8
votes
Is non-temperature related Symmetry Breaking possible?
Temperature is not needed to define symmetry breaking. Symmetry breaking simply refers to the loss of some symmetry during the evolution of a system. Given that a system is in a state $A$ that is ...
- 1,091
5
votes
Solid-on-solid models
First, I'd say that the case you describe corresponds to a wetting transition, rather than to a roughening transition: the system goes from a regime of complete wetting (the wall if fully covered by a ...
- 10.5k
3
votes
Is non-temperature related Symmetry Breaking possible?
In physics. Symmetry Breaking is related to temperature [...]
Symmetry breaking in classical physics
More correct way of saying this is that in (classical) physics symmetry breaking is related to a ...
- 60.3k
3
votes
Accepted
Why won't there be any transfer of heat energy when ice at 0°C is in contact with water at 0°C in a closed container?
The other answers have hammered quite well that
There is no such thing as heat inside a thing; heat is the name for the spontaneous transfer of energy due to temperature differences and so if it is ...
- 9,368
3
votes
Why won't there be any transfer of heat energy when ice at 0°C is in contact with water at 0°C in a closed container?
As others have said, systems don't contain heat but contain internal energy. So, let's pretend your textbook used the correct term.
To socratically answer your question -- why there is not heat ...
- 3,888
2
votes
Why won't there be any transfer of heat energy when ice at 0°C is in contact with water at 0°C in a closed container?
"If there is no transfer of heat between the two bodies placed in
contact, they are said to be at the same temperature, but it doesn't
mean that they have equal amount of heat in them."
...
- 73.7k
2
votes
Why won't there be any transfer of heat energy when ice at 0°C is in contact with water at 0°C in a closed container?
Heat transfer only occurs when there is a temperature difference.The heat flux 'q' s.t by$$\vec q =-\lambda \nabla T$$where $T$ is temperature and '$\lambda$' is coefficient, and if $T$ is same in ...
- 21
1
vote
Accepted
Alternative potentials in the context of spontaneous symmetry breaking
Let $V(\phi)$ be the potential for a scalar field $\phi(x)$. The scalar can be real or complex, it can have an arbitrary number of components, the important thing is just that it is a scalar under the ...
- 1,014
1
vote
At what temperature does flowing water start to freeze?
The flowing does not change the freezing point of water, but it can change how difficult it is for the water to actually reach that temperature.
If the air temperature is at, say, $–5 \rm °C$, the ...
- 9,500
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