21

I have a class for local use only (i.e., its cope is only the c++ file it is defined in)

class A {
public:
    static const int MY_CONST = 5;
};

void fun( int b ) {
    int j = A::MY_CONST;  // no problem
    int k = std::min<int>( A::MY_CONST, b ); // link error: 
                                            // undefined reference to `A::MY_CONST` 
}

All the code reside in the same c++ file. When compiling using VS on windows, there is no problem at all.
However, when compiling on Linux I get the undefined reference error only for the second statement.

Any suggestions?

11
  • Don't specify function template arguments. Just std::min(A::MY_CONST, b), it's cleaner.
    – Kerrek SB
    Commented Jun 6, 2013 at 8:46
  • @KerrekSB - in general you are right. I modified this example from my code. There b was not int and therefore I needed to explicitly specify the template argument.
    – user2379182
    Commented Jun 6, 2013 at 8:51
  • 2
    How did you build this? I cannot reproduce the problem with gcc 4.7.3. Commented Jun 6, 2013 at 8:55
  • 1
    Compiles just fine: ideone.com/2LlrHt
    – djf
    Commented Jun 6, 2013 at 8:56
  • 1
    "I modified this example from my code." => But did you check at least that you actually get the posted error with your posted code? (I ask because I can't reproduce the error.)
    – gx_
    Commented Jun 6, 2013 at 8:57

6 Answers 6

26

std::min<int>'s arguments are both const int&(not just int), i.e. references to int. And you can't pass a reference to A::MY_CONST because it is not defined (only declared).

Provide a definition in the .cpp file, outside the class:

class A {
public:
    static const int MY_CONST = 5; // declaration
};

const int A::MY_CONST; // definition (no value needed)
6
  • @djf Indeed, maybe that's why I couldn't actually reproduce the error. (But I still think it avoids potential problems to always provide a definition; if not needed the compiler will strip it out anyway. If you want to prevent taking its address you can just use the old enum trick.)
    – gx_
    Commented Jun 6, 2013 at 9:03
  • For completion static const int are treated differently than other data types, see this answer.
    – user2379182
    Commented Jun 6, 2013 at 9:05
  • Isn't MY_CONST defined when you assign it 5? You mean it is "declared to be 5" versus "defined to be 5"? Commented Mar 22, 2016 at 17:09
  • this is the best solution. the suggestion of definition with value only may not fit some situations that value of MY_CONST appears in declaration of other members.
    – ZFY
    Commented Apr 6, 2018 at 14:39
  • This isn't very satisfying. std::min of constant expressions should be evaluated at compile time; if the compiler can't figure out how to do that using static const members, then I'd say static const members aren't ready for prime time and #define MY_CONST 5 is preferable.
    – Don Hatch
    Commented Feb 2, 2019 at 3:46
6
// initialize static constants outside the class

class A {
public:
    static const int MY_CONST;
};

const int A::MY_CONST = 5;

void fun( int b ) {
    int j = A::MY_CONST;  // no problem
    int k = std::min<int>( A::MY_CONST, b ); // link error: 
                                            // undefined reference to `A::MY_CONST` 
}
1
  • This solves the problem because it provides a definition. The original code would also work if there was a definition, just like the one here but without the initializer. Commented Jun 6, 2013 at 17:57
4

To explain what's happening here:

You declared static const integer inside class, this "feature" is here to be able to use it as constant expression,i.e. for local array size, template non-type parameters, etc.. If compiler wants to use this constant expression it must be able to see it's value in that translation unit.

9.5/3

If a non-volatile const static data member is of integral or enumeration type, its declaration in the class definition can specify a brace-or-equal-initializer in which every initializer-clause that is an assignment expression is a constant expression (5.19). A static data member of literal type can be declared in the class definition with the constexpr specifier; if so, its declaration shall specify a brace-or-equal-initializer in which every initializer-clause that is an assignment-expression is a constant expression. [ Note: In both these cases, the member may appear in constant expressions. — end note ] The member shall still be defined in a namespace scope if it is odr-used (3.2) in the program and the namespace scope definition shall not contain an initializer.

odr-used means to form reference to that variable or take it's address.

std::min takes it's parameters by reference, so they are odr-used.

Solution:

Define it!

class A
{
    static const int a = 5;
};

const int A::a; //definition, shall not contain initializer
2

You can also save the const value to a local variable.

class A {
public:
    static const int MY_CONST = 5;
};

void fun( int b ) {
    int j = A::MY_CONST;  // no problem
    int k = std::min<int>( A::MY_CONST, b ); // link error: undefined reference to `A::MY_CONST` 
    int l = std::min<int>( j, b);  // works
}
0

I am having a very strange situation

template<class T> class Strange {

public:
  static const char gapchar='-';
  };

template<class T> void Strange<T> method1 {
      char tmp = gapchar;
}

template<class T> void Strange<T> method2 {
    char tmp = gapchar;
}

I include the above class, it has been working for several years.

I added another method, essentially the same signature and just reading the gapchar.

I got undefined error only for the third method, even I am using all three methods.

Then I changed the way I initialize the static variable by

not initializing in the class definition:

static const char gapchar;

template<class T> const char Strange<T>::gapchar='-';

This solved the problem. I could not figure out why the old way of initializing int or char type (the only two types allowed) inside the class definition section stop working for only one of the methods but not others.

0

If you are using some header-only thing and want to avoid having to add a .cpp file, it seems like you can do this:

class A {
public:
    static inline const int MY_CONST = 5;
};

(or `static inline constexpr`)

This requires C++17