Seven 2s with seven math operations

Question

Linked to A four digit number using exact same 4 digits

A number with same repeated digits is called a Repdigit or Monodigit number https://en.wikipedia.org/wiki/Repdigit

Can you write an equation for the 7 digit Repdigit number 2222222 using only the digit 2 and its Repdigit numbers (EXCEPT the original number 2222222) and the following seven math operations:

+ - / * ! ^ and square-root

The seven math operations must be used exactly once.

Order of the math operations not important.

The RHS of the equation can only show Repdigit numbers of 2, including 2, but not 2222222.

Bonus: Can you create a general equation for the number 2222... that has "n" 2s and n>2?

Answer 1

If I've interpreted correctly then I think the following would work

$$\sqrt{2^2}+ 222222 *\left(\frac{22-2}{2!}\right) = 2222222$$

which generalises as follows

$$\sqrt{2^2}+ 22\ldots 2 *\left(\frac{22-2}{2!}\right) = 22\ldots 2$$

and if you are being strict about parentheses then perhaps we can change it to the following

$$2+ 222222 *\sqrt{\frac{22-2}{2!}}^2 = 2222222$$

Answer 2

My solution is on the same theme as @hexomino's solution but a bit simpler, I think

2222222 = 222222*22/2 - 222222 + sqrt2^2!

2222222 = 2444442 - 222220

Generically

2222...to"n" = 2222... to "n-1" *22/2 - 2222..to "n-1" + sqrt2^2! n >2

I have of course accepted @hexomino's answer