Find the quotients as algebraic fractions of the following division:
$$\frac{4x^2-8x+3}{4x^2+2x-12}$$
The answer is
$$\frac{2x-1}{2(x+2)}$$
The method that I am applying to solve:
Write what $2$ numbers multiplied give me the far most right number in the numerator, and add, give me the number left to the far most right number in the numerator as the numerator for the new fraction and doing the same for the denominator then cancelling out whichever $2$ numbers i can.
Ex.
- $\frac{x^2 -2x -3}{x^2 -1}$
- $\frac{(x+1)(x-3)}{(x+1)(x-1)}$
- after I cancel out $(x+1)$, I’m left with $\frac{x-3}{x-1}$
I can't find any numbers that both multiply together to get $3$ and add together to get $-8$. i tried simplifying the original fraction then applying the method but i still didn't get the right answer. This method should work because it worked for part a) and b) in the question