Skip to main content

Questions tagged [modules]

For questions about modules over rings, concerning either their properties in general or regarding specific cases.

0 votes
0 answers
26 views

rational functions flat over $k[x]$

I was looking at the solution of an exercise, which proved the following statement: The $k[x]$-module $k(x)$ of rational functions for $k$ a field is flat. The solution goes as follows: Let $\phi: N ...
Pastudent's user avatar
  • 870
0 votes
0 answers
24 views

Flat Module from book of NS Gopala Krishnan

I was reading flat modules from book by NS Gopalakrishnan. In starting of faithfully flat algebra the below is written Let $A$ be an $R$-algebra, $M$ and $N$ are $R$-modules. Then homomorphism $\phi_M ...
Swaraj Koley's user avatar
0 votes
0 answers
22 views

First syzygy is unique up to direct summand

Let $R:=K[x_0,...,x_n]$ be the polynomial ring over a field $K$ and $M$ be finitely generated $R$ module. Let $(m_i)_{i=1,...,k}$ be a generating set for $M$. Then we can define the free module $F_0 :=...
Flynn Fehre's user avatar
0 votes
0 answers
35 views

Length and complete decomposability of $(\varphi,\Gamma)$-modules

I am following the following book on Galois representations and $(\varphi,\Gamma)$-modules. Let $p$ be prime and $L$ a finite $\mathbb{Q}_p$ extension. Let $\Gamma= \mathrm{Gal}(L_\infty/L)$ be the ...
farik-amin's user avatar
1 vote
2 answers
55 views

Find the natural number n for which the set $A_n$ has exactly 323 integers

the problem For n a natural number we define $A_n=\{x\in \Bbb R \,|\,\, |x+n+4| \leq 3n-4\}$. The natural number n for which the set $A_n$ has exactly 323 integers is....? my idea i absolutely have ...
IONELA BUCIU's user avatar
2 votes
0 answers
63 views

$\varphi$-modules that are not completely decomposable

Forgive me for I am not an expert in the area, and I fear that this may be a somewhat trivial question - so thank you for your patience! I am reading Brinon-Conrad's notes on $p$-adic Hodge theoy, ...
mathieu_matheux's user avatar
0 votes
0 answers
28 views

Connection between twisted graded modules and twisted sheaves

I came across the definitions of graded twisted modules while reading about the syzygy theorem. In the meantime I also attended an algebraic geometry course where twisted sheaves occured. For both ...
Flynn Fehre's user avatar
1 vote
1 answer
33 views

Number of left ideals in the simple components of groups algebras

Let $G$ be a finite group and $K$ a field with characteristic zero. Suppose $G$ has $m$ irreducible $K$-representation $W_i$ with character $\chi_i$. $KG$ is semisimple algebra, and $$KG=KGe_1 \times \...
khashayar's user avatar
  • 2,307
1 vote
0 answers
12 views

The residue class of a complete set of primitive orthogonal idempotents

I was studying the book Elements of the Representation Theory of Associative Algebras: Volume 1 and this question occurred to me: In page 29, it says that Because $\{e_1,…,e_n\}$ is a complete set of ...
Chestnuto's user avatar
1 vote
1 answer
84 views

Let $R$ be a ring and $M$ a (left) $R$-module.

Let $R$ be a ring and $M$ a (left) $R$-module. (a) Prove that for every $z \in Z(R)$ the set $zM = \{ zm \mid m \in M \}$ is a submodule of $M$. (b) Give an example of a ring $R$ and an idempotent $e \...
Markus's user avatar
  • 45
0 votes
1 answer
50 views

Let $\varphi: K_1 \rightarrow K_2$ be a ring homomorphism and $M$ a left $K_2$-module.

Let $\varphi: K_1 \rightarrow K_2$ be a ring homomorphism and $M$ a left $K_2$-module. (a) Prove that $M$ becomes a left $K_1$-module if we introduce the operation of multiplication by elements from $...
Markus's user avatar
  • 45
0 votes
0 answers
39 views

Free module and finitely generated submodule.

Let $A$ be a commutative ring, $M$ a free $A$-module and $N\subseteq M$ a finitely generated submodule. Prove that there is a Sub-Noetherian Ring $A_0 \subseteq A$, a free $A_0$-submodule $M_0 \...
George's user avatar
  • 549
1 vote
1 answer
52 views

Questions on the $\hom$ Functor and Free Groups

This question arises while learning about the $\hom$ functor. My algebra background is not that strong, so here is my question: Let $G$ be a free group, and let $f\colon G \to G$ be a group ...
Random's user avatar
  • 649
5 votes
1 answer
74 views

Finiteness of a generalization of the class number of a number field

Let $f(x)$ be an irreducible monic integral polynomial with root $\alpha \in \mathbb{C}$. A classical result of Latimer and MacDuffee asserts that there is a bijection between similarity classes of ...
Ben Marlin's user avatar
1 vote
1 answer
73 views

Cohomology group for trivial group

Let $G$ be a group, $A, B$ be a $G$ - modulo. We can define the n-th Cohomology group of $G$ with coefficient in $A$. $$H^n(G,A) =\text{Ext }_G^n(\mathbb{Z},A)$$ And the n-th Homology group of $G$ ...
Kongca's user avatar
  • 94

15 30 50 per page
1
2 3 4 5
��
654