph without loops, i.e. multiple edges are allowed, but there are no edges starting/ending at the same vertex. Furthermore, lets assume $\gamma$ is planar, which means ...
B.Hueber's user avatar
  • 2,876
0 votes
1 answer
108 views

What is a convex combination of graphs?

For example in this paper, they refer to a "convex combination of trees" (pg. 2, first paragraph), and also, more generally, to "convex combination of graphs" (pg. 2, footnote). -&...
Syed M. Akbari's user avatar
4 votes
1 answer
203 views

Is $T_1+T_2$ planar if $T_1,T_2$ are trees with the same vertices?

I have two trees $T_1=(V,E_1)$ and $T_2=(V,E_2)$. My question is, supposing that $G=(V,E_1\cup E_2)$, can we conclude that $G$ is planar? I think it's planar, because $G$ is created by the union of ...
tstt's user avatar
  • 341
11 votes
0 answers
301 views

Can every tree with total length $2$ be covered by a semi-disc of radius $1$?

Can every tree with total length $2$ be covered by a semi-disc of radius $1$? If the tree is actually a curve, or the convex hull of the tree is a triangle, I know this is correct after some attempts. ...
Minghui Ouyang's user avatar
1 vote
2 answers
395 views

Showing that any tree has a separator vertex such that the size of the separated components is at most $\lfloor\frac{k}{n}V(G)\rfloor$

The task is to show that one can always find such a separator vertex in a tree $T$ such that the created components have a size of at most $\lfloor\frac{k}{n}V(G)\rfloor, \frac{k}{n} \in (0, 1)$ in ...
Epsilon Away's user avatar
  • 1,030
11 votes
0 answers
488 views

Parity on the number of rooted trees

Suppose we have a planar graph with vertices $v_0, \ldots, v_n$, where $n$ is even such that there exist a checkerboard coloring of the regions in the complement such that the black regions are $n$ (...
user avatar
1 vote
1 answer
2k views

show that all trees are planar without using Euler's formula or the fact that all trees are planar

the question is this: Show that all trees are planar I thought about using Euler's formula to show this but then I was told that I wasn't allowed to assume that trees are connected planar graphs so my ...
user avatar
2 votes
1 answer
407 views

Given a binary tree with N labelled leaves, is it possible to find its unique number in the Catalan range?

The question is about finding the inverse to the problem of generating the $n^{th}$ binary tree with N labelled leaves (Generating the $n^{th}$ full binary tree over $N$ labelled leaves). Let's say if ...
Ganesh's user avatar
  • 21
1 vote
1 answer
2k views

Find a formula, in terms of n and k , for the number of leaves of G.

Let G be a tree having n n vertices. Suppose that every vertex in G which is not a leaf has degree k, where k > 1 . Find a formula, in terms of n and k , for the number of leaves of G. I started ...
primms123's user avatar
  • 151

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