729

Question: is there a simple sh/bash/zsh/fish/... command to print the absolute path of whichever file I feed it?

Usage case: I'm in directory /a/b and I'd like to print the full path to file c on the command-line so that I can easily paste it into another program: /a/b/c. Simple, yet a little program to do this could probably save me 5 or so seconds when it comes to handling long paths, which in the end adds up. So it surprises me that I can't find a standard utility to do this — is there really none?

Here's a sample implementation, abspath.py:

#!/usr/bin/python
# Author: Diggory Hardy <[email protected]>
# Licence: public domain
# Purpose: print the absolute path of all input paths

import sys
import os.path
if len(sys.argv)>1:
    for i in range(1,len(sys.argv)):
        print os.path.abspath( sys.argv[i] )
    sys.exit(0)
else:
    print >> sys.stderr, "Usage: ",sys.argv[0]," PATH."
    sys.exit(1)
4
  • I would argue that @DennisWilliamson's answer (using -m option) is superior for (usually) being more portable and working with files that don't exist.
    – TTT
    Commented Apr 25, 2014 at 12:11
  • Or Flimm's answer; both are good solutions. Bannier's however answers my original question best.
    – dhardy
    Commented May 8, 2014 at 12:59
  • 3
    OSX users: see this answer
    – Ian
    Commented May 29, 2014 at 19:19
  • Possible duplicate of Bash: retrieve absolute path given relative Commented Jul 5, 2019 at 4:25

24 Answers 24

1030

Use realpath

$ realpath example.txt
/home/username/example.txt
23
  • 193
    +1, very nice program. But note that it is an external command (not a shell built-in) and may not be present in every system by default, i.e. you may need to install it. In Debian it resides in a separate package with the same name. Commented Oct 12, 2010 at 17:22
  • 5
    I added to my path a realpath consisting of: github.com/westonruter/misc-cli-tools/blob/master/realpath Commented Jan 24, 2012 at 1:10
  • 18
    @Dalin: Try installing coreutils. The binary is named grealpath. Commented Feb 4, 2014 at 9:08
  • 9
    This tool was introduced in GNU coreutils 8.15 (in 2012), so it's quite new.
    – marbu
    Commented Feb 6, 2014 at 22:29
  • 7
    @WalterTross, it is available from the coreutils formula via Homebrew. Commented May 5, 2020 at 8:46
381

Try readlink which will resolve symbolic links:

readlink -e /foo/bar/baz
13
  • 66
    I would rather use '-f' instead of '-e' so that we can see absolute path of a nonexistent file.
    – hluk
    Commented Oct 12, 2010 at 14:54
  • 6
    This looks like the simplest to me, while also being portable. readlink is port of the gnu coreutils, so it will be installed on almost any linux distribution, except for some embedded ones.
    – catphive
    Commented Nov 16, 2010 at 0:15
  • 21
    It seems to me that -m is the best option to use. Commented May 21, 2011 at 7:02
  • 2
    @Dalin: /usr/bin/readlink on Mavericks. Or did you mean those options are not found on OS X? It seems to be a stunted BSD version... :p
    – iconoclast
    Commented Jul 24, 2014 at 16:13
  • 17
    @iconoclast Those options aren't available on OSX, and as per the BSD readlink manpage: only the target of the symbolic link is printed. If the given argument is not a symbolic link, readlink will print nothing and exit with an error, so readlink won't work for this purpose on OSX Commented Jan 14, 2016 at 18:53
331
#! /bin/sh
echo "$(cd "$(dirname -- "$1")" >/dev/null; pwd -P)/$(basename -- "$1")"
15
  • 10
    Don't forget to quote all the stuff. If you don't understand why, try your program on a file a b (two spaces between a and b, SO eats one of them). Commented Oct 12, 2010 at 17:27
  • 1
    also try this on "/" it turns into "///"
    – George
    Commented Jun 28, 2012 at 22:12
  • 43
    the only POSIX solution so far that does not require you to write and compile an executable since readlink and realpath are not POSIX Commented Jun 29, 2013 at 12:49
  • 36
    I used function realpath { echo $(cd $(dirname $1); pwd)/$(basename $1); } to make myself a realpath command (currently accepted answer) on OS X. Thanks! Commented Jun 20, 2014 at 19:13
  • 1
    I used this method to define log filenames for scripts: LOG=$(echo $(cd $(dirname $0); pwd)/$(basename $0 .sh).log) Commented Sep 12, 2014 at 13:53
129

Forget about readlink and realpath which may or may not be installed on your system.

Expanding on dogbane's answer above here it is expressed as a function:

#!/bin/bash
get_abs_filename() {
  # $1 : relative filename
  echo "$(cd "$(dirname "$1")" && pwd)/$(basename "$1")"
}

you can then use it like this:

myabsfile=$(get_abs_filename "../../foo/bar/file.txt")

How and why does it work?

The solution exploits the fact that the Bash built-in pwd command will print the absolute path of the current directory when invoked without arguments.

Why do I like this solution ?

It is portable and doesn't require neither readlink or realpath which often does not exist on a default install of a given Linux/Unix distro.

What if dir doesn't exist?

As given above the function will fail and print on stderr if the directory path given does not exist. This may not be what you want. You can expand the function to handle that situation:

#!/bin/bash
get_abs_filename() {
  # $1 : relative filename
  if [ -d "$(dirname "$1")" ]; then
    echo "$(cd "$(dirname "$1")" && pwd)/$(basename "$1")"
  fi
}

Now it will return an empty string if one the parent dirs do not exist.

How do you handle trailing '..' or '.' in input ?

Well, it does give an absolute path in that case, but not a minimal one. It will look like:

/Users/bob/Documents/..

If you want to resolve the '..' you will need to make the script like:

get_abs_filename() {
  # $1 : relative filename
  filename=$1
  parentdir=$(dirname "${filename}")

  if [ -d "${filename}" ]; then
      echo "$(cd "${filename}" && pwd)"
  elif [ -d "${parentdir}" ]; then
    echo "$(cd "${parentdir}" && pwd)/$(basename "${filename}")"
  fi
}
14
  • 2
    @dhardy. Not sure I understand your comment. What is it in the solution proposed here that excludes use from an interactive environment? ... btw, just like all the other alternative answers presented on this page.
    – peterh
    Commented Jan 26, 2014 at 11:39
  • 1
    Neither realpath nor realink is 'a standard Unix utility' so if that's what you were after then you've gone with the wrong answer.
    – peterh
    Commented Feb 4, 2014 at 13:53
  • 6
    I would like to add that realpath comes from coreutils package, which also contains tools such as who, touch or cat. It's quite standar set of GNU tools, so you can be quite sure that this is installed on almost any linux based machine.That said, you are right: there are 2 issues with it: i) you will likely miss it in default install on non GNU unix systems (like OpenBSD) ii) this tools was introduced in version 8.15 (so it's quite new, from 2012), so you will miss it on long term stable systems (like RHEL 6).
    – marbu
    Commented Feb 6, 2014 at 22:22
  • 1
    Well, it seems at least that Continuum Analytics (makers of the Anaconda Python distribution) liked this answer. It is implemented (with a reference linking back here) in their "activate" script, which is used to activate virtual environments created by the conda tool. So… good one!
    – wjv
    Commented Mar 6, 2014 at 11:39
  • 4
    @marbu realpath is not present on Ubuntu 14.04, or on Debian Wheezy. It may become somewhat standard over time, but it's certainly not now. Also note that the OP didn't say anything about linux or GNU. Bash is more widely used than that.
    – mc0e
    Commented Nov 27, 2014 at 11:45
83
$ readlink -m FILE
/path/to/FILE

This is better than readlink -e FILE or realpath, because it works even if the file doesn't exist.

5
  • Nice. This also works on files/directories that do exist but are not symlinks.
    – quietmint
    Commented Dec 30, 2013 at 14:32
  • I do have readlink available on OS X 10.9 (Mavericks), so this this is definitely the best answer here. Commented Mar 10, 2014 at 20:59
  • 6
    @KennethHoste: the -m option is not available on Mavericks.
    – iconoclast
    Commented Jul 24, 2014 at 16:15
  • 4
    Definitely it is not on a DEFAULT OSX installation. Commented Nov 9, 2015 at 13:20
  • works on linux (CentOS) thank you, because realpath did not exist for it
    – jimh
    Commented Mar 25, 2016 at 20:51
80

This relative path to absolute path converter shell function

  • requires no utilities (just cd and pwd)
  • works for directories and files
  • handles .. and .
  • handles spaces in dir or filenames
  • requires that file or directory exists
  • returns nothing if nothing exists at the given path
  • handles absolute paths as input (passes them through essentially)

Code:

function abspath() {
    # generate absolute path from relative path
    # $1     : relative filename
    # return : absolute path
    if [ -d "$1" ]; then
        # dir
        (cd "$1"; pwd)
    elif [ -f "$1" ]; then
        # file
        if [[ $1 = /* ]]; then
            echo "$1"
        elif [[ $1 == */* ]]; then
            echo "$(cd "${1%/*}"; pwd)/${1##*/}"
        else
            echo "$(pwd)/$1"
        fi
    fi
}

Sample:

# assume inside /parent/cur
abspath file.txt        => /parent/cur/file.txt
abspath .               => /parent/cur
abspath ..              => /parent
abspath ../dir/file.txt => /parent/dir/file.txt
abspath ../dir/../dir   => /parent/dir          # anything cd can handle
abspath doesnotexist    =>                      # empty result if file/dir does not exist
abspath /file.txt       => /file.txt            # handle absolute path input

Note: This is based on the answers from nolan6000 and bsingh, but fixes the file case.

I also understand that the original question was about an existing command line utility. But since this seems to be THE question on stackoverflow for that including shell scripts that want to have minimal dependencies, I put this script solution here, so I can find it later :)

10
  • 1
    This doesn't work for directories with spaces, i.e.: $ abspath 'a b c/file.txt' That's because the argument to cd isn't quoted. To overcome this, instead of quoting the entire argument to echo (is there a reason for these quotes?) quote only the path arguments. I.e. replace echo "$(cd ${1%/*}; pwd)/${1##*/}" with echo $(cd "${1%/*}"; pwd)/${1##*/}.
    – george
    Commented Dec 24, 2014 at 11:52
  • 1
    I looked through dozens of half-cocked solutions and this definitely appears to be the most concise and accurate bash-only solution. You could slim it even more by replacing echo "$(cd "$1"; pwd)" with (cd "$1"; pwd). There is no need for echo here.
    – Six
    Commented Mar 26, 2015 at 14:07
  • @Six True, updated. The braces ( ... ) are still needed, so the cd happens in a subshell, as we don't want to change the working directory for any callers of abspath. Commented Mar 27, 2015 at 1:37
  • This is a well thought out answer, but it doesn't work for symbolic links to files, only to directories. So, if you have a script that looks for a config file in the same directory as the script, you can't symlink the script to ~/bin. This is a pretty common practice for tools that are under version control. Commented Jul 1, 2015 at 12:39
  • @BrunoBronosky it works fine for me with symlinks. Do you have an example that does not work? Note that it will return the absolute path (in case of symlinks based on the symlink you pass in), not the "canonical" path, which I would consider having a separate tool/function for that is likely much more difficult to implement in a simple shell function. Commented Jul 1, 2015 at 19:28
28

The find command may help

find $PWD -name ex*
find $PWD -name example.log

Lists all the files in or below the current directory with names matching the pattern. You can simplify it if you will only get a few results (e.g. directory near bottom of tree containing few files), just

find $PWD

I use this on Solaris 10, which doesn't have the other utilities mentioned.

6
  • 1
    i did not grok this comment on the first read; the key point here is that if you give an absolute path to the find command then it will output results in absolute path. so using $PWD is the absolute path of where you are so you get the output as absolute.
    – simbo1905
    Commented Jan 1, 2013 at 19:05
  • 4
    If you rely on PWD, you could simply use $PWD/$filename.
    – jonny
    Commented Apr 24, 2014 at 19:05
  • This approach can be improved with use of -maxdepth 1. Also don't forget about quoting - potential security issues here, depending how you use this.
    – mc0e
    Commented Nov 27, 2014 at 11:57
  • 1
    @jonny: $PWD/$filename fails if $filename is already absolute.
    – mc0e
    Commented Nov 27, 2014 at 11:58
  • This fails if the file name is given as "./filename.txt" (with leading dot and slash). Commented Jul 29, 2015 at 18:15
21

Here's a zsh-only function that I like for its compactness. It uses the ‘A’ expansion modifier — see zshexpn(1).

realpath() { for f in "$@"; do echo ${f}(:A); done }
1
  • 2
    Wow that's an elegant solution!!
    – ShellFish
    Commented Apr 19, 2014 at 11:59
17

If you don't have readlink or realpath utilities than you can use following function which works in bash and zsh (not sure about the rest).

abspath () { case "$1" in /*)printf "%s\n" "$1";; *)printf "%s\n" "$PWD/$1";; esac; }

This also works for nonexistent files (as does the python function os.path.abspath).

Unfortunately abspath ./../somefile doesn't get rid of the dots.

5
  • 1
    Looks portable to me. On the other hand, will break for example on a filename containing a newline. Commented Oct 12, 2010 at 17:31
  • 1
    To improve further, replace echo "$1" with printf "%s\n" "$1" (same with the second echo). echo may interpret backslashes inside its arguments. Commented Oct 12, 2010 at 17:52
  • Again, you're right! Really, the behavior of echo command in zsh is different from bash.
    – hluk
    Commented Oct 12, 2010 at 18:29
  • 1
    Strictly speaking, under POSIX behaviour of echo is undefined if arguments contain backslashes. However, it is defined under XSI extension (namely, echo should interpret the escape sequences). But both bash and zsh are soo far even from POSIX compliance... Commented Oct 12, 2010 at 19:58
  • Sorry, but I don't see the point. I already provided an answer as a script with more features that this and it doesn't need to be used within a shell script.
    – dhardy
    Commented Oct 13, 2010 at 15:43
11

There is generally no such thing as the absolute path to a file (this statement means that there may be more than one in general, hence the use of the definite article the is not appropriate). An absolute path is any path that start from the root "/" and designates a file without ambiguity independently of the working directory.(see for example wikipedia).

A relative path is a path that is to be interpreted starting from another directory. It may be the working directory if it is a relative path being manipulated by an application (though not necessarily). When it is in a symbolic link in a directory, it is generally intended to be relative to that directory (though the user may have other uses in mind).

Hence an absolute path is just a path relative to the root directory.

A path (absolute or relative) may or may not contain symbolic links. If it does not, it is also somewhat impervious to changes in the linking structure, but this is not necessarily required or even desirable. Some people call canonical path ( or canonical file name or resolved path) an absolute path in which all symbolic links have been resolved, i.e. have been replaced by a path to whetever they link to. The commands realpath and readlink both look for a canonical path, but only realpath has an option for getting an absolute path without bothering to resolve symbolic links (along with several other options to get various kind of paths, absolute or relative to some directory).

This calls for several remarks:

  1. symbolic links can only be resolved if whatever they are supposed to link to is already created, which is obviously not always the case. The commands realpath and readlink have options to account for that.
  2. a directory on a path can later become a symbolic link, which means that the path is no longer canonical. Hence the concept is time (or environment) dependent.
  3. even in the ideal case, when all symbolic links can be resolved, there may still be more than one canonical path to a file, for two reasons:
    • the partition containing the file may have been mounted simultaneously (ro) on several mount points.
    • there may be hard links to the file, meaning essentially the the file exists in several different directories.

Hence, even with the much more restrictive definition of canonical path, there may be several canonical paths to a file. This also means that the qualifier canonical is somewhat inadequate since it usually implies a notion of uniqueness.

This expands a brief discussion of the topic in an answer to another similar question at Bash: retrieve absolute path given relative

My conclusion is that realpath is better designed and much more flexible than readlink. The only use of readlink that is not covered by realpath is the call without option returning the value of a symbolic link.

15
  • I do not mind being downvoted, but I like to understand why so that I can learn something, either technical or regarding what is considered proper practice on the site. Well ... at least it induced me to register with Meta Stack Overflow to better understand local sociology. I do recommend it. -- Still, if anyone has an opinion about the inappropriateness of my answer, I am interested.
    – babou
    Commented May 20, 2013 at 15:35
  • 1
    (a) the question has a valid answer from 2+1/2 years ago, (b) there is a (single) absolute path corresponding to a relative path (which is what I wanted), though maybe not to a file as you pointed out. BTW any comments about realpath vs readlink or even about symbolic links are surplus to what I asked.
    – dhardy
    Commented May 28, 2013 at 18:56
  • 1
    Second comment: short answers are very often more useful than long lectures. Stack overflow is usually used to ask specific questions.
    – dhardy
    Commented May 28, 2013 at 18:58
  • 6
    1- the fact that a question has had a valid answer for however long does not mean that it is closed. The questions are not intended for personnal use only. Indeed, there are badges for replies that collect more votes than the validated answer. And with new tools, the "best" answer can change over time. Many people use old answers accessed through web search.
    – babou
    Commented May 29, 2013 at 11:58
  • 1
    2 - You insist that there is a (single) absolute path corresponding to a relative path. While I do guess what you mean by "corresponding", i.e. a path derived from the original through a given set of transformations, your statement is still incorrect. There is a unique "corresponding" canonical path. The word canonical refers precisely to this uniqueness relative to a set of transformations. But, for example, /dev/cdrom is a perfectly good absolute path, even though it is actually a link to /dev/sr0. Both point to the same device. My original answer pointed to a relevant web article.
    – babou
    Commented May 29, 2013 at 11:58
9

The simplest if you want to use only builtins is probably:

find `pwd` -name fileName

Only an extra two words to type, and this will work on all unix systems, as well as OSX.

4
  • I would add -maxdepth 1 before -name (supposing the file is in the current directory). Without that it will work with files in any subdirectory of pwd, but not with others. Commented May 4, 2020 at 15:01
  • Indeed you are right, the question did specify that the file would be in the current directory. What do you mean "but not with others"?
    – Arj
    Commented May 6, 2020 at 8:47
  • I mean find won't find a file outside the directory tree underneath pwd. E.g., if you try to find . -name ../existingFile, it fails. Commented May 6, 2020 at 13:40
  • Fair enough, yes this'd assume your'e wanting to print the full path of a file in your cwd (as per original question), or anywhere in your cwd tree (not in original question).
    – Arj
    Commented May 12, 2020 at 15:29
6

The dogbane answer with the description what is coming on:

#! /bin/sh
echo "$(cd "$(dirname "$1")"; pwd)/$(basename "$1")"

Explanation:

  1. This script get relative path as argument "$1"
  2. Then we get dirname part of that path (you can pass either dir or file to this script): dirname "$1"
  3. Then we cd "$(dirname "$1") into this relative dir and get absolute path for it by running pwd shell command
  4. After that we append basename to absolute path: $(basename "$1")
  5. As final step we echo it
6

Answer with Homebrew

realpath is the best answer, but if you don't have it installed, you must first run brew install coreutils which will install coreutils with lots of awesome functions. Writing a custom function and exporting it is too much work and risk for error for something like this, here are two lines:

$ brew install coreutils
$ realpath your-file-name.json 
2
  • realpath resolves symlinks
    – balupton
    Commented Sep 26, 2021 at 18:21
  • @balupton in newer versions of realpath, one can use realpath --no-symlinks <file> if they want the full path to a file without resolving symlinks (as you pointed out, they are resolved by default). I'm on Fedora 35 right now and confirm GNU realpath v8.32 supports this. Might be in older versions too; I did not test on any Debian-based distros / research when the option was added. Also did not test BSD versions so no clue for Mac / OpenBSD / etc. So in terms of Mac/homebrew, you would need the gnu coretools for this.
    – zpangwin
    Commented Nov 14, 2022 at 21:48
6

The top answers in this question may be misleading in some cases. Imagine that the file, whose absolute path you want to find, is in the $PATH variable:

# node is in $PATH variable
type -P node
# /home/user/.asdf/shims/node
cd /tmp
touch node  # But because there is a file with the same name inside the current dir check out what happens below
readlink -e node
# /tmp/node
readlink -m node
# /tmp/node
readlink -f node
# /tmp/node
echo "$(cd "$(dirname "node")"; pwd -P)/$(basename "node")"
# /tmp/node
realpath node
# /tmp/node
realpath -e node
# /tmp/node

# Now let's say that for some reason node does not exist in current directory
rm node
readlink -e node
# <nothing printed>
readlink -m node    
# /tmp/node         # Note: /tmp/node does not exist, but is printed
readlink -f node
# /tmp/node         # Note: /tmp/node does not exist, but is printed
echo "$(cd "$(dirname "node")"; pwd -P)/$(basename "node")"
# /tmp/node         # Note: /tmp/node does not exist, but is printed
realpath node
# /tmp/node         # Note: /tmp/node does not exist, but is printed
realpath -e node
# realpath: node: No such file or directory

Based on the above I can conclude that: realpath -e and readlink -e can be used for finding the absolute path of a file, that we expect to exist in current directory, without result being affected by the $PATH variable. The only difference is that realpath outputs to stderr, but both will return error code if file is not found:

cd /tmp
rm node
realpath -e node ; echo $?
# realpath: node: No such file or directory
# 1
readlink -e node ; echo $?
# 1

Now in case you want the absolute path a of a file that exists in $PATH, the following command would be suitable, independently on whether a file with same name exists in current dir.

type -P example.txt
# /path/to/example.txt

# Or if you want to follow links
readlink -e $(type -P example.txt)
# /originalpath/to/example.txt

# If the file you are looking for is an executable (and wrap again through `readlink -e` for following links )
which executablefile
# /opt/bin/executablefile

And a, fallback to $PATH if missing, example:

cd /tmp
touch node
echo $(readlink -e node || type -P node)
# /tmp/node
rm node
echo $(readlink -e node || type -P node)
# /home/user/.asdf/shims/node
2

For directories dirname gets tripped for ../ and returns ./.

nolan6000's function can be modified to fix that:

get_abs_filename() {
  # $1 : relative filename
  if [ -d "${1%/*}" ]; then
    echo "$(cd ${1%/*}; pwd)/${1##*/}"
  fi
}
4
  • 1
    Welcome to SO! For small changes and remarks, adding a comment to an existing answer might be more appropriate than adding an answer, especially if this copied answer lacks a lot of the other information of the original answer. Once you've collected a bit more reputation, you are able to add comments to other people's answers. For now, try to collect reputation by asking unique, valuable questions or providing stand alone, good answers.
    – cfi
    Commented Mar 21, 2014 at 8:16
  • 1
    Since you are referring to nolan6000's answer, please note that the poster dhardy already commented that he would not accept nolan6000's answer because he is not looking for a script. So strictly speaking your answer does not answer the question.
    – cfi
    Commented Mar 21, 2014 at 8:17
  • the function can be added to .profile and hence available for interactive use.
    – adib
    Commented Mar 19, 2015 at 6:19
  • This won't work if $1 is a plain filename: get_abs_filename foo -> nothing (or <current_dir>/foo/foo if foo is a directory). Commented Nov 8, 2018 at 14:05
2

This is not an answer to the question, but for those who does scripting:

echo `cd "$1" 2>/dev/null&&pwd||(cd "$(dirname "$1")";pwd|sed "s|/*\$|/${1##*/}|")`

it handles / .. ./ etc correctly. I also seems to work on OSX

2

I have placed the following script on my system & I call it as a bash alias for when I want to quickly grab the full path to a file in the current dir:

#!/bin/bash
/usr/bin/find "$PWD" -maxdepth 1 -mindepth 1 -name "$1"

I am not sure why, but, on OS X when called by a script "$PWD" expands to the absolute path. When the find command is called on the command line, it doesn't. But it does what I want... enjoy.

1
  • $PWD always has the working directory's absolute path. Also, find won't tolerate slashes, so you're not answering the question as asked. A quicker way to do what you're looking to do would simply be echo "$PWD/$1"
    – Adam Katz
    Commented Dec 20, 2018 at 22:46
2

In zsh, yes there is.

Assuming your path is stored in a variable, you can use the :P modifier to get the absolute path of the file.

Example:

f='../example.txt'
echo ${f:P}

The above will print the absolute path of ../example.txt.

You can alternatively use the :A modifier to further resolve symbolic links, but this depends on realpath being installed.

f='../example.txt'
echo ${f:A}

See https://zsh.sourceforge.io/Doc/Release/Expansion.html#Modifiers

1
#! /bin/bash

file="$@"
realpath "$file" 2>/dev/null || eval realpath $(echo $file | sed 's/ /\\ /g')

This makes up for the shortcomings of realpath, store it in a shell script fullpath. You can now call:

$ cd && touch a\ a && rm A 2>/dev/null 
$ fullpath "a a"
/home/user/a a
$ fullpath ~/a\ a
/home/user/a a
$ fullpath A
A: No such file or directory.
2
  • What does it solve? realpath "foo bar" -> /home/myname/foo bar . If you can't be bothered to quote command line arguments, that's not realpath's fault. Commented Nov 8, 2018 at 14:15
  • Agreed, it's more of a convenience wrapper.
    – ShellFish
    Commented Nov 21, 2018 at 5:57
1

An alternative to get the absolute path in Ruby:

realpath() {ruby -e "require 'Pathname'; puts Pathname.new('$1').realpath.to_s";}

Works with no arguments (current folder) and relative and absolute file or folder path as agument.

1

The answer of Alexander Klimetschek is okay if your script may insist on a bash or bash compatible shell being present. It won't work with a shell that is only POSIX conforming.

Also when the final file is a file in root, the output will be //file, which is not technically incorrect (double / are treated like single ones by the system) but it looks strange.

Here's a version that works with every POSIX conforming shell, all external tools it is using are also required by the POSIX standard, and it explicitly handles the root-file case:

#!/bin/sh

abspath ( ) {
    if [ ! -e "$1" ]; then
        return 1
    fi

    file=""
    dir="$1"
    if [ ! -d "$dir" ]; then
        file=$(basename "$dir")
        dir=$(dirname "$dir")
    fi

    case "$dir" in
        /*) ;;
        *) dir="$(pwd)/$dir"
    esac
    result=$(cd "$dir" && pwd)

    if [ -n "$file" ]; then
        case "$result" in
            */) ;;
             *) result="$result/"
        esac
        result="$result$file"
    fi

    printf "%s\n" "$result"
}

abspath "$1"

Put that into a file and make it executable and you have a CLI tool to quickly get the absolute path of files and directories. Or just copy the function and use it in your own POSIX conforming scripts. It turns relative paths into absolute ones and returns absolute ones as is.

Interesting modifications:

If you replace the line result=$(cd "$dir" && pwd) with result=$(cd "$dir" && pwd -P), then all symbolic links in the path to the final file are resolved as well.

If you are not interested into the first modification, you can optimize the absolute case by returning early:

abspath ( ) {
    if [ ! -e "$1" ]; then
        return 1
    fi

    case "$1" in
        /*)
            printf "%s\n" "$1"
            return 0
    esac

    file=""
    dir="$1"
    if [ ! -d "$dir" ]; then
        file=$(basename "$dir")
        dir=$(dirname "$dir")
    fi

    result=$(cd "$dir" && pwd)

    if [ -n "$file" ]; then
        case "$result" in
            */) ;;
            *) result="$result/"
        esac
        result="$result$file"
    fi

    printf "%s\n" "$result"
}

And since the question will arise: Why printf instead of echo?

echo is intended primary to print messages for the user to stdout. A lot of echo behavior that script writers rely on is in fact unspecified. Not even the famous -n is standardized or the usage of \t for tab. The POSIX standard says:

A string to be written to standard output. If the first operand is -n, or if any of the operands contain a character, the results are implementation-defined.
- https://pubs.opengroup.org/onlinepubs/9699919799/utilities/echo.html

Thus whenever you want to write something to stdout and it's not for the purpose of printing a message to the user, the recommendation is to use printf as the behavior of printf is exactly defined. My function uses stdout to pass out a result, this is not a message for the user and thus only using printf guarantees perfect portability.

1

in bash this:

ls -d "$(pwd)/the-file"

works also with wild card

ls -d "$(pwd)"/*.ts

2
  • I needed to add quotes for directories with spaces. The following worked for me: ls -d "$(pwd)"/*
    – joon
    Commented Apr 11 at 10:47
  • 1
    @joon you'r right (I don't put space in file-path so I forgot this)
    – jo_
    Commented Apr 15 at 9:51
0

I use the single line

(cd ${FILENAME%/*}; pwd)

However, this can only be used when $FILENAME has a leading path of any kind (relative or absolute) that actually exists. If there is no leading path at all, then the answer is simply $PWD. If the leading path does not exist, then the answer may be indeterminate, otherwise and the answer is simply ${FILENAME%/*} if the path is absolute.

Putting this all together I would suggest using the following function

function abspath() {
  # argument 1: file pathname (relative or absolute)
  # returns: file pathname (absolute)
  if [ "$1" == "${1##*/}" ]; then # no path at all
    echo "$PWD"
  elif [ "${1:0:1}" == "/" -a "${1/../}" == "$1" ]; then # strictly absolute path
    echo "${1%/*}"
  else # relative path (may fail if a needed folder is non-existent)
    echo "$(cd ${1%/*}; pwd)"
  fi
}

Note also that this only work in bash and compatible shells. I don't believe the substitutions work in the simple shell sh.

-1

Hey guys I know it's an old thread but I am just posting this for reference to anybody else who visited this like me. If i understood the question correctly, I think the locate $filename command. It displays the absolute path of the file supplied, but only if it exists.

1
  • 5
    locate is a utility to search for files/paths by name. It may do the job but may also find other matches and may not find an existing file without calling updatedb as root first.
    – dhardy
    Commented Dec 5, 2014 at 18:17

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