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17 votes
7 answers
8k views

Chain rule for discrete/finite calculus

In the context of discrete calculus, or calculus of finite differences, is there a theorem like the chain rule that can express the finite forward difference of a composition $∆(f\circ g)$ in ...
GregRos's user avatar
  • 1,787
11 votes
9 answers
6k views

How to compute the formula $\sum \limits_{r=1}^d r \cdot 2^r$?

Given $$1\cdot 2^1 + 2\cdot 2^2 + 3\cdot 2^3 + 4\cdot 2^4 + \cdots + d \cdot 2^d = \sum_{r=1}^d r \cdot 2^r,$$ how can we infer to the following solution? $$2 (d-1) \cdot 2^d + 2. $$ Thank you
q0987's user avatar
  • 223
8 votes
1 answer
251 views

Changing Variables in Discrete Calculus

In discrete calculus one soon meets the $h$-difference operator $$\Delta_h[f(x)] = f(x+h) - f(x)$$ and we often define $\Delta = \Delta_1.$ We can similarly define the indefinite sums $\Delta_h^{-1}$ ...
KJL's user avatar
  • 153
5 votes
1 answer
58 views

How to evaluate $\sum\limits_{n \geq 0} \left(S_{n + 2} + S_{n + 1}\right)^2(-1)^n$, given the multivariable recurrence relation?

The given multivariable recurrence relation is that for every $n \geq 1$ $$S_{n + 1} = T_n - S_n$$ where $S_1 = \dfrac{3}{5}$ and $T_1 = 1$. Both $T_n$ and $S_n$ depend on the following condition $$ \...
NasuSama's user avatar
  • 3,364
4 votes
1 answer
690 views

Formula for nth derivative of partial sum of geometric series.

I am trying to find a formula for either (1) the $n$th derivative for the following $m$th partial sum: $$\frac{d^n}{dx^n} \sum_{i=0}^m x^i$$ or (2) the $n$th derivative of the infinite series given by ...
RyRy the Fly Guy's user avatar
3 votes
3 answers
138 views

Infinite Sum with Combinatoric Expression

Calculate the value of the infinite sum, where $0<p<1$ and $r,n\in\mathbb{Z}_{\ge1}$: $$\sum_{y=1}^\infty \binom{r+y-1}{y}y^n(1-p)^y$$ Just for context, this is the $n^{th}$ moment of the ...
EllipticalInitial's user avatar
3 votes
5 answers
5k views

Deriving the summation formula for $x^2, x^3,\ldots,x^n$

How is the summation formula's for $x,x^2,x^3,x^4,\ldots$ derived? I know how to do it for $x$ which is $n^2/2 + n/2$ but I am having hard time deriving the summation formula for $x^n$ on my own. I ...
Eames Cobb's user avatar
2 votes
1 answer
106 views

Function satisfying $f(z) = 1 + z f\left(\frac{z}{1+z}\right)$

Iterate the following equation to obtain an explicit formula for $f( z)$: $$ \begin{align*} f( z) = 1 + z f\left( \frac{z}{1 + z}\right) .\end{align*} $$ Iterating this equation one obtains $$ \begin{...
Richard's user avatar
  • 575
2 votes
3 answers
118 views

Sum with two indices, how to handle the condition $i\neq j$?

I'm given $$ \sum_{i,j=1, i \neq j}^{N} ij \tag 1 $$ I assume this is a short hand for $$ \sum_{i=1}^{N} \Bigg ( \sum_{j=1}^{N} ij \Bigg ) \qquad? \tag 2 $$ But where does $i\neq j$ belong, to the ...
JDoeDoe's user avatar
  • 2,362
2 votes
1 answer
73 views

Integration of 1 to n...

Anybody can explain how, summation of $1$ to $N$, can be replaced with integration and result leads to $(1/2)N^2$: $$ \sum_{i=1}^N i \sim \int_1^N x \ \mathrm{d}x \sim \frac{1}{2}N^2 $$ Note: Image ...
user252514's user avatar
2 votes
2 answers
178 views

Evaluate the Finite Sum with Binomial Coefficient [duplicate]

Evaluate the following sum: $$\sum_{k=0}^n\binom{n}{k}\frac{k}{n}x^k(1-x)^{n-k}$$ This almost looks like the Binomial Theorem, except there's that pesky little $\frac{k}{n}$ term in there that ...
EllipticalInitial's user avatar
1 vote
4 answers
957 views

Summation of n-squared, cubed, etc. [duplicate]

How do you in general derive a formula for summation of n-squared, n-cubed, etc...? Clear explanation with reference would be great.
user67527's user avatar
  • 493
1 vote
3 answers
418 views

$T(n)=2T(n-1)+n,T(1)=1,n\ge2$ [duplicate]

Solve the recurrence $T(n)=2T(n-1)+n,T(1)=1,n\ge2$ My approach: $$T(n)=2T(n-1)+n$$ $$T(n)=2(2T(n-2)+(n-1))+n$$ $$T(n)=4T(n-2)+2(n-1)+n\dots$$ $$T(n)=2^kT(n-k)+2^{k-1}(n-k+1)+\dots+2^{k-k}n$$ From ...
laura's user avatar
  • 2,540
1 vote
1 answer
38 views

Prove Value of Summation with Combinatoric

Prove that: $$\sum_{k=0}^n\binom{n}{k}\left(\frac{k}{n}\right)^2x^k(1-x)^{n-k}=\frac{x(1+x(n-1))}{n}$$ I've managed to simplify the sum up until this point: $$\frac{\sum_{k=1}^n\binom{n-1}{k-1}kx^k(...
EllipticalInitial's user avatar
1 vote
1 answer
1k views

Find generating function for the sequence 0, 0, 0, 0, 3, 4, 5, 6, ...

1.Derive the generating function for the sequence $$0, 0, 0, 0, 3, 4, 5, 6, . . .$$ 2.Derive the generating function for the sequence $$0, 0, −12, 36, −108, 324, .. .$$ So the first function ...
Rui Yu's user avatar
  • 33

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