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Qmechanic ♦
Qmechanic ♦
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Spontaneous symmetry breaking of U$U(1)$ in superconductivity

In the crystal, infinitesimal translational symmetry breaking makes the phonon, In ferromagnet, time-reversal symmetry breaking makes magnon. I know that in superconductor there is a spontaneous symmetry breaking of U(1)$U(1)$. In the consequence, which kind of quasi-particle is in superconductor? At first, I thought it is Bogoliubov quasi-particles, but it has mass. What's this?

Spontaneous symmetry breaking of U(1) in superconductivity

In the crystal, infinitesimal translational symmetry breaking makes the phonon, In ferromagnet, time-reversal symmetry breaking makes magnon. I know that in superconductor there is a spontaneous symmetry breaking of U(1). In the consequence, which kind of quasi-particle is in superconductor? At first, I thought it is Bogoliubov quasi-particles, but it has mass. What's this?

Spontaneous symmetry breaking of $U(1)$ in superconductivity

In the crystal, infinitesimal translational symmetry breaking makes the phonon, In ferromagnet, time-reversal symmetry breaking makes magnon. I know that in superconductor there is a spontaneous symmetry breaking of $U(1)$. In the consequence, which kind of quasi-particle is in superconductor? At first, I thought it is Bogoliubov quasi-particles, but it has mass. What's this?

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Roger V.
Roger V.
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spontaneous Spontaneous symmetry breaking of U(1) in superconductivity

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iron fist
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spontaneous symmetry breaking of U(1) in superconductivity

In the crystal, infinitesimal translational symmetry breaking makes the phonon, In ferromagnet, time-reversal symmetry breaking makes magnon. I know that in superconductor there is a spontaneous symmetry breaking of U(1). In the consequence, which kind of quasi-particle is in superconductor? At first, I thought it is Bogoliubov quasi-particles, but it has mass. What's this?