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5 votes
1 answer
76 views

$ \pi^0\to \gamma\gamma$ parity conservation

Let's consider the decay process $\pi^0\to \gamma \gamma$. After we spontaneously broke the chiral symmetry of QCD coupled to an abelian gauge field $A^\mu$, we end up with the Goldstone boson ...
Alex's user avatar
  • 357
1 vote
0 answers
77 views

What is the meaning of twist in OPE?

In Operator Product Expansion (such as explained in Peaking) there appear a quantity for an operator called twist, defined to be $d-s$ where $d$ is the scaling dimension of the operator and $s$ is it'...
Fabio Canedo's user avatar
0 votes
0 answers
52 views

Using Compton scattering to derive the deep inelastic cross-section for the parton model

In the second volume of The Quantum theory of Fields, Weinberg provides the inelastic cross-section for the scattering of an electron from a nucleon with four momentum $p$ based on the parton model: $$...
agc's user avatar
  • 163
-1 votes
2 answers
206 views

How exactly does a proton form from quarks? What is the exact sequence and mechanism?

What are the steps that lead to the bonding of two up quarks and one down quark into a proton? For instance, does an up quark "bind" with a down quark in quark-gluon plasma, which then binds ...
xxl's user avatar
  • 29
1 vote
1 answer
81 views

How can I show the following contraction of the electromagnetic field strength and its dual? [closed]

Given the electromagnetic field strength $F^{\mu\nu}$, and its dual $$\tilde{F}^{\mu\nu} =\dfrac{1}{2}\varepsilon^{\mu\nu\alpha\beta}F_{\alpha\beta},$$ how can I show that $$\tilde{F}^{\mu\nu}F_{\nu\...
João Paulo Melo's user avatar
2 votes
0 answers
77 views

Transpose of a matrix element [closed]

A matrix element is just a number. Now, If I have the following matrix element: \begin{equation} \newcommand\bra[1]{\left<{#1}\right|} \newcommand\ket[1]{\left|{#1}\right>} A = \bra{B}\bar{b}\...
Tifa's user avatar
  • 41
0 votes
0 answers
41 views

Structure function in DIS calculation step

There is one step in the calculation that I am not understanting, but there are many things to present so one can understand and help me: i)$k^2$ and $k_T^2$ are small, so can be neglected; ii)$k^\mu=\...
Vinicius Fuckner Linhares's user avatar
2 votes
1 answer
80 views

Is Compton Scattering the "Abelian limit" of $qg \rightarrow qg$?

I have calculated the average over initial and sum over final states of the squared amplitude for both Compton scattering $e^-\gamma \rightarrow e^-\gamma$ (QED) and quark-gluon scattering $qg \...
user4580791's user avatar
2 votes
0 answers
155 views

Can one distinguish QED (or QCD) from QED (or QCD) plus higher field powers?

The Lagrangian of QED is based on minimal coupling; it contains a term proportional to $F_{\mu\nu}F^{\mu\nu}$ for the electromagnetic field. The QED Lagrangian is the simplest Lagrangian with U(1) ...
frauke's user avatar
  • 684
2 votes
1 answer
814 views

Topological theta-term as a background electric/magnetic field?

The topological $\theta$-term in the Schwinger model (1+1-dimensional QED) can be interpreted as a background electric field, as explained in Chapter 7.1.2 of Tong's lecture notes. The same holds true ...
Thomas's user avatar
  • 1,783
2 votes
1 answer
461 views

Why is the fine structure constant the probability for photon emission by a charged particle?

I see in page 31 of Martin, Hanzel "Quarks and Leptons", that the fine structure constant is the probability for photon emission by a charged particle. Also I read from Lubos Motl's answer on this ...
Kim Dong's user avatar
  • 700
3 votes
1 answer
692 views

Wilson Loops and Confinement in QED

In [1] Kenneth G. Wilson proposed a mechanism for confinement using lattice paths what leds him to the concept of Wilson loop. It seems to me that he is using mainly a single abelian field. He says ...
physics_teacher's user avatar
4 votes
0 answers
399 views

Is the physical mass of the electron a gauge invariant quantity?

In Lattice, one cannot calculate gauge non-invariant quantities, such as the quark mass. This is because one averages over the gauge and gets 0. One way to get around the issue is to fix the gauge. ...
Yang's user avatar
  • 41
1 vote
1 answer
171 views

How would the photon having a charge change the electromagnetic interaction?

This question is motivated by my recent foray into Quantum Field Theory. Just to make this clear straight off the bat; I am not suggesting in any way shape or form that the photon has a charge. I am ...
chuckstables's user avatar
1 vote
0 answers
302 views

Radiative correction to the charge form factor $F_1$ in QED

In QED, one can calculate the correction to the form factor $F_2$. To the lowest order, $F_1=1$ and $F_2=0$. At one loop, it is found that $F_2(0)$ receives a non-zero finite correction which is ...
SRS's user avatar
  • 26.8k

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