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Questions tagged [recurrences]

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4 votes
0 answers
39 views

Can P-recursive functions assume only prime values?

A function $f\colon \{0,1,\dots\}\to \mathbb{R}$ is P-recursive if it satisfies a recurrence $$ P_d(n)f(n+d)+P_{d-1}(n)f(n+d-1)+\cdots+P_0(n)f(n)=0,\ n\geq 0, $$ where each $P_i(n)\in \mathbb{R}[n]$ ...
Richard Stanley's user avatar
0 votes
0 answers
52 views

Closed form for the A357990 using A329369 and generalised A373183

Let $$ \ell(n) = \left\lfloor\log_2 n\right\rfloor, \\ \ell(0) = -1 $$ Let $$ f(n) = \ell(n) - \ell(n-2^{\ell(n)}) - 1 $$ Here $f(n)$ is A290255. Let $A(n,k)$ be a square array such that $$ A(n,k)...
Notamathematician's user avatar
2 votes
1 answer
191 views

Sequences with constant cross-ratio

The cross ratio for four collinear points $\left(A,B,C,D\right)$ is defined as $\frac{(AC)(BD)}{(AD)(BC)}=\frac{(AB+BC)(BC+CD)}{(AB+BC+CD)BC}$ i.e. it is a function of the three lengths $AB,BC,CD$ if ...
Manfred Weis's user avatar
  • 12.8k
3 votes
0 answers
104 views

Sequence that sums up to A014307

Let $s(n,k)$ be a (signed) Stirling number of the first kind. Let $n \brace k$ be a Stirling number of the second kind. Let $a(n)$ be A014307. Here $$ A(x) = \sum\limits_{k=0}^{\infty} \frac{a(k)}{...
Notamathematician's user avatar
8 votes
1 answer
210 views

A recurrence satisfied by a function asymptotic to $n^n$

A function $f\colon \{0,1,\dots\}\to \mathbb{R}$ is P-recursive if it satisfies a recurrence $$ P_d(n)f(n+d)+P_{d-1}(n)f(n+d-1)+\cdots+P_0(n)f(n)=0,\ n\geq 0, $$ where each $P_i(n)\in \mathbb{R}[n]$ ...
Richard Stanley's user avatar
2 votes
1 answer
112 views

Recursion for the sum with Stirling numbers of both kinds

Let $s(n,k)$ be a (signed) Stirling number of the first kind. Let $n \brace k$ be a Stirling number of the second kind. Let $$ f(n,m,i) = (-1)^{m-i+1}\sum\limits_{j=i}^{m+1}j^n s(j,i) {m+1 \brace j}...
Notamathematician's user avatar
2 votes
0 answers
96 views

Another (unique) algorithm for the A329369

Let $a(n)$ be A329369 (i.e, number of permutations of ${1,2,...,m}$ with excedance set constructed by taking $m-i$ ($0 < i < m$) if $b(i-1) = 1$ where $b(k)b(k-1)\cdots b(1)b(0)$ ($0 \leqslant k ...
Notamathematician's user avatar
2 votes
0 answers
101 views

Division based recurrence with negative coefficients, e.g. $F(n)= -F(\lfloor n/2\rfloor) - F(\lfloor n/3\rfloor)$

A famous problem of Erdos dealt with the division-based recurrence $a_n = a_{\lfloor n/2\rfloor}+a_{\lfloor n/3\rfloor}+a_{\lfloor n/6\rfloor}$ with $a_0=1$ (and was about the limit $\lim_{n\to\infty} ...
D.R.'s user avatar
  • 771
1 vote
0 answers
54 views

Simple recursion for the A329369 using Stirling numbers of both kinds

Let $s(n,k)$ be a (signed) Stirling number of the first kind. Let $n \brace k$ be a Stirling number of the second kind. Let $a(n)$ be A329369 (i.e, number of permutations of ${1,2,...,m}$ with ...
Notamathematician's user avatar
1 vote
1 answer
66 views

Questions about Lamperti's criteria for stochastic process recurrence

I'm working through Lamperti's 1960 paper "Criteria for the recurrence or transience of stochastic process. I" (J. Math. Anal. Appl. 1(3–4), 314–330. DOI: 10.1016/0022-247x(60)90005-6) as ...
ZENG's user avatar
  • 113
1 vote
0 answers
66 views

Does the perturbed recurrence of the Least Common Multiple expansion give a sequence asymptotic to $\frac{\sqrt{n N} \log (n)}{\log (N)}$?

The logarithm of the Least common multiple, or $\log(\operatorname{LCM})$, of ${1, 2, \ldots, n} ={}$A003418 can be computed as the infinite series: $$\log(A003418(n)) = \sum_{k \geq 1} \frac{T(n, k)}{...
Mats Granvik's user avatar
  • 1,153
14 votes
1 answer
382 views

Can you "slice" a triangular number into three equal slices?

Problem statement: Does there exist positive integers $a<b<c$ such that $$1 + 2 + \dots + (a-1) = (a+1) + \dots + (b-1) = (b+1) + \dots + c?$$ (Note that $a$ and $b$ are not in the sums.) ...
Benjamin Wang's user avatar
1 vote
0 answers
130 views

Sequence that sums up to A000153

Let $a(n)$ be A329369 (i.e, number of permutations of ${1,2,...,m}$ with excedance set constructed by taking $m-i$ ($0 < i < m$) if $b(i-1) = 1$ where $b(k)b(k-1)\cdots b(1)b(0)$ ($0 \leqslant k ...
Notamathematician's user avatar
3 votes
0 answers
70 views

Recursion for reversed rows of the A373183 using unsigned Stirling numbers of the first kind

Let $\left[{n \atop k}\right]$ be unsigned Stirling numbers of the first kind. Here $$ \left[{n \atop k}\right] = (n-1)\left[{n-1 \atop k}\right] + \left[{n-1 \atop k-1}\right], \\ \left[{n \atop 0}\...
Notamathematician's user avatar
1 vote
0 answers
84 views

Simpler recursion for the A358612

Let $T(n,k)$ be an integer coefficients (A358612) such that $$ T(2n+1, k) = kT(n, k) + T(n, k-1), \\ T(2n, k) = kT(n, k) + T(n, k-1) - \frac{T(2n, k-1) + T(n, k-1)}{k-1}, \\ T(n, 1) = T(0, 2) = 1 $$ ...
Notamathematician's user avatar

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