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A capacitor of capacitance C is intially uncharged is connected with a battery of emf ε.Find the heat dissipated in the circuit during charging?How can we apply energy conservation although there are no two diffrent instances of time . the formula of energy conservation where i had doubt is

HEAT GENRATED(LOSS OF ENERGY)=ENERGY SUPPLIED BY BATTERIES - ENERGY CONSUMED BY BATTERIES + ENERY STORED IN CAPACITOR INTIALLY - ENERGY STORED IN CAPACITOR FINALLY

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  • $\begingroup$ The heat generated is equal to the difference between the work done by batteries and the final potential energy of the system of capacitors. Well you can apply first law of thermodynamics. $\endgroup$
    – Shreyansh Pathak
    Commented May 23, 2019 at 6:31
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    $\begingroup$ You have repeated your question twice:-physics.stackexchange.com/questions/481799/… $\endgroup$
    – Shreyansh Pathak
    Commented May 23, 2019 at 6:34
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    $\begingroup$ Please do not ask new questions that are identical to previous ones. If you would like to clarify your original question, use the 'edit' button under the tags to update the question. Doing so will automatically put it in the Reopen queue for users to check if it has improved. $\endgroup$
    – tpg2114
    Commented May 23, 2019 at 10:52

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