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8 votes
1 answer
266 views

Surprising fact about a certain number-theoretic function

Ante suggested the following function : For natural number $n$ we can observe the $n$ remainders $b_1,...,b_n$ by writing $n$ as $n=a_k \cdot k+b_k$ for $1 \leq k \leq n$ Because of the familiar ...
Peter's user avatar
  • 85.1k
12 votes
5 answers
301 views

Sums of $5$th and $7$th powers of natural numbers: $\sum\limits_{i=1}^n i^5+i^7=2\left( \sum\limits_{i=1}^ni\right)^4$?

Consider the following: $$(1^5+2^5)+(1^7+2^7)=2(1+2)^4$$ $$(1^5+2^5+3^5)+(1^7+2^7+3^7)=2(1+2+3)^4$$ $$(1^5+2^5+3^5+4^5)+(1^7+2^7+3^7+4^7)=2(1+2+3+4)^4$$ In General is it true for further increase ...
Ekaveera Gouribhatla's user avatar
7 votes
2 answers
1k views

proof - Show that $1! +2! +3!+\cdots+n!$ is a perfect power if and only if $n=3$

Show that $1! +2! +3!+\cdots+n!$ is a perfect power if and only if $n =3$ For $n=3$, $1!+2!+3!=9=3^2$. I also feel that the word 'power' makes it a whole lot hard to prove. How do we prove this? What ...
TheRandomGuy's user avatar
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