why is printf not called when expected?

Question

This is my Code [Note: I am using Eclipse for C/C++ on Windows Platform]

#include <stdio.h>
#include<stdlib.h>

int main(void) {
    int num;
    printf("Enter a number:\n");
    scanf("%d",&num);
    if(num%2==0)
        printf("Number is Even");
    else
        printf("Number is Odd");
    return EXIT_SUCCESS;
}

Here I have to enter an Integer first only then printf is called... I want to call printf first before I enter an Integer...What am I doing wrong here?

for example this is the output that I get

6
Enter a number:
Number is Even

and expected output is

Enter a number:
6
Number is Even

Answer 1

you can call fflush(stdout) after first printf to print the buffered output. But considering in future if you extend the program with more printfs then adding fflush after every printf will be an overhead. So you can add

setbuf(stdout, NULL)

just before all the printfs. This will make sure no output is buffered and you will see the prints instantaneously.