A standard deck of cards contains $52$ cards divided into four suits: the red suits, hearts and diamonds, and the black suits, clubs and spades. Each suit, in turn, is divided in 13 ordered ranks: ace through 10 followed by the face cards jack, queen, and king. The ace can act as either the lowest or highest card in the ranking.
What is the number of $5$-card hands in a $52$-card deck that contain two pairs (i.e., two pairs from different ranks, and a fifth card of a third rank)?
Answer: $\binom {13}{2}{\binom 42}^2 \binom {44}{1}$
Why is $\binom {13}{2}$ a factor in the answer?