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14 votes
10 answers
3k views

Can you explain to me why this proof by induction is not flawed? (Domain is graph theory, but that is secondary)

Background I am following this MIT OCW course on mathematics for computer science. In one of the recitations they come to the below result: Official solution Task: A planar graph is a graph that can ...
SLLegendre's user avatar
0 votes
0 answers
42 views

Why can we assume a triangulated graph without loss of generality, for proofs of the 4 colour theorem?

In the Wikipedia article about the four colour theorem it is stated First, if planar regions separated by the graph are not triangulated, i.e. do not have exactly three edges in their boundaries, we ...
Sextus Empiricus's user avatar
2 votes
1 answer
113 views

Planar Graph Cycle Proof (boundary walk question)

Prove that if G is a 2-connected plane graph, then the boundary walk of every face of G describes a cycle. What does this question mean by boundary walk? I have tried looking it up but do not quite ...
shrizzy's user avatar
  • 794
1 vote
1 answer
95 views

Lower bounds on the matching number of maximal planar graphs.

I have read the following article in which the authors briefly prove that the lower bound on the matching number of a maximal planar graph is $\frac{n+8}{3}$. Biedl, T., & Wittnebel, J. (2023). ...
licheng's user avatar
  • 2,474
1 vote
0 answers
25 views

Showing that the subgraph induced on the vertices $a \in V(G)$ such that $z(a) \in H$ for a half-plane $H$ is connected.

Let $G$ be a 3-connected planar graph and $z$ a Tutte embedding. A Tutte embedding is defined as the mapping $z:V(G)\to \mathbb{R}^2$ such that i.) there is a face $F$ of the graph $G$ such that $z$ ...
Epsilon Away's user avatar
  • 1,030
3 votes
1 answer
185 views

How can I prove that a cactus graph is planar?

I've been struggling with the following question: Prove that a cactus graph is planar I've worked out something, but I'm not sure if I'm right or wrong: Consider every cycle of the cactus graph ...
Quinten Mortier's user avatar
1 vote
1 answer
224 views

Ultra-Hamiltonian cycle

Ultra-Hamiltonian cycling is defined to be a closed walk that visits every vertex exactly once, except for at most one vertex that visits more than once. Question:- Prove that it is NP-hard to ...
Nitin Kumar Chauhan's user avatar
0 votes
0 answers
424 views

Explanation of proof for planar bipartite graph

I am supposed to prove that a bipartite planar graph has a vertex of degree at most 3. I saw this answer. But I am little bit confused. I do not understand the following part: For planar bipartite ...
Martin N.'s user avatar
  • 149
1 vote
2 answers
590 views

Proof that bipartite planar graph has a vertex of degree at most 3

I'm trying to understand proof that bipartite planar graph has a vertex of degree at most 3. I found this proof: Prove that a bipartite planar graph has a vertex of degree at most 3 . However, I'm not ...
Emanuel's user avatar
  • 69
1 vote
2 answers
202 views

How to show the following for Planar Graphs-Proof Verification

Please tell me where I am wrong: Consider this graph $G$: Show that this graph is not planar. My answer: Let us consider the vertices $\{0,1,2,3,4\}$. Then the sub-graph induced by these vertices is ...
Charlotte's user avatar
  • 1,686
1 vote
5 answers
424 views

How to show that this graph is planar?-Formal Proof

How to show that this graph is planar? I am unable to write a formal proof In the book the answer is given that this graph is planar. Can you kindly say how to prove that this graph has no subgraph ...
Charlotte's user avatar
  • 1,686
0 votes
0 answers
87 views

Are there graphs embeddable on $S^2$ but not on $\mathbb{R}^2$?

The answer is No for finite graphs, of course, via the stereographic projection. But we need a free point on $S^2$ for that to work. Let $\mathfrak{c}$ denote the cardinality of the continuum. I can ...
SK19's user avatar
  • 3,161
9 votes
1 answer
2k views

All 4-connected planar graphs are Hamiltonian-connected

I started reading Thomassen's paper A Theorem on Paths in Planar Graphs, where he proves one of Plummer's conjectures: Every $4$-connected planar graph is Hamiltonian-connected. Context. Recall that ...
Prism's user avatar
  • 11.3k
4 votes
2 answers
339 views

Adding an edge to a maximal planar graph results in topological minors of both $K_5,K_{3,3}$.

I was trying to prove this exercise from Diestel's book: Show that adding a new edge to a maximal planar graph of order at least 6 always produces both a $TK_5$ and a $TK_{3,3}$ subgraph. I used ...
Nell's user avatar
  • 908
0 votes
0 answers
36 views

Regrading segments in planar graphs

I've been reading this paper about linear time planarity testing algorithm. I have a question about two terms authors use throught the whole paper. What is a segment and what is a subsegment? I ...
False Promise's user avatar

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