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1 vote
2 answers
184 views

Sum of the product of Permutations

I found a similar problem on one of my problem sets and am struggling with how to approach the problem. The problem is as follows: $$ \text{Evaluate} \sum _{k=1}^{n}\:P(n, k-1)P(n-1,n-k). $$ The ...
Akilan Manivannan's user avatar
3 votes
2 answers
178 views

What is $\underset{\pi \in S_n}{\max}\underset{1\leq i\leq n}{\sum}|i-\pi(i)|$, where $S_n$ is the set of permutations of $(1,2,\ldots,n)$?

What is the value of $$\underset{\pi \in S_n}{\max} \biggl( \underset{1\leq i\leq n}{\sum} \big|i-\pi(i)\big|\biggr)\,,$$ where $S_n$ is the set of permutations of $(1,2,\ldots,n)$? I can see that if ...
Soumyadip Sarkar's user avatar
1 vote
0 answers
80 views

Summing discrete coordinate lengths, a generalized n-dimensional case

A previous question pertains to a formula for the total number of points in a 3d discrete coordinate system that each total number of coordinate digit lengths $l$ can describe. Is it possible to ...
ijaubgiaugf's user avatar
2 votes
1 answer
100 views

Summing discrete 3d coordinate lengths

Consider a three dimensional discrete coordinate system $(x,y,z)$, where $x,y,z\in$ natural numbers. The number of digits describing an integer coordinate for each dimension is $l_c=\lfloor log(c) \...
ijaubgiaugf's user avatar
-1 votes
1 answer
423 views

How to calculate the sum of the total set of numbers from a set of digits (without repetition)?

The question seems fairly complicated but let me break it down: For example, you are to calculate the sum of the possible 4 digit numbers of the digits 1,2,3,4 without repetition. So all the numbers ...
Kingsley Zhong's user avatar
4 votes
1 answer
836 views

How to expand a summation of "n choose k" into a polynomial?

I wish to expand $$\sum\limits_{k = 0}^{i - 1} {n \choose k}$$ where $i \leq n$ into a polynomial. However I am uncertain about the coefficients of each term. I have consulted https://en.wikipedia....
Norman's user avatar
  • 1,156
0 votes
1 answer
746 views

Proof by induction that $\sum$ $n\choose k $ $= 2^n$ [duplicate]

Trying to prove by induction that $\sum^{i=n}_{i = 0}$$n\choose i$$=2^n$ So obviously, I prove for some arbitary number, i.e $n = 2$ I then go on to show what the n = k terms look like for the ...
user36606's user avatar
2 votes
3 answers
288 views

Permutation of integers

Let $n$ be a positive integer and let $(a_1,...,a_n)$ be a permutation of $\{1,2,...,n\}$. Define $$A_k = \{ a_i | a_i < a_k, i >k\} \\ B_k = \{a_i | a_i > a_k, i < k\}$$ for $1 \leq k \...
user avatar
1 vote
2 answers
140 views

Prove summation related to cycles: For $n \geq r $ there is:$ \sum_{k=1}^{n} {b_r(n,k)x^k=(r-1)!\frac{x^\overline{n}}{(x+1)^\overline{r-1}}} $

Let $b_r(n,k)$ be the number of n-permutations with $k$ cycles, in which numbers $1,2,\dots,r$ are in one cycle. Prove that for $n \geq r $ there is: $$ \sum_{k=1}^{n} {b_r(n,k)x^k=(r-1)!\frac{x^\...
syntagma's user avatar
  • 1,013