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17 votes
3 answers
2k views

Are some congruence subgroups better than others?

When I first started studying modular forms, I was told that we can consider any congruence subgroup $\Gamma\subset\operatorname{SL}_2(\mathbb{Z})$ as a level, but very soon the book/lecturer begins ...
Coherent Sheaf's user avatar
2 votes
0 answers
163 views

A direct proof that every projectivity between parallel lines is affine

Definition 1. An affine plane is a pair $(X,\mathcal L)$ consisting of a set $X$ and a family $\mathcal L$ of subsets of $X$ called lines which satisfy the following axioms: Any distinct points $x,y\...
Taras Banakh's user avatar
  • 41.1k
1 vote
0 answers
159 views

Motivic complex on arithmetic schemes

If we believe the finite generation of motivic cohomology for regular arithmetic schemes like $X$ then we can see that (using Quillen-Lichtenbaum)for infinitely many primes $l$ we have an isomorphism ...
user127776's user avatar
  • 5,861
3 votes
0 answers
201 views

Tate isogeny theorem over varieties?

Let $X$ be a nice scheme, $\pi:E\to X$ an elliptic curve, and $\ell$ a prime invertible on $K$. Then we can consider the "Tate module" $(R^1\pi_*\mathbb{Z}_{\ell})^\vee=\hbox{''}\varprojlim\...
Curious's user avatar
  • 341
3 votes
0 answers
115 views

How does the number of connected components of the Néron model change in a family of abelian varieties?

Given an elliptic curve $E/\mathbb{Q}_p$, it is known that the component group of the Néron model of $E$ is cyclic of order $-v(j(E))$ when $E$ has split multiplicative reduction, and in all other ...
Nathan Lowry's user avatar
2 votes
0 answers
249 views

The group of the modular automorphisms of the Shimura curves

Let $B$ be a rational indefinite division quaternion algebra, $(X,G)$ the Shimura datum associated with $B$ (i.e., $X$ is the upper half plane and $G(R) = (B \otimes_\mathbb{Q} R)^*$ for a ring $R/\...
k.j.'s user avatar
  • 1,352
15 votes
2 answers
1k views

How to think of algebraic geometry in characteristic p?

How does a working mathematician usually think about algebraic geometry in characteristic $p$? For the sake of concreteness, and to make things more "geometric" (whatever that means), let's ...
JustLikeNumberTheory's user avatar
5 votes
1 answer
361 views

Fermat cubic hypersurfaces over finite fields

Consider the Fermat cubic $$ X = \{x_0^3+\dots +x_n^3 = 0\}\subset\mathbb{P}^n_{\mathbb{F}_{q}} $$ over a finite field $\mathbb{F}_{q}$ with $q$ elements. If $q \equiv 2 \mod 3$ then the projection $\...
Puzzled's user avatar
  • 8,922
4 votes
1 answer
216 views

Points on affine hypersurface over finite field

I am interested in the hypersurface $X\subset\mathbb{A}^4_{\mathbb{F}_{5^n}}$ defined by $$ X = \{x^3 + 3xy^2 + z^3 + 3zw^2 + 1 = 0\} $$ over a finite field $\mathbb{F}_{5^n}$ with $5^n$ elements. Via ...
Puzzled's user avatar
  • 8,922
4 votes
1 answer
171 views

Primes of bad reductions for quotients of elliptic curves

Let $E$ be an elliptic curve over a number field $K$ and $p$ a prime. Suppose that $E$ has a $K$-rational $p$-torsion, which gives the short exact sequence $0\to\mathbb{Z}/p\to E[p]\to\mu_p\to0$ of ...
User0829's user avatar
  • 1,408
4 votes
2 answers
394 views

$p$-divisibility of Picard groups

Let $p$ be a prime number and let $k$ be a field with $char(k)\neq p$ such that all finite extensions have degree coprime to $p$. (For example, we can take $k=\mathbb{R}$ and $p\neq 2$ or let $k$ the ...
Boaz Moerman's user avatar
1 vote
0 answers
45 views

Weight of adjoint action on a lower central series extension

Let $\mathcal{U}$ be a unipotent Lie $\mathbb{Q}_p$-group scheme, whose associated gradeds from the lower central series filtration are $\mathcal{U}_0 = \mathcal{U}^{\text{ab}}$, $\mathcal{U}_1 = [\...
kindasorta's user avatar
  • 2,113
3 votes
1 answer
234 views

$\mathbf{Z}$-points of quasi-projective schemes

Let $U\subset\mathbf{P}^n_{\mathbf{Z}}$ be an open subscheme such that the smooth morphism $U\to\text{Spec}(\mathbf{Z})$ is surjective. Suppose $U(\mathbf{Q})\neq\varnothing$ and $U(\mathbf{Z}_p)\neq\...
Tim's user avatar
  • 85
1 vote
1 answer
298 views

Cohomology of singular curves

Suppose $X$ is a singular quasi-projective curve over the complex numbers, and $X'$ is a good nonsingular compactification of a resolution of singularities $Y\to X$. Let $D$ be the complement of $Y$ ...
user avatar
2 votes
1 answer
276 views

Geometric Interpretation of absolute Hodge cohomology

$\quad$Let $\mathcal{Sch}/\mathbb C$ denote the category of schemes over $\mathbb C$. For an arbitrary $X\in\mathcal{Ob}(\mathcal{Sch}/\mathbb C)$, Deligne in his Article defined a polarizable Hodge ...
user avatar

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