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1 vote
1 answer
54 views

Tensor equation

What is a valid tensor equation. In the book by Bernard Schutz, it is often argued that a valid tensor equation will be frame invariant. So the conclusions reached by relatively easy calculation done ...
Questioningmind's user avatar
3 votes
2 answers
714 views

Partial derivatives vs Covariant derivatives in polar coordinates

Covariant derivatives take into account for both component and basis changes, thereby applicable for curved spaces - where partial derivatives only take component changes into account - is this ...
Nayeem1's user avatar
  • 1,141
3 votes
2 answers
345 views

Difference and meaning of index the derivative operator

I'm a beginner in this type of math, we are just starting to study it, but I need some clarifications about the meaning and the difference of when we write $$\partial_i \qquad \text{and}\qquad \...
Heidegger's user avatar
  • 361
1 vote
0 answers
244 views

On the definition of the Van Vleck-Morette determinant

Let $M$ be a Riemannian manifold and $\sigma$ the world function. The Van-Vleck-Morette determinant $D$ is defined by $$D(x,x')=\det(-\sigma_{;\mu\nu{}'})$$ Regarding the semi-colon: In chapter $4.1$ ...
Filippo's user avatar
  • 1,801
2 votes
2 answers
281 views

Is the contracted Christoffel symbol a tensor?

The coordinate transformation law (from coordinates x to coordinates y) for the Christoffel symbol is: $$\Gamma^i_{kl}(y)=\frac{\partial y^i}{\partial x^m} \frac{\partial x^n}{\partial y^k} \frac{\...
Tachyon's user avatar
  • 633
2 votes
2 answers
219 views

Confusion about Transforming Christoffel Symbols

I'm trying to understand how transforming Christoffel symbols works. Specifically I'm thinking about the transformation between Schwarzschild and Eddington-Finkelstein coordinates, $$\Gamma^v_{\;vv}=\...
user345249's user avatar
0 votes
1 answer
113 views

Partial differentiation of tensors

We know that $∂x^ρ /∂x^μ = δ^ρ_μ$ Τhen, $∂x_ρ /∂x^μ = η_{ρμ}$ Should be correct, right? Similarly, $\frac{∂x_ρ} {∂x_μ} = δ^μ_ρ$ Also, if $x'^μ = e^α x^μ $, then $∂'_μ$ should be $e^α ∂_μ$ I am new to ...
Korra's user avatar
  • 348
1 vote
2 answers
333 views

Are there differences in notation for the d'Alembert operator?

On Wikipedia the d'Alembert operator is defined as $$\square = \partial ^\alpha \partial_\alpha = \frac{1}{c^2} \frac{\partial^2}{\partial t^2}-\nabla^2 $$ However, my professor uses the notation: $$ \...
Struggling_Student's user avatar
0 votes
3 answers
990 views

Christoffel symbol and covariant derivative

I came across the Christoffel symbols via the geodesic equation, and I understand the extrinsic form and the intrinsic form and can prove that they are identical: extrinsic form: $$\Gamma^{j}_{~ik}=\...
Fuzzy's user avatar
  • 157
4 votes
1 answer
868 views

Explicit expression of gradient, laplacian, divergence and curl using covariant derivatives

For my course in General Relativity I am given the problem to find the expressions for the gradient, laplacian, divergence and curl in spherical coordinates using covariant derivatives. I have tried ...
IKKUHUKKI's user avatar
1 vote
2 answers
519 views

Which derivative to use in the change of metric tensor due to a gauge transformation?

I'm used to calculating the change in the metric due to a gauge transformation in the following way: The gauge transformation up to linear order is \begin{equation} x^\mu \rightarrow x' ^\mu =x^\mu ...
P. C. Spaniel's user avatar
1 vote
2 answers
559 views

Calculate the expression of divergence in spherical coordinates $r, \theta, \varphi$

Hi this is my first question in [Physics.SE] I saw a lot of posts and I liked them. I hope that my question will be answered too. While I'm solving a problem in vector calculus. I recognized that I ...
user avatar
106 votes
4 answers
10k views

Why does nature favour the Laplacian?

The three-dimensional Laplacian can be defined as $$\nabla^2=\frac{\partial^2}{\partial x^2}+\frac{\partial^2}{\partial y^2}+\frac{\partial^2}{\partial z^2}.$$ Expressed in spherical coordinates, it ...
Sam Jaques's user avatar
  • 1,327
4 votes
1 answer
946 views

Why is the absolute gradient of the metric tensor $\nabla_{\alpha} g_{\mu \nu} = 0$ in every coordinate system? [duplicate]

Is there any intuitive explanation for why the absolute gradient of the metric tensor $\nabla_{\alpha} g_{\mu \nu} = 0$ in every coordinate system?
kanizak's user avatar
  • 41
0 votes
2 answers
9k views

What is the derivative of an angle? [closed]

What is the derivative of an angle? I don't understand
Bol Bol Osama Amir's user avatar

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