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Why won't there be any transfer of heat energy when ice at 0°C is in contact with water at 0°C in a closed container?

The other answers have hammered quite well that There is no such thing as heat inside a thing; heat is the name for the spontaneous transfer of energy due to temperature differences and so if it is ...
naturallyInconsistent's user avatar
3 votes

Why won't there be any transfer of heat energy when ice at 0°C is in contact with water at 0°C in a closed container?

As others have said, systems don't contain heat but contain internal energy. So, let's pretend your textbook used the correct term. To socratically answer your question -- why there is not heat ...
jwimberley's user avatar
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0 votes

Why won't there be any transfer of heat energy when ice at 0°C is in contact with water at 0°C in a closed container?

If we heat a fraction of a block of ice at 273 K to get some liquid water at the same temperature, and remove the source of heat, the water doesn't "fall" to its previous solid phase, ...
Claudio Saspinski's user avatar
0 votes

Why won't there be any transfer of heat energy when ice at 0°C is in contact with water at 0°C in a closed container?

It seems that the ambiguity here is not so much in physics as it is in mathematical logic. Buckle up! Firstly and most importantly, bravo for your effort to understand your textbook. I appreciate your ...
Saeed's user avatar
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2 votes

Why won't there be any transfer of heat energy when ice at 0°C is in contact with water at 0°C in a closed container?

"If there is no transfer of heat between the two bodies placed in contact, they are said to be at the same temperature, but it doesn't mean that they have equal amount of heat in them." ...
Bob D's user avatar
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2 votes

Why won't there be any transfer of heat energy when ice at 0°C is in contact with water at 0°C in a closed container?

Heat transfer only occurs when there is a temperature difference.The heat flux 'q' s.t by$$\vec q =-\lambda \nabla T$$where $T$ is temperature and '$\lambda$' is coefficient, and if $T$ is same in ...
UnnamedUser's user avatar
0 votes

Why do we say that at boiling point liquid and vapour exist in equilibrium?

What does it mean by 'vapour and liquid exist in equilibrium' and also why do they exist in equilibrium? They exist in a phase equilibrium in which the boiling point is equal to the condensation ...
Stevan V. Saban's user avatar
0 votes

Why do we say that at boiling point liquid and vapour exist in equilibrium?

Vapor and liquid can coexist in a range of temperatures, usually (under standard pressure 1atm), in range $273.15-373.15$K. When increasing temperature mentally (moving horizontally to the right on ...
Ján Lalinský's user avatar
0 votes

Why do we say that at boiling point liquid and vapour exist in equilibrium?

The key ingredient missing from the other discussion here is the concept of chemical equilibrium. You are entirely correct that the boiling temperature is the point at which the vapor pressure of the ...
Matt Hanson's user avatar
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0 votes

Why do we say that at boiling point liquid and vapour exist in equilibrium?

The boiling point of a liquid is the point till which the liquid and gaseous phases can coexist. A dynamic equilibrium is created. At higher temperatures, only one phase dominates. The rate at which ...
Ritesh Nandi's user avatar
0 votes

Is there a phase transition between a gas and plasma?

Plasma as an ionized gas Naïvely, plasma results from ionization of gas molecules. In this sense transition to plasma with increasing temperature is no different from, e.g., thermal dissociation of ...
Roger V.'s user avatar
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0 votes

Can Lee-Yang zeros theorem account for triple point phase transition?

After analyzing the proposal of this question from various aspects, I fear that I have reached a negative answer for the use of the Lee-Yang theorem to study phase equilibria, particularly for the ...
Alfredo Maranca's user avatar
1 vote

At what temperature does flowing water start to freeze?

The flowing does not change the freezing point of water, but it can change how difficult it is for the water to actually reach that temperature. If the air temperature is at, say, $–5 \rm °C$, the ...
RC_23's user avatar
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5 votes

Solid-on-solid models

First, I'd say that the case you describe corresponds to a wetting transition, rather than to a roughening transition: the system goes from a regime of complete wetting (the wall if fully covered by a ...
Yvan Velenik's user avatar
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3 votes

Is non-temperature related Symmetry Breaking possible?

In physics. Symmetry Breaking is related to temperature [...] Symmetry breaking in classical physics More correct way of saying this is that in (classical) physics symmetry breaking is related to a ...
Roger V.'s user avatar
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8 votes

Is non-temperature related Symmetry Breaking possible?

Temperature is not needed to define symmetry breaking. Symmetry breaking simply refers to the loss of some symmetry during the evolution of a system. Given that a system is in a state $A$ that is ...
Javi's user avatar
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1 vote
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Alternative potentials in the context of spontaneous symmetry breaking

Let $V(\phi)$ be the potential for a scalar field $\phi(x)$. The scalar can be real or complex, it can have an arbitrary number of components, the important thing is just that it is a scalar under the ...
11zaq's user avatar
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