All Questions
14
questions
0
votes
1
answer
74
views
Could you calculate the force between two NON-PARALLEL, straight current carrying wires?
Just like there are ways to solve for the force between two straight parallel wires, what is the way we could find the force between non-parallel wires?
2
votes
3
answers
417
views
Why is electromotive force in magnetohydrodynamics a vector quantity?
In the mean-field dynamo theory in magnetohydrodynamics, I frequently came across a quantity;
$\langle v'\times B' \rangle$, which is termed as the mean electromotive force. I want to know that why is ...
29
votes
11
answers
6k
views
Is there a more "physically mature" way to think about the right hand rule with electromagnetism?
I've always found using the righthand rule to remember how forces, B-fields, and particle velocities to be intellectually cheating myself a bit. It feels like being able to multiply numbers by using ...
-3
votes
1
answer
63
views
My doubt is regarding the lorentz force
Consider a magnetic field in the positive z direction, and a charge +q moves with a velocity along the positive x direction. How do we know in which direction lorentz force on charge will be acting?
2
votes
3
answers
905
views
Cross product between two vector quantities [closed]
I wish to understand the "why, what, and how" of the vector cross product. Particularly speaking, I'd like to know its interpretation and how it's connected to the area.
Also, what would be ...
-3
votes
1
answer
74
views
Regarding the Lorentz force:
I know that the Lorentz Force law states that:
$\vec{F} = q\vec{E}+q\vec{v} \times \vec{B}$
And then for the magnitude of the force, where $q_2$ is the moving charge:
$E = F/q_2$, and therefore $E =...
2
votes
1
answer
215
views
An absurd consequence of magnetic field as an axial vector
One of the definitions of magnetic field (in free space): Force on magnetic north pole per unit pole.
Magnetic field is an axial vector. So it changes its sign when we use left handed coordinate ...
-1
votes
1
answer
220
views
Resultant effect of orthogonal motion of electric charges
*If two charges are moving uniformly with parallel velocity vectors that are not perpendicular to the line joining the charges, then the net mutual forces are equal and opposite but do not lie along ...
11
votes
4
answers
2k
views
Is it strange that there are two directions which are perpendicular to both field and current, yet the Lorentz force only points along one of them?
By "strange" I mean 'Is there a reason for this, or is it something we accept as a peculiarity of our universe?'
I see no reason why if magnetic field is in the $+x$ direction and a charge's velocity ...
1
vote
1
answer
861
views
Is the force on a magnet between two magnets of same size and strength additive?
Two bar magnets are in line with each other with their north and south poles near but not touching and they are secured in place. A third magnet is placed in the center air gap but perpendicular. Lets ...
0
votes
1
answer
160
views
Vector question on the relation: $\vec{F}=q\vec{E}+q\vec{v}\times\vec{B}$
The force on a charged particle due to electric and magnetic fields is given by $\vec{F}=q\vec{E}+q\vec{v}\times\vec{B}$. If $\vec{E}$ is along the $X$-axis and $\vec{B}$ asking the $Y$-axis, in what ...
1
vote
0
answers
117
views
validity of "law of vector addition of current elements"
In several articles and books, I have read that "the magnetic force on or due to a small element of a circuit is equivalent to two or more of its component elements, provided that the current remains ...
4
votes
3
answers
5k
views
Why is the magnetic force experienced by a current carrying wire perpendicular to the length of the wire?
I don't quite understand why the force is perpendicular, can somebody explain with a magnetic field diagram as to how the perpendicular direction is produced as a result of the interaction of the two ...
56
votes
13
answers
23k
views
Is there an intuitive explanation for why Lorentz force is perpendicular to a particle's velocity and the magnetic field?
The Lorentz force on a charged particle is perpendicular to the particle's velocity and the magnetic field it's moving through. This is obvious from the equation:
$$ \mathbf{F} = q\mathbf{v} \times \...