This is one of those small everyday things that I've always wondered but have always considered too trivial to ask. I decided to in the end because it's interesting to know and would save me a few keystrokes. Apologies in advance if it appears common sense to some, I just wanted to confirm.
The help for CMD's chkdsk lists three switches that imply others:
/F Fixes errors on the disk
/R Locates bad sectors and recovers readable information (implies /F)
/B NTFS only: Re-evaluates bad clusters on the volume (implies /R)
/X Forces the volume to dismount first if necessary. All opened handles to the volume would then be invalid (implies /F).
I know from the final one that /x implies /f, so if I specify /x I don't need to also specify /f.
However, if /b implies /r and /r implies /f, does /b also imply /f? In other words, if I wanted to run chkdsk with all of the above switches (plus the /v for verbose output), would I need to run:
chkdsk PATH /r /b /x /v
...or would chkdsk PATH /b /x /v be sufficient?
