I want to design a power supply (buck converter) which converts 9 V to 5 V and supplies it to the LED strip. The LED strip is a basic 1 meter long 70 LEDs/meter WS2812B strip. In my project, I want to set the brightness around 5%.
The problem: I am confused how to size the buck converter. The total current at 100% brightness is around 4.2 A (60mA per LED) but the average is only about 210 mA and the RMS about 900 mA (Imax * sqrt(D)).
The LEDs change brightness by changing the PWM signal. This means, that the ideal current draw would be a 400 Hz square wave with 5% duty cycle. But if you look closer at the strip, every LED has a bypass capacitor. Also, the buck converter has some capacitance (around 40 uF) and I want to place big bulky capacitors parallel to the output, over 1 mF in total.
I want to simulate/calculate how much current gets drawn from the bulk capacitors by the led strip. This is crucial, because I wouldn't need to design my converter for >4.2 A. For now, I have this buck converter from TI: LM60440, Datasheet
Could anyone help with these calculations or help me simulate it in LTspice? Also, does anyone have tips for selecting a buck converter for this application? Low EMI is important for me, frequency spreading is key here.