5 cards are extracted simultaneously from a standard deck of 32 cards (8 cards for each of the four suits (hearts, diamonds, spades and clubs): 7,8,9,10, Jack, Queen, King, Ace).
How many different ways can you extract 5 cards containing exactly 3 hearts and exactly 2 kings?
The answer of my book is: 1428 different ways, I am not able to achieve this.
first case
The two kings are not either of their hearts.
$\binom{3}{2} = 6$ possibilities ==> The hearts cards that remain are EIGHT !! But the king of hearts must be excluded, otherwise the kings extracts become three !!! So are 7 !!!
$$6 \times \binom{7}{3} = 1260$$
second case
One of the two king of hearts.
6 always possible ==> The hearts cards that remain are SEVEN because it lacks the king of hearts
$$6 \times \binom{7}{2} = 6 \cdot 7 \cdot 6 = 252$$
But $1260 + 252 = 1512 \ne 1428$
What am I doing in the wrong way?
Thank you very much for considering my request.