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2 votes
1 answer
51 views

Regarding the number of variables in Symmetric Functions

I'm studying Symmetric Functions and I came across a doubt that could be considered stupid but I need clarifications. In the course I'm following we introduced symmetric functions as formal series of ...
Marco Andreoli's user avatar
0 votes
0 answers
14 views

Isometric automorphisms of the ring of symmetric functions

I was trying to understand how special the $\omega$ involution on the ring of symmetric functions $\Lambda$ or $\Lambda^n$ (restriction to $n$ variables, just in case if by some magic, the situation ...
yeetcode's user avatar
  • 143
2 votes
0 answers
22 views

Derivation of the Macdonald operator $D_{n}(X;q,t)$

Since I first encountered Equation (3.2) on p.315 of Macdonald's Symmetric functions and Hall polynomials, I have wanted to know where it comes from. So how does one derive the operator \begin{...
BatsOnASwing's user avatar
4 votes
1 answer
64 views

Can the product of two quasisymmetric functions (that are not symmetric) be symmetric?

Given two quasisymmetric functions (see definition below) that are not symmetric, must their product also not be symmetric? From Stanley's Enumerative Combinatorics 2, recall that a function $f\in \...
ywrht_'s user avatar
  • 83
0 votes
0 answers
107 views

Hall Scalar product calculation: $\langle h_3p_6, s_{(5,4)}\rangle$

This is a problem from an old qualifying exam I am reviewing: Calculate: $\langle h_3p_6, s_{(5,4)}\rangle$ where $\langle \cdot,\cdot \rangle$ is the Hall scalar product defined by $\langle s_\lambda,...
Sawyer Robertson's user avatar
1 vote
1 answer
173 views

Help with an expression of the Schur polynomial

I am reading: https://www2.math.upenn.edu/~peal/polynomials/schur.htm where it says: The Schur polynomial is defined as $$s_\lambda(x_1,...,x_n)=\prod_{1\le i<j\le n}(x_i-x_j)^{-1}\det(x_j^{\...
Bach's user avatar
  • 5,760
8 votes
2 answers
382 views

Proving an identity for complete homogenous symmetric polynomials

Probably everybody knows the expression: $$ \sum_{k_1,k_2\ge0}^{k_1+k_2=k}a_1^{k_1}a_2^{k_2}=\frac{a_1^{k+1}-a_2^{k+1}}{a_1-a_2}, $$ where $a_1\ne a_2$ is assumed. It seems that it can be further ...
user's user avatar
  • 26.7k
1 vote
0 answers
96 views

Murnaghan-Nakayama rule for general dimension of a hook

Let $m,r\in \mathbb{N}, n=rm$. The character of symmetric group $\chi^{\lambda}$ where $\lambda$ is of the from $(k,1^{n-k})$ evaluated at the conjugacy class of $S_{n}$ of the from $(r,\ldots,r)$, ...
GGT's user avatar
  • 1,065
4 votes
2 answers
581 views

What do we mean when we say the Schur functions form a basis.

This has always bugged me. When we are examining symmetric functions (or polynomials if you prefer finitely many variables), we have an easy choice of basis with the monomial symmetric functions. As ...
Apprentice Counter's user avatar
2 votes
1 answer
1k views

nth power symmetric polynomial in terms of Schurs polynomial

The Schur's polynomial forms the basis of the symmetric algebra so does the power symmetric function. nth power symmetric function are the function of the form $\sum_i x_i^n$. Let $\lambda \vdash n$ ...
GGT's user avatar
  • 1,065
1 vote
1 answer
169 views

prove a polynomial identity..

The equation is that $h_m(x_1, \cdots, x_n, a)-h_m(x_1, \cdots, x_n, b)=(a-b)h_{m-1}(x_1, \cdots, x_n, a, b)$ where $h_m$ is a complete homogeneous symmetric polynomial. See and find several ...
mathstock's user avatar
  • 313
6 votes
2 answers
992 views

Properties of the 'forgotten' symmetric polynomials

In I.G. Macdonald "Symmetric Functions and Hall Polynomials" pg.22, the forgotten symmetric functions $f$ are introduced very briefly as the result of applying an involution $\omega$ to the monomial ...
Wouter M.'s user avatar
  • 910
3 votes
0 answers
234 views

Symmetrization of Powersum polynomials

Let $n\in\mathbb{N}$. Then, for $i\in\mathbb{N}$, the $i-$th power sum if defined to be the polynomial $p_i^{(n)}:=\sum_{j=1}^n x_j^i$ in $n$ indeterminates $x_1,x_2,\ldots,x_n$. Then let $\lambda:=(\...
user58248's user avatar