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I´ve tried at least dozen ways to convert DNF to CNF, yet I always end up with something wrong. Here is the DNF: (B ∧ D) ∨ (C ∧ D) ∨ (¬D ∧ ¬B) ∨ (¬D ∧ ¬C) .

Is there someone who can help me with it ?

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Question already answered here Boolean algebra - Converting DNF form to CNF avoid posting duplicate questions or asking for your homework

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  • $\begingroup$ Yes I know about this one, but it's not the same like mine. $\endgroup$
    – AlZiSVK
    Commented Oct 2, 2019 at 12:20
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    $\begingroup$ @AlZiSVK No, not exactly the same ... but at the start of my Answer there, I give several examples of how to use Distribution, and from those examples you can certainly figure out how it works in your case as well. $\endgroup$
    – Bram28
    Commented Oct 2, 2019 at 21:15

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