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Mathematics
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oneneedsanswers
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2
prove that $(0,1)\cap \mathbb{Q}$ is order-isomorphic to $(-\pi,\pi)\cap \mathbb{Q}$
Apr 22, 2022
2
$M$ is smooth compact manifold and $C_0,C_1$ disjoint closed subsets of $M$ so there is exists smooth func $f:M \to [0,1]$ s.t $f(C_0)={0},f(C_1)={1}$
May 7, 2023
2
Given a sequence $a_n$ s.t. forall $\varepsilon>0$ exists $m,n_{0} \in \mathbb{N}$ s.t. $\forall n \geq n_0$ $|a_n-a_m|<\varepsilon$
Feb 16
2
If $F/K$ is normal extension and $f \in K[x]$ irreducible and $f=\prod_{i=1}^{n}g_{i}^{m_{i}}$ in $F[x]$ then $m_{i}=m_{j}$ for all $i,j$
Jun 24
1
Whether $\mathbb{R}^{\mathbb{R}}$ with product topology is first countable or not. [duplicate]
Mar 17, 2023
1
If $F/K$ is normal extension and $f \in K[x]$ irreducible and $f=\prod_{i=1}^{n}g_{i}^{m_{i}}$ in $F[x]$ then $m_{i}=m_{j}$ for all $i,j$
Jun 25
0
a hint for a question: "proof an attribute of $f$ such that it's differentiable at a neighbourhoods of $0$ and $f'$ isn't continuous at $0$.."
Oct 14, 2021
0
If $\sum_{i=0}^{n}e^{\lambda_{i}\cdot t}\cdot q_{i}(t) = 0$ then $q_{i}(t) = 0$ where $q_{i}(t)$ is complex polynomial with real variable $t$.
Jun 8