Skip to main content
Mathematics
jack's user avatar
jack's user avatar
jack's user avatar
jack
  • Member for 9 years, 4 months
  • Last seen more than 3 years ago
Profile Activity
Stats
1,256
reputation
8k
reached
1
answer
17
questions
Communities
Badges
View all badges
This user doesn’t have any gold badges yet.
7
silver badges
22
bronze badges
Top tags
View all tags
2
Score
4
Posts
22
Posts %
2
Score
4
Posts
22
Posts %
0
Score
5
Posts
28
Posts %
0
Score
5
Posts
28
Posts %
0
Score
4
Posts
22
Posts %
0
Score
3
Posts
17
Posts %
Top posts
View all questions and answers
37
On the inequality $ \int_{-\infty}^{+\infty}\frac{(p'(x))^2}{(p'(x))^2+(p(x))^2}\,dx \le n^{3/2}\pi.$
Apr 18, 2015
20
On the inequality $\frac{1+p(1)+p(2) + \dots + p(n-1)}{p(n)} \leq \sqrt {2n}.$
Jul 11, 2015
16
Two sets $X,Y \subset [0,1]$ such that $X+Y=[0,2]$
Jun 6, 2015
12
Infinitely many polygons, no four have a common point
Jan 8, 2016
10
if $|f(n+1)-f(n)|\leq 2001$, $|g(n+1)-g(n)|\leq 2001$, $|(fg)(n+1)-(fg)(n)|\leq 2001$ then $\min\{f(n),g(n)\}$ is bounded
Feb 27, 2015
10
All clubs have a member among $n$ people
May 30, 2015
10
All terms of this sequence are equal to 1: $x_{n+1}= \frac{nx_{n}^2+1}{n+1}$
Jul 1, 2017
7
There are infinitely prime numbers $p$, st $P(x)+p$ is irreducible over $\mathbb{Z}[x]$
Mar 17, 2018
7
Is there any number with $2017$ divisors whose sum of digits is $2017$?
Mar 24, 2018
6
There is no sequence such that $a_{a_n}=a_{n+1}a_{n-1}-a_{n}^2$
Mar 2, 2016
Top network posts
View all network posts
40
The sequence $a_{n+1}=\left\lceil \frac{-1+\sqrt{5}}{2}a_{n}-a_{n-1} \right\rceil$ is periodic
29
All polynomials are the sum of three others, each of which has only real roots
27
$m$-fold composite $p^{(m)}(x) \in \mathbb{Z}[x]$ implies $p(x) \in \mathbb{Z}[x]$
24
If $x_{n+1}= \frac{nx_{n}^2+1}{n+1}$ then $x_{n}=1$
20
Minimum value of $|p(1)|^2+|p(2)|^2 +...+ |p(n+3)|^2$ over all monic polynomials $p$