I have 2 equation describing the alternating amperage $I_1$ and $I_2$. I need to get amount of these amperages.
My equations: $$I_1=10\sin(\omega t+30)$$ $$I_2=20\sin(\omega t-50)$$
How can i make it? I forgot.
Thank you.
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$\begingroup$ Please don't post your homework, if that's what this is. Otherwise, it's unclear to me what you're asking. $\endgroup$– Mark EichenlaubCommented Nov 14, 2010 at 6:28
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$\begingroup$ @shk: do you need to add i1 and i2 and reduce to the shortest form? $\endgroup$– Peter MortensenCommented Nov 14, 2010 at 10:13
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4$\begingroup$ Better always use "current" instead of "amperage", especially on a physics site. $\endgroup$– Peter MortensenCommented Nov 14, 2010 at 10:19
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$\begingroup$ I am not sure what you are really asking here. Do you just want the R.M.S. current? $\endgroup$– NoldorinCommented Nov 14, 2010 at 16:06
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$\begingroup$ What's wrong with "amperage"? dictionary.reference.com/browse/amperage $\endgroup$– endolithCommented Nov 15, 2010 at 17:01
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1 Answer
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I am going to assume that you ask R.M.S. current and will answer that. If you want some other form of answer just clarify the question a bit more and I'll adjust the answer.
To calculate the RMS(Root-Mean-Square) value of a current, you do the following calculation:
$\sqrt{\frac{1}{T} \int_0^T i(t) dt }$
where T is the period of the signal and t is the variable of integration.
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$\begingroup$ Oh let me note that you can apply superposition to add both RMS values up, provided that your circuitry is linear. $\endgroup$– CemCommented Nov 17, 2010 at 12:35