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2 votes
1 answer
45 views

Stone-Cech compactification via lattice ideals of $Coz(X)$

While studying P. T. Johnstone's book Stone Spaces I have come across the following Proposition (Section: 3.3) Where $max C(X)$ is the set of all maximal ideals of $C(X)$ (ring of real-valued ...
Dots_and_Arrows's user avatar
2 votes
1 answer
83 views

The Boolean lattice of a Boolean ring

I am proving that a Boolean Ring is also a Boolean Lattice. I defined $\leq$ as $x\leq y$ when $xy=x$. The supremum is $a+b+ab$, and infimum is $ab$. The Max element is $1$, Min is $0$. I proved that $...
ShishRobot's user avatar
3 votes
1 answer
171 views

What kind of algebra is the lattice of ideals of a ring?

I have been messing around with rings and ideals for the past week or so in an attempt to prove Nakayama's lemma as an exercise. I completely failed to prove the lemma, but I did notice something ...
Greg Nisbet's user avatar
  • 11.9k
5 votes
0 answers
119 views

What is the distributive reflection of the lattice of ideals of a ring?

Let $A$ be a commutative ring and let $L$ be the set of ideals of $A$, partially ordered by inclusion. $L$ is a complete lattice but is not distributive in general. For instance, in the polynomial ...
Zhen Lin's user avatar
  • 90.9k
10 votes
1 answer
279 views

Constructing rings with a specific lattice of ideals.

Let $R$ be a commutative ring with 1. The ideals of $R$ form a lattice with inclusion as order relation. Let me call it the ideal lattice $L(R)$ of $R$. Given an arbitrary lattice $L$, there are some ...
M. Winter's user avatar
  • 30.1k
2 votes
0 answers
92 views

On a necessary condition for being a prime ideal

All rings below are commutative with unity. If $P$ is a prime ideal in a ring $R$, then it has the following property: (*) For every ideal $I,J$ of $R$, $I \cap J \subseteq P \implies I \subseteq P$...
user avatar
2 votes
1 answer
100 views

Proving associativity of a certain binary aperation in any complemented distributive lattice

If, in a Boolean lattice $(X,\vee,\wedge,0,1,')$ (i.e. a complemented distributive lattice), we define $x+y=(x'\wedge y)\vee(x\wedge y')$, is there an elegant way to prove that $(x+y)+z=x+(y+z)$ ...
Daniel Kawai's user avatar
  • 1,017
4 votes
2 answers
220 views

The lattice of annihilator ideals of a ring

The question is about an exercise from the book "Lattice-ordered rings and modules" from Stuart A. Steingberg. This is the exercise 7 from chapter 1, section 2. Let $R$ a ring with no nonzero ...
Daniel Kawai's user avatar
  • 1,017
1 vote
1 answer
80 views

Distributive lattices

I have a question which is in my ring theory lesson. it's under the topic of distributive lattice and I don't know how to prove it. Que: If A is a strongly regular ring, then the principle right ...
Mnik's user avatar
  • 11
2 votes
1 answer
193 views

What algebraic structure best fits the Cantor set?

Let $2^{\Bbb N}$ be the set of infinite binary sequences $\{x_n\}$ where $x_n\in \{0,1\}$ for every $n\in \Bbb N$. I want it to fit the axioms of a known algebraic structure such that the following ...
augustoperez's user avatar
  • 3,226
2 votes
0 answers
37 views

Complete positively ordered rigs (semirings)

A positively ordered rig $A$ is a rig together with a (pre-)order $\leq$ such that: $x\leq y \Rightarrow x + z \leq y +z$ $x\leq y \Rightarrow x\cdot z \leq y\cdot z\,\&\, z\cdot x \leq z\cdot y$ ...
Stefan Perko's user avatar
  • 12.5k
1 vote
2 answers
146 views

Cardinality of the base of a ring of sets

Concretely, my question is: What is the size of the minimal base of a ring of sets? In my understanding the base is the set of elements that can be used to "deduce the rest". E.g., if I have a ring ...
None's user avatar
  • 11
1 vote
1 answer
179 views

Boolean lattices vs boolean rings

Which kinds of theorems about boolean algebras are easier to prove with boolean rings (than with actual boolean lattices)? Give me at least one example, as an answer.
porton's user avatar
  • 5,103
1 vote
1 answer
34 views

How to find an $R$-order $\Lambda$, such that $A=k\Lambda$?

Let $R$ be a Noetherian integral domain with quotient field $k$. An $R$-order $\Lambda$ is a finitely generated torsionless non-zero $R$-module, which is at the same time an $R$-algebra. Why is ...
LSt's user avatar
  • 540
2 votes
1 answer
254 views

Subrings of the product of rings of algebraic integers

Let $K,L$ be a number fields and $\mathcal{O}_K,\mathcal{O}_L$ their rings of algebraic integers, and $n_K=[K:\mathbb Q]$, $n_L=[L:\mathbb Q]$. Suppose that $R$ is a subring of $\mathcal{O}_K\oplus\...
Carlos  I.'s user avatar
  • 409

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