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Consider a random walk on the integer lattice in the plane. If a “particle” making a random walk arrives at a lattice point $p = (k_1,k_2)$ at the time $t$, then one of the four neighbors $(k_1±1, k_2 )$, $(k_1 , k_2 ± 1)$ of p is selected with equal probability $\frac{1}{4}$ . The particle moves to that neighbor at time $t + 1$. Let $D$ be a region in the plane (a square or a half plane for example), and let $B$ denote its boundary. Let $p$ be a point of $D$, and let $b$ be a boundary point. We’ll denote by $P_p(b)$ the probability that a random walk starting at $p$ exits at $b$, i.e., that $b$ is the first boundary point that is reached.

I was wondering if someone could help me answer some questions if the region in the plane that we are considering is a rectangle.

1) What is the probability that a particle starting at $p$ never reaches the boundary? 2) What is the “exit time”, the expected time for a particle starting at $p$ to reach the boundary? 3) How does the exit time depend on $p$?

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  • $\begingroup$ 1) is easy. There is a nonzero probability that the first $n$ steps will be in the same direction. So if the region is rectangular, there is a nonzero probability that the walk will take you to an edge in the shortest way possible. And so the probability it never reaches the boundary is $0$. $\endgroup$
    – 2'5 9'2
    Commented Feb 18, 2016 at 23:39
  • $\begingroup$ @alex.jordan Could you write me a solution for all 3 questions ? $\endgroup$
    – amir
    Commented Feb 19, 2016 at 0:17
  • $\begingroup$ If someone could help me in any way with questions 2 and 3, that would be much appreciated $\endgroup$
    – amir
    Commented Feb 19, 2016 at 0:59
  • $\begingroup$ I don't see an easy way to answer 2) and 3). I only commented on 1) because it was the only one I see as easy. If I had an answer for 2) and 3) I would probably try for the bounty. $\endgroup$
    – 2'5 9'2
    Commented Feb 19, 2016 at 1:02
  • $\begingroup$ @alex.jordan Do you have maybe a direction that I could follow or things that I coud try ? $\endgroup$
    – amir
    Commented Feb 19, 2016 at 1:13

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