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Questions tagged [uniform-continuity]

For questions involving the concept of uniform continuity, that is, "the $\delta$ in the definition is independent of the considered point".

1 vote
0 answers
24 views

Finding a function in the unit sphere of a functional subspace with a couple of properties

Preliminaries: A={f $\in C(X); f(a)=0$} is a banach space with norm the following: $\Vert f\Vert=sup\vert f(x)-f(y)\vert; x,y \in X$ ( X is Hausdorff and compact space. 'a' is a point in X) $\tilde f ...
nahid's user avatar
  • 11
4 votes
2 answers
131 views

$\displaystyle \lim_{n \rightarrow +\infty} \dfrac{1}{\log(n)}\sum_{k=1}^n \dfrac{1}{k}f\left(\dfrac{k}{n} \right) = f(0)$

I am working on the following question : let $f:[0,1] \rightarrow \mathbb{R}$ be a continuous function. Prove that : $$\lim_{n \rightarrow +\infty} \dfrac{1}{\log(n)}\sum_{k=1}^n \dfrac{1}{k}f\left(\...
Toctocguy's user avatar
0 votes
1 answer
28 views

Redundancy in the definition of uniform spaces

Let me paraphrase Wikipedia's definition of uniform spaces: Definition A. A set $X$ endowed with a nonempty collection $\Phi$ of subsets of $X \times X$ is a uniform space if the following conditions ...
Dannyu NDos's user avatar
  • 2,049
0 votes
0 answers
21 views

Uniformly Continuous and locally Lipschitz but not Globally Lipschitz Function on a "Connected but not compact" set

I know such a function exists but I can’t find an example. I have the famous example f:]0,inf[ --->R f(x)=sqrt(x) function. But I can't find any other function which is Uniformly Continuous and ...
máthēma's user avatar
0 votes
1 answer
49 views

Continuity question on compact and connected domain

Let $\Omega$ be an open and bounded connected domain from $\mathbb{R}^N$. Consider a continuous function $f:\overline{\Omega}\to\mathbb{R}$. So $K=\overline{\Omega}$ is compact. My question is: Can we ...
Bogdan's user avatar
  • 1,912
0 votes
1 answer
55 views

Counterexample of function that is hard to find

Is there a continuous function $f:\left [0,\dfrac{1}{2}\right ]\to \mathbb{R}$ for which there is no constant $c>0$ such that: $$|f(x)-f(y)|\leq\dfrac{c}{-\ln(|x-y|)},\ \forall\ x,y\in\left [0,\...
Bogdan's user avatar
  • 1,912
0 votes
2 answers
78 views

If $f'$ is periodic , are $f , f'$ uniformly continuous?

$f: ℝ \rightarrow ℝ $ is such that $f'$ exist and $f'$ is periodic. Are $f ,f'$ uniformly continuous ? Attempt :- I was thinking along a counter example . What if $f'(x)=\tan x$ but then $f(x)=\ln (|...
user-492177's user avatar
  • 2,589
1 vote
0 answers
36 views

Holomorphic and bounded implies uniform continuity

I'm working on the following Qualifying Exam problem: Let $\mathbb{H}$ be the upper half plane, and let $f: \mathbb{H} \to \mathbb{C}$ be holomorphic and bounded. For a given $r> 0$, let $\mathbb{...
sireesh's user avatar
  • 73
0 votes
1 answer
38 views

Relation between uniformly absolutely continuous and absolutely continuous in measure theory

I'm a little confused with these two definitions: Definition of $\textbf{absolutely continuous}$: $\nu$ is said absolutely continuous in respect to $\mu$ if $\mu(E)=0 \Rightarrow \nu(E)=0, \forall E \...
TY FIRE's user avatar
  • 17
2 votes
4 answers
83 views

If $\lim\limits_{x\to +\infty} f(x)=L, (L\in \mathbb{R})$, $f'(x)$ is uniformly continuous on $(0,+\infty),$ then $\lim\limits_{x\to +\infty} f'(x)=0$

If $\lim\limits_{x\to +\infty} f(x)=L, (L\in \mathbb{R})$, $f'(x)$ is uniformly continuous on $(0,+\infty),$ then $\lim\limits_{x\to +\infty} f'(x)=0$. $\textbf{Attempt}$: $\textbf{Claim}$: If $f'(x)$...
Bowei Tang's user avatar
  • 1,541
0 votes
0 answers
33 views

$\mathbb R^n$ version of proof that uniform continuity implies boundedness [duplicate]

I have seen a lot of questions on the site about the proof that if $f$ is uniformly continuous on an interval, then its range is bounded. However, I have not been able to find a question that ...
lightweaver's user avatar
1 vote
1 answer
40 views

Continuity and uniform continuity on products

Let $X,Y,Z$ be metric spaces, and $F:X \times Y \rightarrow Z$ be a continuous function. Further, suppose that for each $x \in X, F_x: Y \rightarrow Z$ is uniformly continuous. Then, is the canonical ...
mathable's user avatar
  • 444
1 vote
1 answer
77 views

Rudin's Construction of Lebesgue Measure 2

I am currently studying Rudin's RCA book and I have a question about Theorem 2.20, where the author constructs Lebesgue measure on $\mathbb{R}^k$. Here are the definitions and the notations I am ...
meh's user avatar
  • 13
2 votes
1 answer
37 views

Prove that if $f$ is continuous, and has two asymptotes, then it is uniformly continuous (Argument check)

The exercise is the following: Let $f:\mathbb{R} \rightarrow \mathbb{R} $ continuous such that $\lim_{x\rightarrow+\infty} f(x) = \ell_1$ and $\lim_{x\rightarrow-\infty} f(x) = \ell_2$ for some ...
Fausto Martinez's user avatar
-2 votes
1 answer
71 views

How can I prove that if $f:[0,+\infty)\to[0,1]$ is continuous and increasing, then it is uniformly continuous? [closed]

The problem is the following: Let $f:[0,+\infty)\rightarrow\mathbb{R}$ such that it is continuous, strictly growing and its image is contained in $[0,1]$, is uniformly continuous. I've tried in ...
Fausto Martinez's user avatar

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