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0 votes
0 answers
55 views

Math question about point transformations

I am trying to prove the classic problem to showcase Lagrangian's scalar invariant property. Namely, that if you have $x_i = \{ x_1, ...., x_n; t \}$ , you can then represent $L(x_1,....,\dot{x_1},.....
Enrique Segura's user avatar
0 votes
2 answers
285 views

Taylor expansion in derivation of Noether-theorem

In my classical mechanics lecture we derived the Noether-theorem for a coordinate transformation given by: $$ q_i(t) \rightarrow q^{'}_i(t)=q_i(t) + \delta q_i(t) = q_i(t) + \lambda I_i(q,\dot q,t).$$...
Peter Hidor's user avatar
0 votes
3 answers
136 views

Mathematical identity related to d'Alembert's Principle

In Hand & Finch's book on Analytical Mechanics, I came across this mathematical identity Eq. 1.19 in Chapter 1, page 5, which is related to the description of d'Alembert's principle: $$\dot{\vec{...
feedMe's user avatar
  • 113
2 votes
1 answer
3k views

Lagrange equations in a conservative system, understanding $\nabla_i$

For a system of multiple particles with conservative forces: $\mathbf{F}_i = - \nabla_i V$, with $V \equiv V(\mathbf{r}_1,\dots,\mathbf{r}_N)$ the potential in function of the position of the $N$ ...
Zachary's user avatar
  • 265
0 votes
1 answer
656 views

Derivative of Lagrangian with respect to a vector

Sometimes to find an equation of motion, the Lagrangian is derivated with respect to the (position) vector. How can this be possible?
Sam Jefferson's user avatar
1 vote
1 answer
341 views

How come $\frac{d}{dt}\left(\frac{\partial {r_i}}{\partial {q_j}}\right) = \frac{\partial {\dot r_i}}{\partial {q_j}}$ in Lagrangian mechanics? [duplicate]

It is written in the Goldstein's Classical Mechanics text that $$\frac{\mathrm d}{\mathrm dt}\left(\frac{\partial {r_i}}{\partial {q_j}}\right) = \frac{\partial {\dot r_i}}{\partial {q_j}}=\sum_k \...
Sameer Baheti's user avatar
57 votes
7 answers
9k views

Why isn't the Euler-Lagrange equation trivial?

The Euler-Lagrange equation gives the equations of motion of a system with Lagrangian $L$. Let $q^\alpha$ represent the generalized coordinates of a configuration manifold, $t$ represent time. The ...
Trevor Kafka's user avatar
  • 1,826
2 votes
4 answers
1k views

The definition of the hamiltonian in lagrangian mechanics

So going through the "Analytical Mechanics by Hand and Finch". In section 1.10 of the book, the Hamiltonian $H$ is defined as: $$H = \sum_k{\dot{q_k}\frac{\partial L}{\partial \dot{q_k}} -L}.\tag{1.65}...
user avatar
0 votes
2 answers
2k views

Derivation of generalized velocities in Lagrangian mechanics

So I know that: $$r_i = r_i(q_1, q_2,q_3,...., q_n, t)$$ Where $r_i$ represent the position of the $i$th part of a dynamical system and the $q_n$ represent the dynamical variables of the system ($n$ =...
user avatar
1 vote
2 answers
260 views

Order of derivatives in Euler-Lagrange equations

The Euler-Lagrange equations are $$\frac{\mathrm{d}}{\mathrm{d}t} \frac{\partial L}{\partial \dot{q}_i} = \frac{\partial L}{\partial q_i}.\tag{1}$$ Is it equivalent to switch the derivatives on the ...
David Hansen's user avatar
1 vote
2 answers
160 views

Why $\sum\limits_{i} \frac{\partial L}{\partial \dot{q_i}} \dot{q_i} = \sum\limits_{i} \frac{\partial T}{\partial \dot{q_i}} \dot{q_i} = 2T$? [closed]

From Landau and Lifschitz's "Mechanics"; section 6. I understand up to this point $$E \equiv \sum\limits_{i} \dot{q_i}\frac{\partial L}{\partial \dot{q_i}} - L $$ Then the author states: Using ...
Aaaa Bbbb's user avatar
0 votes
2 answers
2k views

Velocity in generalized coordinates

Consider the expression of velocity in generalized coordinates, $\mathbf v = \frac {d \mathbf x}{dt}$, where $\mathbf x = \mathbf x (\mathbf q(t), t)$. We end up with a total derivative, i.e $$\...
Lo Scrondo's user avatar
2 votes
2 answers
188 views

Take derivative to a cross product of two vectors with respect to the position vector [closed]

I'm doing classical mechanics about Lagrange formulation and confused about something about vector differentiation.The Lagrangian is given: $$\mathcal{L}=\frac{m}{2}(\dot{\vec{R}}+\vec{\Omega} \times \...
Bruce's user avatar
  • 103
1 vote
0 answers
258 views

Partial derivative of $v$ w.r.t. $x$ in Lagrangian dynamics [duplicate]

In Lagrangian dynamics, when using the Lagrangian thus: $$ \frac{d}{dt}(\frac{\partial \mathcal{L} }{\partial \dot{q_j}})- \frac{\partial \mathcal{L} }{\partial q_j} = 0 $$ often we get terms such ...
Bea's user avatar
  • 11
1 vote
3 answers
120 views

Lagrange classical relation

I have been studying theoretical mechanics and just now I came cross a formula called "Lagrange classical relation", that is, if we let $q_1$, $q_2$,$\cdot $$ \cdot $$\cdot $, $q _ m$, $t$ be the $...
painday's user avatar
  • 115

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