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2 votes
1 answer
34 views

Connection Between Derivations of Finite and Infinite Binomial Expansion

At first when learning the binomial expansion you learn it in the case of working as a shortcut to multiplying out brackets - anti-factorising if you will. In these cases what you are expanding takes ...
0 votes
1 answer
35 views

Binomial identity involving square binomial coefficient [closed]

I want to prove this identity, but I have no idea... Could someone please post a solution? Thank you. $$\sum_{k=0}^{n} \binom{-1/2}{n+k}\binom{n+k}{k}\binom{n}{k}= \binom{-1/2}{n}^2$$ (Maybe -1/2 can ...
3 votes
1 answer
45 views

Steps on solving part b of the bit-string exercise?

This is the exercise: How many bit strings of length $77$ are there such that a.) the bit string has at least forty-six $0$s and at least twenty-nine $1$s, and also the bit string corresponding to ...
2 votes
2 answers
91 views

Compute the value of a double sum

I need some help computing a(n apparently nasty) double sum: $$f(l):=\sum_{j = \frac{l}{2}+1}^{l+1}\sum_{i = \frac{l}{2}+1}^{l+1} \binom{l+1}{j}\binom{l+1}{i} (j-i)^2$$ where $l$ is even. I'm not ...
3 votes
3 answers
65 views

Prove that $\frac{(n + 1)!}{((n + 1) - r)!} = r \sum_{i=r - 1}^{n} \frac{i!}{(i - (r - 1))!}$

I Need Help proving That $$\frac{(n + 1)!}{(n - r + 1)!} = r \cdot \sum_{i=r - 1}^{n} \frac{i!}{(i - r + 1)!}$$ Or in terms of Combinatorics functions: $P_{r}^{n+1} = r \cdot \sum_{i = r-1}^{n} {P_{r-...
6 votes
3 answers
610 views

An identity involving binomial coefficients

Prove the following identity $$\displaystyle \sum_{i+j=m}\frac{(n-1) \binom{ai+n-1}{i} \binom{aj+1}{j}}{(ai+n-1)(aj+1)} = \frac{n\binom{am+n}{m}}{am+n}$$ where $i = 0,1,\cdots,m$ and $m, n$ are ...
3 votes
4 answers
3k views

Binomial coefficients identity: $\sum i \binom{n-i}{k-1}=\binom{n+1}{k+1}$

I am trying to prove $ \sum_{i=1}^{n-k+1} i \binom{n-i}{k-1}=\binom{n+1}{k+1} $ Whichever numbers for $k,n$ I try, the terms equal, but when I try to use induction by n, I fail to prove the ...
1 vote
0 answers
47 views

Find the number of lattice paths weakly under a slope $y = \mu x$

How many lattice paths are there from an arbitrary point $(a,b)$ to another point $(c,d)$ that stay weakly (i.e. it can touch the line) under a slope of the form $y = \mu x$, with $\mu \in \mathbb{N}$?...
0 votes
1 answer
42 views

Binomial coefficient inequality ${n+x \choose x} > {{m+q-x} \choose q-x}$

Let $m,n,q$ be positive integers and $0\leq x\leq q$ where $x$ is an integer. When does the inequality $$ {n +x \choose x} > {{m+q-x} \choose q-x} $$ hold? Using the Hockey-Stick identity, $$ {n+x \...
3 votes
0 answers
162 views

Closed form for $\sum_{k=n}^{2n-1} k(-1)^k \sum_{i=k}^{2n-1} {2n \choose i+1} {i \choose n}$?

I've found this sum: $$S(n) = \sum_{k=n}^{2n-1} k(-1)^k \sum_{i=k}^{2n-1} {2n \choose i+1} {i \choose n}$$ The inner sum is elliptical iirc, but perhaps the double sum has a nice expression. We can ...
2 votes
1 answer
72 views

Express Lucas numbers as a sum of binomial coefficients

So here's the question, prove that $$L_n = \sum_{k=0}^{n} \frac{n}{n-k} \binom{n-k}{k}$$ where $L_n$ is the $n$-th Lucas number. It really resembles the Fibonacci identity: $$F_n = \sum_{k=0}^{n} \...
0 votes
1 answer
33 views

How to upper bound $\sum_{m=2}^{d-1}\binom{n}{d+1+m} n^{-\alpha 2m} $ [closed]

As I'm saying in the title, I am looking for an upper bound (or an identity) for this: $$ \sum_{m=2}^{d-1}\binom{n}{d+1+m} n^{-\alpha 2m} $$ where $\alpha \in [0,\infty)$. Any ideas/suggestions? ...
0 votes
0 answers
34 views

Probability involving identical objects. I am not able to understand how the Ncr formula is being applied below for counting identical objects.

Question: A bag contains 5 identical red coins, 6 identical yellow coins and 8 identical blue coins. If 3 coins are picked up randomly from the bag, what is the probability that there is at least one ...
2 votes
2 answers
64 views

binomial distribution but sometimes the last outcome doesn't matter

Here's the motivation for my question: I'm designing an RPG. To simplify as much as possible, lets say my enemy has $h = 4$ HP and I deal $a = 1$ damage with every attack. However, there's also a $p$ ...
21 votes
6 answers
19k views

How to show that this binomial sum satisfies the Fibonacci relation?

The Binomial Sum $$s_n=\binom{n+1}{0}+\binom{n}{1}+\binom{n-1}{2}+\cdots$$ satisfies the Fibonacci Relation. $$ \mbox{I failed to prove that}\quad \binom{n-k+1}{k}=...

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