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-1 votes
0 answers
39 views

Orthonormal basis for $\mathbb{C}^2$ over $\mathbb{R}$ [closed]

$\mathbb{C}^2$ is a 4-dimensional vector space over $\mathbb{R}$ with basis $\left\{\begin{bmatrix} 1 \\ 0 \end{bmatrix}, \begin{bmatrix} i \\ 0 \end{bmatrix}, \begin{bmatrix} 0 \\ 1 \end{bmatrix}, ...
Mark Ren's user avatar
0 votes
0 answers
23 views

Graphical Intuition of a Linear Transformation in terms of Row Vectors

The graphical intuition of a linear transformation (matrix) $A \in \mathbb{R}^{m \times n}$ applied on a vector $\textbf{v}$ in terms of the column vectors $\textbf{c}_i$ of $A$ is quite clear to me: ...
olives's user avatar
  • 1
1 vote
0 answers
103 views

Why is the inner product space defined separately?

While learning about the inner product space, I became curious why it is defined separately? In my opinion, there seems to be no difference between defining the inner product space separately and ...
LACKHOLE's user avatar
0 votes
0 answers
45 views

Manifolds and Euclidean Spaces

This might be a basic question, but it's been irking me for the past few days. The common definition of a manifold is as a second-countable, Haussdorff topoplogical space which is locally homeomorphic ...
markusas's user avatar
  • 358
2 votes
1 answer
52 views

Assume that for every $f\in X^*$, there exists $y \in X$ such that $f(x)=\langle x, y \rangle$ for every $x \in X$. Show that $X$ is a complete space.

Let $(X, \langle \cdot, \cdot \rangle)$ be a real or complex vector space with an inner product. Assume that for every $f \in X^*$, there exists $y \in X$ such that $f(x) = \langle x, y \rangle$ for ...
user avatar
1 vote
1 answer
28 views

Given an inconsistent overdeterminate system AX=b where $A\in M_{m×n}(R)$ and $b\in R^m$ with rank A=n. Find the least square approx. solution of AX=b

Suppose $A$ is a real matrix of order $m\times n$ with $m>n,b\in\Bbb R^m$ be such that the over determined system of linear equations $AX=b$ is inconsistent and $\text{rank} (A)= n.$ Let $W$ be the ...
Thomas Finley's user avatar
0 votes
2 answers
56 views

$\lambda \in \mathbb{C}$ is an eigenvalue of the operator $A$, then $\text{Re}(\lambda) = 0$ AND $H$ is a complex vector space, then $A = iB$.

Let $H$ be a Hilbert space and $A \in B(H)$ such that $A^* = -A$. Prove the following statements: (a) If $H$ is a real vector space, then $\langle Ax, x \rangle = 0$ for every $x \in H$. (b) If $\...
user avatar
0 votes
1 answer
65 views

True or False: Inner product on $\mathbb{R}^2$ satisfying a specific norm.

Verify or refute: There exists an inner product in $\mathbb{R}^2$ such that the norm of every vector $v=(v_1,v_2)$ is $\|v\|=|v_1|+|v_2|$. I think this is untrue. So I took $v=(1,0), y=(0,1)$. After ...
user926356's user avatar
  • 1,494
1 vote
1 answer
74 views

Orthogonal projection is bounded

Definition: Let $U$ be a subspace of $V$. The orthogonal projection of $V$ onto $U$ is the operator $P_U\in L(V)$ given by $$P_U(u+w)=u$$ if $u\in U, w\in U^{\perp}$. Let $V$ be a space with inner ...
user926356's user avatar
  • 1,494
2 votes
1 answer
52 views

Consequences of definition of scalar product

Definition: Let $V$ be a vector space over the field $K=\mathbb{R}$ (or over $K=\mathbb{C})$. The scalar product on $V$ is a function $V\times V\to K,$ denoted by $(x,y)\mapsto \langle x,y\rangle$, ...
user926356's user avatar
  • 1,494
2 votes
3 answers
104 views

Why is $ R(A^*) \perp N(A)$ true?

Let a matrix the $A \in M_{n\times n}(\mathbb{C})$. My question is: (1) Why every matrix $A$ satisfies $ R(A^*) \perp N(A)$(where $R(A),N(A)$ are range of $A$,null space of $A$ respectively)? And why ...
user avatar
0 votes
1 answer
38 views

Projection of vector

The projection of a vector $x$ onto a vector $u$ is $proj_u(x) =\frac{\langle x, u \rangle}{\langle u, u \rangle}u.$ Projection onto $u$ is given by matrix multiplication $proj_u(x)=Px$ where $P=\frac{...
user avatar
1 vote
1 answer
52 views

The inner product of column vectors is the same as matrix multiplication

I am very much new on the topic of inner product: Definition. The inner product of vectors $x, y \in \mathbb{R}^n$ is $\langle x, y\rangle =\sum_{i=1}^{n} x_ky_k=x_1y_1+x_2y_2+\dots+x_ny_n$ I can't ...
user avatar
2 votes
1 answer
38 views

Matrix of an Inner Product and Spectral Theorem

My linear algebra has become very rusty and now I've confused myself entirely. Let $V$ be an inner product space over an $n$-dimensional real vector space $V$. Moreover, let the set of vectors $$\...
Algebro1000's user avatar
0 votes
1 answer
59 views

Orthogonal orthornomal bases imply pair-orthogonal vectors

While self-studying linear algebra i started thinking about following problem: Let's say that $A, B \in \mathbb{C}_{n\times n}$ are orthogonal in a Frobenius sense orthonormal bases of complex vector ...
Freechoice guy's user avatar

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